The directional field of the differential equation t y ′ + ( t + 1 ) y = 2 t e − t , y ( 1 ) = a , t > 0 and interpret its behavior.

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Answer 1

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Chapter 2.1, Problem 15P

(a)

To determine

To sketch: The directional field of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and interpret its behavior.

(b)

To determine

To solve: The initial value differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and find the critical value a0.

(c)

To determine

The behavior of the solution of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 corresponding to the initial value a0.

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>tt 1:32 > trend.1m 1m (sales > summary(trend.1m) - tt) #3###23 (i) #### Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 2107.220 57.997 36.332e-16 *** tt -43.500 3.067 -14.18 7.72e-15 *** > trend = ts (fitted (trend.1m), start-start (sales), freq-frequency (sales)) sales trend ###23%23 (ii) #### as.numeric((1:32 %% 4) > X > q1 > q2 > q3 > 94 = = = = - as.numeric((1:32 %% 4) as.numeric((1:32 %% 4) as.numeric((1:32 %% 4) == 1) 2) == == 3) == 0) > season.lm = 1m (resid (trend.1m) 0+q1 + q2 + q3 + q4) #3##23%23 (iii) #### > summary(season.1m) Coefficients: Estimate Std. Error t value Pr(>|t|) q1 -38.41 43.27 -0.888 0.38232 92 18.80 43.27 0.435 0.66719 q3 -134.78 43.27 -3.115 0.00422 ** 94 154.38 43.27 3.568 0.00132 ** > season = ts (fitted (season.lm), start=start (sales), freq=frequency (sales)) > Y X season %23%23%23%23 (iv) #### >ar (Y, aic=FALSE, order.max=1) #23%23%23%23 (v) #### Coefficients: 1 0.5704 Order selected 1 sigma 2 estimated as 9431 > ar(Y, aic=FALSE,…

Please sketch questions 1, 2 and 6

QUESTION 18 - 1 POINT Jessie is playing a dice game and bets $9 on her first roll. If a 10, 7, or 4 is rolled, she wins $9. This happens with a probability of . If an 8 or 2 is rolled, she loses her $9. This has a probability of J. If any other number is rolled, she does not win or lose, and the game continues. Find the expected value for Jessie on her first roll. Round to the nearest cent if necessary. Do not round until the final calculation. Provide your answer below:

Answer 2

Question

Chapter 2.1, Problem 15P

(a)

To determine

To sketch: The directional field of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and interpret its behavior.

(b)

To determine

To solve: The initial value differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and find the critical value a0.

(c)

To determine

The behavior of the solution of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 corresponding to the initial value a0.

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Answer 3

Question

Chapter 2.1, Problem 15P

(a)

To determine

To sketch: The directional field of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and interpret its behavior.

(b)

To determine

To solve: The initial value differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and find the critical value a0.

(c)

To determine

The behavior of the solution of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 corresponding to the initial value a0.

Expert Solution & Answer

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Answer 4

Question

Chapter 2.1, Problem 15P

(a)

To determine

To sketch: The directional field of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and interpret its behavior.

(b)

To determine

To solve: The initial value differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and find the critical value a0.

(c)

To determine

The behavior of the solution of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 corresponding to the initial value a0.

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Answer 5

Chapter 2.1, Problem 15P

(a)

To determine

To sketch: The directional field of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and interpret its behavior.

(b)

To determine

To solve: The initial value differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and find the critical value a0.

(c)

To determine

The behavior of the solution of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 corresponding to the initial value a0.

Answer 6

Chapter 2.1, Problem 15P

(a)

To determine

To sketch: The directional field of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and interpret its behavior.

Answer 7

Chapter 2.1, Problem 15P

(a)

To determine

To sketch: The directional field of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and interpret its behavior.

Answer 8

(b)

To determine

To solve: The initial value differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and find the critical value a0.

Answer 9

(b)

To determine

To solve: The initial value differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and find the critical value a0.

Answer 10

(c)

To determine

The behavior of the solution of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 corresponding to the initial value a0.

Answer 11

(c)

To determine

The behavior of the solution of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 corresponding to the initial value a0.

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 2.1 - Prob. 1P Ch. 2.1 - Prob. 2P Ch. 2.1 - Prob. 3P Ch. 2.1 - Prob. 4P Ch. 2.1 - Prob. 5P Ch. 2.1 - Prob. 6P Ch. 2.1 - Prob. 7P Ch. 2.1 - Prob. 8P Ch. 2.1 - Prob. 9P Ch. 2.1 - Prob. 10P

The directional field of the differential equation t y ′ + ( t + 1 ) y = 2 t e − t , y ( 1 ) = a , t &gt; 0 and interpret its behavior.

To sketch: The directional field of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and interpret its behavior.

To solve: The initial value differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 and find the critical value a0.

The behavior of the solution of the differential equation ty′+(t+1)y=2te−t, y(1)=a, t>0 corresponding to the initial value a0.

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Chapter 2 Solutions

The directional field of the differential equation t y ′ + ( t + 1 ) y = 2 t e − t , y ( 1 ) = a , t > 0 and interpret its behavior.