To calculate the average O − F bond enthalpy in OF 2 molecule. Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in a gaseous state) to give the separate atoms in a gaseous state. The bond dissociation energy is the energy of a single bond while bond energy is the average of the all bond dissociation energies. For the diatomic molecule bond dissociation energy is equal to the bond energy of the molecule. The change of enthalpy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard enthalpy of formation. The standard enthalpy of formation ( Δ f H ∘ ) in terms of standard bond dissociation enthalpy ( B ∘ ) is written as, Δ f H ∘ = ∑ B ∘ products − ∑ B ∘ reactants (1)
To calculate the average O − F bond enthalpy in OF 2 molecule. Concept introduction: The bond dissociation energy is the energy required to break one mole of the gas (in a gaseous state) to give the separate atoms in a gaseous state. The bond dissociation energy is the energy of a single bond while bond energy is the average of the all bond dissociation energies. For the diatomic molecule bond dissociation energy is equal to the bond energy of the molecule. The change of enthalpy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard enthalpy of formation. The standard enthalpy of formation ( Δ f H ∘ ) in terms of standard bond dissociation enthalpy ( B ∘ ) is written as, Δ f H ∘ = ∑ B ∘ products − ∑ B ∘ reactants (1)
Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.
Chapter 21, Problem 101GQ
Interpretation Introduction
Interpretation:
To calculate the average O−F bond enthalpy in OF2 molecule.
Concept introduction:
The bond dissociation energy is the energy required to break one mole of the gas (in a gaseous state) to give the separate atoms in a gaseous state. The bond dissociation energy is the energy of a single bond while bond energy is the average of the all bond dissociation energies. For the diatomic molecule bond dissociation energy is equal to the bond energy of the molecule.
The change of enthalpy to form one mole of a substance from its constituent elements when all the substances in the standard form is known as standard enthalpy of formation.
The standard enthalpy of formation (ΔfH∘) in terms of standard bond dissociation enthalpy (B∘) is written as,
Laser. Indicate the relationship between metastable state and stimulated emission.
The table includes macrostates characterized by 4 energy levels (&) that are
equally spaced but with different degrees of occupation.
a) Calculate the energy of all the macrostates (in joules). See if they all have
the same energy and number of particles.
b) Calculate the macrostate that is most likely to exist. For this macrostate,
show that the population of the levels is consistent with the Boltzmann
distribution.
macrostate 1 macrostate 2 macrostate 3
ε/k (K) Populations
Populations
Populations
300
5
3
4
200
7
9
8
100
15
17
16
0
33
31
32
DATO: k = 1,38×10-23 J K-1
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell