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Interpretation:
From the given metals, the metals suitable as sacrificial anodes to protect the iron pipes have to be identified with explanation.
Concept Introduction:
Oxidation: The gain of oxygen or the loss of hydrogen or the loss of an electron in a species during a
Reduction: The loss of oxygen or the gain of hydrogen or the gain of an electron in a species during a redox reaction is called as reduction.
Oxidizing agent: The substance that is oxidized is called as a reducing agent.
Reducing agent: The substance that is reduced is called as an oxidizing agent.
Oxidation half-reaction: An oxidation half-reaction is a part of redox reaction that shows only for the oxidized species with electrons and its oxidation state increases with the loss of electrons.
Reduction half-reaction: A reduction half-reaction is a part of redox reaction (counterpart of oxidation half-reaction) that shows only for the reduced species with electrons and its oxidation state decreases with the gain of electrons.
Anode: The electrode where the oxidation occurs is called as an anode. It is a negatively charged electrode.
Cathode: The electrode where reduction occurs is called as a cathode. It is a positively charged electrode.
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Chapter 21 Solutions
CHEMISTRY:MOLECULAR...(LL)-W/CONNECT
- Predict the major organic product(s), if any, of the following reactions. Assume all reagents are in excess unless otherwise indicated.arrow_forwardHow many signals would you expect to find in the 1 H NMR spectrum of each given compound? Part 1 of 2 2 Part 2 of 2 HO 5 ☑ Х IIIIII***** §arrow_forwardA carbonyl compound has a molecular ion with a m/z of 86. The mass spectra of this compound also has a base peak with a m/z of 57. Draw the correct structure of this molecule. Drawingarrow_forward
- Can you draw this using Lewis dot structures and full structures in the same way they are so that I can better visualize them and then determine resonance?arrow_forwardSynthesize the following compound from cyclohexanol, ethanol, and any other needed reagentsarrow_forwardFor a titration of 20.00 mL of 0.0500 M H2SO4 with 0.100 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin; 2) 10.00 mL; 3) 20.00 mL; 4) 30.00 mL. Ka2 = 1.20×10-2 for H2SO4.arrow_forward
- Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s) Be sure to account for all bond-breaking and bond-making steps Problem 73 of 10 Drawing Amows ro HO Donearrow_forward12. Synthesize the following target molecules (TMs) using the specified starting materials. .CI a) HO3S SM TM b) HO- SMarrow_forwardFor a titration of 20.00 mL of 0.0500 M H2SO4 with 0.100 M KOH, calculate the pH at each of the following volume of KOH used in the titration: 1) before the titration begin; 2) 10.00 mL; 3) 20.00 mL; 4) 30.00 mL. Ka2 = 1.20×10-2 for H2SO4.arrow_forward
- Write the systematic name of each organic molecule: structure name show work. don't give Ai generated solutionarrow_forwardShow work with explanation needed. Don't give Ai generated solutionarrow_forwardA Elschboard Part of SpeechT-D Alt Leaming App app.aktiv.com Curved arrows are used to illustrate the flow of electrons. Using the provided resonance structures, draw the curved electron- pushing arrows to show the interconversion between resonance hybrid contributors. Be sure to account for all bond-breaking and bond-making steps. Include all lone pairs and formal charges in the structures. Problem 45 of 10 I Select to Add Arrows N Please selarrow_forward
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