ORGANIC CHEMISTRY-EBOOK>I<
ORGANIC CHEMISTRY-EBOOK>I<
9th Edition
ISBN: 9781305084414
Author: McMurry
Publisher: INTER CENG
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Chapter 20.SE, Problem 23MP
Interpretation Introduction

a)

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  1

Interpretation:

The products of the reaction along with the mechanism of the reaction are to be given.

Concept introduction:

The base catalyzed nitrile hydrolysis into an amide which is then further hydrolyzed to a carboxylate anion and ammonia takes place through the following steps. i) Nucleophilic attack of the hydroxide ion to the cyanide triple bond to yield an imideanion. ii)Protonation of the imine anion by water to yield a hydroxylamine.iii) Tautomerization of the hydroxylimine to an amide iv) Hydrolysis of the amide to carboxylate anion and ammonia.

To give:

The products of the reaction along with the mechanism of the reaction.

Expert Solution
Check Mark

Answer to Problem 23MP

The products of the reaction are ammonia and hexanoic acid.

The mechanism of the reaction is given below.

Formation of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  2

Hydrolysis of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  3

Where C5H11 = -CH2CH2CH2CH2CH3

Explanation of Solution

The nucleophilic attack of the hydroxide ion the nitrile carbon in hexanenitrile yields an imine anion as the product which in the next step gets protonated to produce a hydroxylimine. The hydroxylamine then tautomerizes to give hexanamide.

The nucleophilic attack of the hydroxide ion on the carbonyl carbon of the amide and subsequent loss an amide ion yields hexanoic acid. The deprotonation of the acid by the amide anion leads to the formation of carboxylate anion with the liberation of ammonia.

Conclusion

The products of the reaction are ammonia and hexanoic acid.

The mechanism of the reaction is given below.

Formation of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  4

Hydrolysis of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  5

Where C5H11 = -CH2CH2CH2CH2CH3

Interpretation Introduction

b)

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  6

Interpretation:

The products of the reaction along with the mechanism of the reaction are to be given.

Concept introduction:

The base catalyzed nitrile hydrolysis into an amide which is then further hydrolyzed to a carboxylate anion and ammonia takes place through the following steps. i) Nucleophilic attack of the hydroxide ion to the cyanide triple bond to yield an imideanion. ii)Protonation of the imine anion by water to yield a hydroxylamine.iii) Tautomerization of the hydroxylimine to an amide iv) Hydrolysis of the amide to carboxylate anion and ammonia.

To give:

The products of the reaction along with the mechanism of the reaction.

Expert Solution
Check Mark

Answer to Problem 23MP

The products of the reaction are ammonia and cyclobutanecarboxylate anion.

The mechanism of the reaction is given below.

Formation of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  7

Hydrolysis of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  8

Explanation of Solution

The nucleophilic attack of the hydroxide ion the nitrile carbon in 2-methylbutanenitrile yields an imine anion as the product which in the next step gets protonated to produce a hydroxylimine. The hydroxylamine then tautomerizes to give 2-methylbutanamide.

The nucleophilic attack of the hydroxide ion on the carbonyl carbon of the amide and subsequent loss an amide ion yields butanoic acid. The deprotonation of the acid by the amide anion leads to the formation of carboxylate anion with the liberation of ammonia.

Conclusion

The products of the reaction are ammonia and cyclobutanecarboxylate anion.

The mechanism of the reaction is given below.

Formation of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  9

Hydrolysis of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  10

Interpretation Introduction

c)

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  11

Interpretation:

The product of the reaction is to be given along with the mechanism of the reaction.

Concept introduction:

The base catalyzed nitrile hydrolysis into an amide which is then further hydrolyzed to a carboxylate anion and ammonia takes place through the following steps. i) Nucleophilic attack of the hydroxide ion to the cyanide triple bond to yield an imideanion. ii)Protonation of the imine anion by water to yield a hydroxylamine. iii) Tautomerization of the hydroxylimine to an amide iv) Hydrolysis of the amide to carboxylate anion and ammonia.

To give:

The products of the reaction along with the mechanism of the reaction.

Expert Solution
Check Mark

Answer to Problem 23MP

The products of the reaction are ammonia and m-methylbenzamide.

The mechanism of the reaction is given below.

Formation of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  12

Hydrolysis of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  13

Explanation of Solution

The nucleophilic attack of the hydroxide ion the nitrile carbon in m-methylbenzonitrile yields an imine anion as the product which in the next step gets protonated to produce a hydroxylimine. The hydroxylamine then tautomerizes to give 3-methylbenzamide.

The nucleophilic attack of the hydroxide ion on the carbonyl carbon of the amide and subsequent loss an amide ion yields m-methylbenzoic acid. The deprotonation of the acid by the amide anion leads to the formation of the carboxylate anion with the liberation of ammonia.

Conclusion

The products of the reaction are ammonia and m-methylbenzamide.

The mechanism of the reaction is given below.

Formation of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  14

Hydrolysis of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  15

Interpretation Introduction

d)

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  16

Interpretation:

The products of the reaction along with the mechanism of the reaction is to be given.

