Applied Physics (11th Edition)
11th Edition
ISBN: 9780134159386
Author: Dale Ewen, Neill Schurter, Erik Gundersen
Publisher: PEARSON
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Chapter 21, Problem 1RP
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A convex spherical mirror has a radius of curvature of 71.36 cm. If a candle that is 3.12 cm high is then placed 28 cm in front of the
mirror, what is the height of the image formed in cm?
Round your answer to 2 decimal places.
You have a concave spherical mirror (the same holds if you had a convex mirror) If the value of q (the distance from the image to the mirror along the principal axis of the mirror) is 1.32m and the distance of p (the distance from the object to the mirror along
the principal axis of the mirror) is 3.38m, what is the focal length of the mirror?
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Q
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The magnification equation and the sign convention for q imply that real images of real objects are always inverted (if both p and q are positive, m is negative); virtual images of real objects are always upright (if p is positive and q is negative, m is positive). Keeping
the signs of p and q straight in your mind is the most challenging aspect of mirrors (and lenses). Fortunately, table 23.2 summarizes when p and q are positive and when they are negative.
Note: Do not explicitly include units in your answer (it is understood the unit is meter). Enter only a number. If you do enter a unit, your answer will be counted wrong.
Chapter 21 Solutions
Applied Physics (11th Edition)
Ch. 21.5 - Given so = 1.65 cm and st = 6.00 cm, find f.Ch. 21.5 - Given f = 15.0 cm and st = 3.00 cm, find so.Ch. 21.5 - Given st = 14.5 cm and f = 10.0 cm, find so.Ch. 21.5 - Given st = - 10.0 cm and f = - 5.00 cm, find so.Ch. 21.5 - Given so = 7.35 cm and st = 17.0 cm, find f.Ch. 21.5 - Given ht = 2.75 cm, ho = 4.50 cm, and st = 6.00...Ch. 21.5 - Given ho = 12.0 cm, st = 13.0 cm, and so = 25.0...Ch. 21.5 - Given ht = 3.50 cm. hs = 2.50 cm, and st = 15.5...Ch. 21.5 - If an object is 2.50 m tall and 8.60 m from a...Ch. 21.5 - An object 30.0 cm tall is located 10.5 cm from a...
Ch. 21.5 - Prob. 11PCh. 21.5 - An object 12 6 cm in front of a convex mirror...Ch. 21.5 - What is the height of an image in a truck mirror...Ch. 21.5 - A lift truck has a rear view mirror that is 0.76 m...Ch. 21.5 - Find the focal length of a convex mirror that...Ch. 21.5 - Find the focal length of a mirror that forms an...Ch. 21.5 - Find the focal length of a mirror that forms an...Ch. 21.5 - An image of a statue appears to be 11.5 cm behind...Ch. 21.5 - (a) What is the height of a figurine 7.33 cm in...Ch. 21.10 - Find the index of refraction of a medium for which...Ch. 21.10 - Prob. 2PCh. 21.10 - If the index of refraction of a liquid is 1.50,...Ch. 21.10 - The angle of incidence of light passing from air...Ch. 21.10 - If the critical angle of a liquid is 42.4, find...Ch. 21.10 - If the index of refraction of a substance is 2.45,...Ch. 21.10 - A converging lens has a focal length of 15.0 cm....Ch. 21.10 - An object 2.50 cm tall is placed 20.0 cm from a...Ch. 21.10 - The focal length of a lens is 5.00 cm. How far...Ch. 21.10 - If the distance from the lens in your eye to the...Ch. 21.10 - An object 5.00 cm tall is placed 15.0 cm from a...Ch. 21.10 - An object 4.50 cm tall is placed 18.0 cm from a...Ch. 21.10 - What are the size and location of an image...Ch. 21.10 - What are the size and location of an image...Ch. 21.10 - What is the focal length of a convex lens that...Ch. 21 - Stained glass is an example of a. a transparent...Ch. 21 - A virtual image may be a. larger than the object....Ch. 21 - A real image may be a. erect. b. shown on a...Ch. 21 - Explain the difference between diffusion and...Ch. 21 - Prob. 5RQCh. 21 - Prob. 6RQCh. 21 - Describe the type of images formed by plane...Ch. 21 - Explain the difference between real and virtual...Ch. 21 - Explain the difference between a concave and a...Ch. 21 - Explain the effect of spherical aberration.Ch. 21 - For a mirror of given focal length, how does the...Ch. 21 - For a given object distance from a mirror, how...Ch. 21 - The index of refraction depends on a. the focal...Ch. 21 - Snell's law involves a. the lens equation. b. the...Ch. 21 - Prob. 15RQCh. 21 - Give several examples of total internal...Ch. 21 - Prob. 17RQCh. 21 - Prob. 18RQCh. 21 - Prob. 19RQCh. 21 - What