
Interpretation:
The influence of over voltage on the products in
Concept Introduction:
Oxidation: The gain of oxygen or the loss of hydrogen or the loss of an electron in a species during a
Reduction: The loss of oxygen or the gain of hydrogen or the gain of an electron in a species during a redox reaction is called as reduction.
Oxidizing agent: The substance that is oxidized is called as a reducing agent.
Reducing agent: The substance that is reduced is called as an oxidizing agent.
Oxidation half-reaction: An oxidation half-reaction is a part of redox reaction that shows only for the oxidized species with electrons and its oxidation state increases with the loss of electrons.
Reduction half-reaction: A reduction half-reaction is a part of redox reaction (counterpart of oxidation half-reaction) that shows only for the reduced species with electrons and its oxidation state decreases with the gain of electrons.
Anode: The electrode where the oxidation occurs is called as an anode. It is a negatively charged electrode.
Cathode: The electrode where reduction occurs is called as a cathode. It is a positively charged electrode.
Ecell-the potential difference between anode and cathode in cell is determined as cell potential.
Eocell-the cell potential measured at specified temperature conditions which is used to compare the potentials of different cells since, the Ecell is affected by concentration changes as reaction proceeds and due to energy loss from heating of the cell and external circuit.

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Chapter 21 Solutions
CHEMISTRY:MOLECULAR...(LL)-W/CONNECT
- Tartaric acid (C4H6O6) is a diprotic weak acid. A sample of 875 mg tartaric acid are dissolved in 100 mL water and titrated with 0.994 M NaOH. How many mL of NaOH are needed to reach the first equivalence point? How many mL of NaOH are needed to reach the second equivalence point?arrow_forwardIncluding activity, calculate the solubility of Pb(IO3)2 in a matrix of 0.020 M Mg(NO3)2.arrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M KBr.arrow_forward
- Including activity, calculate the pH of a 0.010 M HCl solution with an ionic strength of 0.10 M.arrow_forwardCan I please get the graph 1: Concentration vs. Density?arrow_forwardOrder the following series of compounds from highest to lowest reactivity to electrophilic aromatic substitution, explaining your answer: 2-nitrophenol, p-Toluidine, N-(4-methylphenyl)acetamide, 4-methylbenzonitrile, 4-(trifluoromethyl)benzonitrile.arrow_forward
- Ordene la siguiente serie de compuestos de mayor a menor reactividad a la sustitución aromática electrofílica, explicando su respuesta: ácido bencenosulfónico, fluorobenceno, etilbenceno, clorobenceno, terc-butilbenceno, acetofenona.arrow_forwardCan I please get all final concentrations please!arrow_forwardState the detailed mechanism of the reaction of benzene with isopropanol in sulfuric acid.arrow_forward
- Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction. For the decomposition reaction of N2O5(g): 2 N2O5(g) · 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 -> NO2 + NO3_(K1) NO2 + NO3 →> N2O5 (k-1) → NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Give the expression for the acceptable rate. (A). d[N₂O] dt = -1 2k,k₂[N205] k₁+k₂ d[N₂O5] (B). dt =-k₁[N₂O₂] + k₁[NO2][NO3] - k₂[NO2]³ (C). d[N₂O] dt =-k₁[N₂O] + k₁[N205] - K3 [NO] [N205] (D). d[N2O5] =-k₁[NO] - K3[NO] [N₂05] dtarrow_forwardA 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardFor the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forward
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