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(a)
Interpretation:
The mechanism and the structure of the product of the nucleophilic addition-elimination reaction between pyridine and an acid chloride are to be drawn.
Concept introduction:
Pyridine is a moderately strong nucleophile as the lone pair of the nitrogen atom is not involved in resonance (and
(b)
Interpretation:
Why the reaction involving pyridine does not interfere with the production of the desired amide product of the given reaction is to be explained.
Concept introduction:
Pyridine is a moderately strong nucleophile as the lone pair of the nitrogen atom is not involved in resonance (and aromaticity). When it is used as a solvent in a nucleophilic addition-elimination reaction, it can compete with the reagent, adding to the carbonyl carbon of the substrate. The product of the reaction has a positive charge on the nitrogen of the pyridine group and, therefore, is reactive toward nucleophilic addition-substitution reaction.
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Chapter 21 Solutions
Get Ready for Organic Chemistry
- Which one of the following functional groups is not present in thecompound shownA. amine; B. aldehyde, C. ether; D. amide. E. ketonearrow_forwardWhich of the following formulas correspond to at least one compound inwhich resonance is important?w. C2H5N x. C3H5Br; y. C3H4; z. C4H6.A. w, x, y; B. x, y, z; C. w, x, z; D. w, y, z; E. all of themarrow_forwardPredict the product(s) that are formed after each step for reactions 1-4. In each case, consider formation of any chiral center(s) and draw all expected stereoisomers. 1) OH 1) HBr (SN2) 2) NaOH, heat 3) BH3, THF 4) H2O2, NaOH 2) OH 1) SOCI 2, py 2) NaOEt 3) Br2, H₂O 3) OH 1) H2SO4 conc. 2) HBr, ROOR 3) KOtBu 4) OH 1) TsCl, py 2) NaOEt 3) 03 4) DMSarrow_forward
- Which of the following rings has the least strain in its most stableconformation?A. Cyclobutane; B. Cyclopentane; C. Cyclohexane; D. Cycloheptane;E. Cyclooctanearrow_forwardThe number of different carbon skeletons that have a main chain of 9carbons and an ethyl branch isA 3; B. 4; C. 5; D. 6; E. 7arrow_forwardQ5: Classify the following pair of molecules as constitutional isomers, enantiomers, diastereomers, the same molecule, or completely different molecules. Br O CI Br OH OH 111 Br .!!!/Br F OH and ...m Br Br OH CI Br OH ་་་་་" ། ་arrow_forward
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