types of images are formed by diverging...Ch. 21 - What types of images are formed by converging...Ch. 21 - How do water waves affect the escape of light from...Ch. 21 - Explain why a fish under water appears to be at a...Ch. 21 - Does light always travel in a straight line?...Ch. 21 - Explain how total internal reflection allows light...Ch. 21 - Under what conditions will a converging lens form...Ch. 21 - Under what conditions will a converging lens form...Ch. 21 - Under what conditions will a diverging lens form a...Ch. 21 - Using 1f=1s0+1si, s0 = 3.50 cm, and si = 7.25 cm,...Ch. 21 - Using 1f=1s0+1si, s0 = 8.50 cm, and f = 25.0 cm,...Ch. 21 - Using M=hih0=sis0, h0 = 6.50 cm, si = 7.50 cm, and...Ch. 21 - If an object is 3.75 m tall and 7.35 m from a...Ch. 21 - An object 43.0 cm tall is located 23.4 cm from a...Ch. 21 - Prob. 6RPCh. 21 - The angle of incidence of light passing from air...Ch. 21 - If the index of refraction of a liquid is 1.44,...Ch. 21 - If the critical angle of a liquid is 45.6, find...Ch. 21 - If the index of refraction of a substance is 1.50,...Ch. 21 - A converging lens has a focal length of 12.0 cm....Ch. 21 - An object 4.50 cm tall is placed 20.0 cm from a...Ch. 21 - The focal length of a lens is 4.00 cm. How far...Ch. 21 - What is the focal length of a convex lens that...Ch. 21 - What is the focal length of a mirror that forms an...Ch. 21 - What are the size and location of an image...Ch. 21 - What is the speed of light passing through a...Ch. 21 - Prob. 18RPCh. 21 - Find the focal length of a concave mirror with an...Ch. 21 - Prob. 20RPCh. 21 - Tamera uses a concave mirror when applying makeup....Ch. 21 - A convex security mirror has a radius of curvature...Ch. 21 - Prob. 3ACCh. 21 - Diamonds are cut to take advantage of internal...Ch. 21 - A photographer uses a 60.0-mm lens. (a) How far...
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- 14arrow_forwardYou have a concave spherical mirror (the same holds if you had a convex mirror) If the value of q (the distance from the image to the mirror along the principal axis of the mirror) is 1.86m and the distance of p (the distance from the object to the mirror along the principal axis of the mirror) is 3.7m, what is the focal length of the mirror? P h AI C | I B h' Q | k V 9 Р The magnification equation and the sign convention for q imply that real images of real objects are always inverted (if both p and q are positive, m is negative); virtual images of real objects are always upright (if p is positive and q is negative, m is positive). Keeping the signs of p and q straight in your mind is the most challenging aspect of mirrors (and lenses). Fortunately, table 23.2 summarizes when p and q are positive and when they are negative.arrow_forwardQuestion in image.arrow_forward
- Some telephoto cameras use a mirror rather than a lens to magnify distant objects. What radius of curvature R, in meters, does the mirror need to have to replace a 550 mm focal length telephoto lens?arrow_forwardFind the angle between the following 3D vectors: 8.46 3.11 7.25' 9.36 15.5 1.24' Angle Between Two Vectors and — 1.35 9.91 12.6 1.35' 10.2" 3.20arrow_forwardThat's how I thought I would solve it, but unfortanetely the answer is not correct. The answer is 0.0 cm and 7.5 cm. Any idea as why that could be?arrow_forward
- Can you solve this with solutions and explain how did you get it. The answer should be "5.79mm or 5.79×10^-3 thank youarrow_forwardYou have a concave spherical mirror (the same holds if you had a convex mirror) If the value of q (the distance from the image to the mirror along the principal axis of the mirror) is 1.86m and the distance of p (the distance from the object to the mirror along the principal axis of the mirror) is 3.7m, what is the focal length of the mirror? P h A C B h' Q I k 9 P 1 The magnification equation and the sign convention for q imply that real images of real objects are always inverted (if both p and q are positive, m is negative); virtual images of real objects are always upright (if p is positive and q is negative, m is positive). Keeping the signs of p and q straight in your mind is the most challenging aspect of mirrors (and lenses). Fortunately, table 23.2 summarizes when p and q are positive and when they are negative.arrow_forwardFind the value of F2 in the figure. ( l1= 95 cm l2=50 cm l3=95 cm l4=50cm d1=50 cm d2=110 cm F1=65kN)arrow_forward
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