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Concept explainers
Interpretation: For the given set of molecules, the Lewis structure should be determined.
Concept Introduction:
Molecular geometry: It is defined as unique three dimensional arrangements of atoms around the central metal present in the molecule which is determined by using spectroscopic techniques and also by using Lewis structure or the valence shell electron pair repulsion theory (VSEPR).
Lewis structure for any molecule is drawn by using the following steps,
First the skeletal structure for the given molecule is drawn then the total number of valence electrons for all atoms present in the molecule is determined
The next step is to subtract the electrons present in the total number of bonds present in the skeletal structure of the molecule with the total valence electrons such that considering each bond contains two electrons with it.
Finally, the electrons which got after subtractions have to be equally distributed such that each atom contains eight electrons in its valence shell.
VSEPR Theory:
As the name itself indicates that the basis for this theory is the electron pair that is bonded electron present in either single or double bonds or lone pair electrons, present in the valence shell tends to repel each other which then the tends to be in position in order to minimize the repulsions.
Electron Domain: In VSEPR theory, both the lone pair and the bonded pair are together considered as electron domain regardless of the type of bond in which the bonded pair presents.
To draw: The Lewis structure for the given molecules.
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Chapter 21 Solutions
EBK CHEMISTRY: ATOMS FIRST
- Classify each pair of molecules according to whether or not they can participate in hydrogen bonding with one another. Participate in hydrogen bonding CH3COCH3 and CH3COCH2CH3 H2O and (CH3CH2)2CO CH3COCH3 and CH₂ CHO Answer Bank Do not participate in hydrogen bonding CH3CH2OH and HCHO CH3COCH2CH3 and CH3OHarrow_forwardNonearrow_forwardQ4: Comparing (3S,4S)-3,4-dimethylhexane and (3R,4S)-3,4-dimethylhexane, which one is optically active? Briefly explain.arrow_forward
- Nonearrow_forwardNonearrow_forwardGiven the standard enthalpies of formation for the following substances, determine the reaction enthalpy for the following reaction. 4A (g) + 2B (g) → 2C (g) + 7D (g) AHrxn =?kJ Substance AH in kJ/mol A (g) - 20.42 B (g) + 32.18 C (g) - 72.51 D (g) - 17.87arrow_forward
- Determine ASran for Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(aq) given the following information: Standard Entropy Values of Various Substance Substance So (J/mol • K) 60.9 Zn(s) HCl(aq) 56.5 130.58 H2(g) Zn2+(aq) -106.5 55.10 CI (aq)arrow_forward3) Catalytic hydrogenation of the compound below produced the expected product. However, a byproduct with molecular formula C10H12O is also formed in small quantities. What is the by product?arrow_forwardWhat is the ΔHorxn of the reaction? NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq) ΔHorxn 1= ________ kJ/molarrow_forward
- = +92kJ ΔΗ = +170kJ Use the following reactions: 2NH3(9) N2(g) + 3H2(g) → 11/N2(g) + 2H2O (1) → NO2(g) + 2H2(g) Determine the DH° of this reaction: NO2(g) + H2(g) → 2(g) → 2H2O(l) + NH3(9) ΔΗarrow_forwardDetermine the entropy change for the reaction SO2(g) + O2(g) following information: Standard Entropy Values of Various Substance Substance SO2(g) 02(g) SO3(g) So (J/mol K) 248.2 205.0 256.8 → SO3(g) given thearrow_forwardIndicate which one of the following reactions most certainly results in a negative AS sys. O1402(g) + 3NH4NO3 (s) + C10 H22(1) → 3N2(g) + 17H2O(g) + 10CO2(g) ○ CO2(aq) = CO2(g) ○ H₂O(g) = H₂O(s) CaCO3(g) = CaO(s) + CO2(g) O CuSO4.5H2O(s) = CuSO4(s) + 5H2O(g)arrow_forward
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