Concept introduction:

The base catalyzed nitrile hydrolysis into an amide which is then further hydrolyzed to a carboxylate anion and ammonia takes place through the following steps. i) Nucleophilic attack of the hydroxide ion to the cyanide triple bond to yield an imideanion. ii)Protonation of the imine anion by water to yield a hydroxylamine.iii) Tautomerization of the hydroxylimine to an amide iv) Hydrolysis of the amide to carboxylate anion and ammonia.

To give:

The products of the reaction along with the mechanism of the reaction.

Expert Solution
Check Mark

Answer to Problem 23MP

The products of the reaction are ammonia and cyclobutanecarboxylate ion.

The mechanism of the reaction is given below.

Formation of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  17

Hydrolysis of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  18

Explanation of Solution

The nucleophilic attack of the hydroxide ion the nitrile carbon in cyclobutanenitrile yields an imine anion as the product which in the next step gets protonated to produce a hydroxylimine. The hydroxylamine then tautomerizes to give cyclobutanecarboxylamide.

The nucleophilic attack of the hydroxide ion on the carbonyl carbon of the amide and subsequent loss an amide ion yields cyclobutane carboxyl acid. The deprotonation of the acid by the amide anion leads to the formation of carboxylate anion with the liberation of ammonia.

Conclusion

The products of the reaction are ammonia and cyclobutanecarboxylate ion.

The mechanism of the reaction is given below.

Formation of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  19

Hydrolysis of the amide:

ORGANIC CHEMISTRY-EBOOK>I<, Chapter 20.SE, Problem 23MP , additional homework tip  20

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Don't used hand raiting

Chapter 20 Solutions

ORGANIC CHEMISTRY-EBOOK>I<

Ch. 20.6 - Prob. 11PCh. 20.6 - How might you carry out the following...Ch. 20.7 - Prob. 13PCh. 20.7 - Prob. 14PCh. 20.8 - Cyclopentanecarboxylic acid and...Ch. 20.8 - Prob. 16PCh. 20.SE - Prob. 17VCCh. 20.SE - Prob. 18VCCh. 20.SE - The following carboxylic acid can’t be prepared...Ch. 20.SE - Electrostatic potential maps of anisole and...Ch. 20.SE - Predict the product(s) and provide the mechanism...Ch. 20.SE - Predict the product(s) and provide the mechanism...Ch. 20.SE - Prob. 23MPCh. 20.SE - Predict the product(s) and provide the complete...Ch. 20.SE - Acid-catalyzed hydrolysis of a nitrile to give a...Ch. 20.SE - Prob. 26MPCh. 20.SE - Naturally occurring compounds called cyanogenic...Ch. 20.SE - 2-Bromo-6, 6-dimethylcyclohexanone gives 2,...Ch. 20.SE - Naturally occurring compounds called terpenoids,...Ch. 20.SE - In the Ritter reaction, an alkene reacts with a...Ch. 20.SE - Give IUPAC names for the following compounds:Ch. 20.SE - Prob. 32APCh. 20.SE - Prob. 33APCh. 20.SE - Prob. 34APCh. 20.SE - Prob. 35APCh. 20.SE - Prob. 36APCh. 20.SE - Prob. 37APCh. 20.SE - Prob. 38APCh. 20.SE - Calculate the Ka's for the following acids: (a)...Ch. 20.SE - Thioglycolic acid, HSCH2CO2H, a substance used in...Ch. 20.SE - Prob. 41APCh. 20.SE - Prob. 42APCh. 20.SE - How could you convert butanoic acid into the...Ch. 20.SE - How could you convert each of the following...Ch. 20.SE - How could you convert butanenitrile into the...Ch. 20.SE - How would you prepare the following compounds from...Ch. 20.SE - Prob. 47APCh. 20.SE - Using 13CO2 as your only source of labeled carbon,...Ch. 20.SE - Prob. 49APCh. 20.SE - Which method-Grignard carboxylation or nitrile...Ch. 20.SE - Prob. 51APCh. 20.SE - Prob. 52APCh. 20.SE - Propose a structure for a compound C6H12O2 that...Ch. 20.SE - Prob. 54APCh. 20.SE - How would you use NMR (either 13C or 1H) to...Ch. 20.SE - Prob. 56APCh. 20.SE - A chemist in need of 2,2-dimethylpentanoic acid...Ch. 20.SE - Prob. 58APCh. 20.SE - Prob. 59APCh. 20.SE - Prob. 60APCh. 20.SE - Prob. 61APCh. 20.SE - Prob. 62APCh. 20.SE - Prob. 63APCh. 20.SE - The following pKa values have been measured....Ch. 20.SE - Identify the missing reagents a-f in the following...Ch. 20.SE - Propose a structure for a compound, C4H7N, that...Ch. 20.SE - Prob. 67APCh. 20.SE - The 1H and 13C NMR spectra below belong to a...Ch. 20.SE - Propose structures for carboxylic acids that show...Ch. 20.SE - Carboxylic acids having a second carbonyl group...
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