Explanation Given data: The induced emf across the light bulb is 1.5 V . The number of turns in the coil are 100 . The area of the coil is 3.0 × 10 − 4 m 2 . The magnetic field at the bar magnet’s north pole is 0.040 T . The distance between the coil and the north pole when the magnetic field is zero is 4 cm . Formula used: According to Lenz’s law, the expression for the change in the magnetic field is given as: | Δ B Δ t | = ε i n N A Here, Δ B is the change in the magnetic field, Δ t is the change in time, ε is the induced emf, N is the number of turns, and A is the area of the coil. Write the expression for the area of the circular loop. A = π r 2 Here, r is the radius of the loop and A is the area of a circle. The expression for the speed of the object is given as: v = d t Here, d is the distance traveled by the object in the time interval t . The conversion formula to convert centimeter to meter is given as: 1 cm = 10 − 2 m Explanation: Recall the expression for Lenz’s law. | Δ B Δ t | = ε i n N A Substitute 1.5 V for ε i n , 100 for N , and 3.0 × 10 − 4 m 2 for A . | Δ B Δ t | = 1

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Author: Eugenia Etkina, Gorazd Planinsic

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Electromagnets

The word "electromagnet" is composed of two words, ‘electro’ and ‘magnet’. It is a type of magnet in which an electric current helps in the generation of a magnetic field. Electromagnets usually consist of two major parts, wire and a coil around which th…

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Chapter 21, Problem 21P

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Whether the bulb can be lightened or not, by electromagnetic induction if it requires 1.5 V potential difference across it to glow, with the help of a small bar magnet having 0.040 T magnetic field at the front of its north pole and 0 T at 4 cm away from the pole, and a 3.0×10−4 m2 coil with 100 turns.

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Chapter 21, Problem 20P

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Pearson eText for College Physics: Explore and Apply -- Instant Access (Pearson+)

Ch. 21 - Review Question 21.1 Your friend thinks that...Ch. 21 - Review Question 21.2 You have a bar magnet and a...Ch. 21 - Review Question 21.3 What difficulty would occur...Ch. 21 - Review Question 21.4 Why do we write the law of...Ch. 21 - Review Question 21.5 How does the law of...Ch. 21 - Review Question 21.6 A capacitor in an electric...Ch. 21 - Prob. 7RQ Ch. 21 - Review Question 21.8 Explain how (a) an electric...Ch. 21 - 1. In which of the experiments with a loop and a...Ch. 21 - If you move the coil in Figure Q21.2 toward the N...

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Solution Summary: The author explains how the light bulb can be lightened by electromagnetic induction if it requires 1.5 V potential difference across it to glow, with the help of a small bar magnet having 0.040 T magnetic field at the front of

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