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Fundamentals of General, Organic, and Biological Chemistry, Books a la Carte Plus Mastering Chemistry with Pearson eText -- Access Card Package (8th Edition)
8th Edition
ISBN: 9780134261256
Author: John McMurray, David S. Ballantine, Carl A. Hoeger, Virginia E. Peterson
Publisher: PEARSON
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Chapter 20.4, Problem 20.1CIAP
Interpretation Introduction
Interpretation:
The structural difference between blood group determinants has to be explained.
Concept introduction:
The human blood is classified into four types based on presence of side chain on D-galactose in red blood cell.
Blood group O has no side chain on D-galactose of red blood cell.
Blood group A has a side chain of N-acetyl-D-galactosamine on D-galactose of red blood cell.
Blood group B has a side chain of D-galactose on D-galactose of red blood cell.
Blood group AB has both oligosaccharides present in blood group A and blood group B.
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Problem 15 of 15
Submit
Using the following reaction data
points, construct Lineweaver-Burk
plots for an enzyme with and without
an inhibitor by dragging the points to
their relevant coordinates on the
graph and drawing a line of best fit.
Using the information from this plot,
determine the type of inhibitor
present.
1
mM-1
1
s mM
-1
[S]'
V'
with 10 μg per
20
54
10
36
20
5
27
2.5
23
1.25
20
Answer:
|||
12:33
CO
Problem 4 of 15
4G 54%
Done
On the following Lineweaver-Burk
-1
plot, identify the by dragging the
Km
point to the appropriate value.
1/V
40
35-
30-
25
20
15
10-
T
Км
-15
10
-5
0
5
|||
10
15
№20
25
25
30
1/[S]
Г
powered by
desmos
1:30
5G 47%
Problem 10 of 15
Submit
Using the following reaction data
points, construct a Lineweaver-Burk
plot for an enzyme with and without a
competitive inhibitor by dragging the
points to their relevant coordinates
on the graph and drawing a line of
best fit.
1
-1 1
mM
[S]'
s mM¹ with 10 mg pe
20
V'
54
10
36
>
ст
5
27
2.5
23
1.25
20
Answer:
|||
Chapter 20 Solutions
Fundamentals of General, Organic, and Biological Chemistry, Books a la Carte Plus Mastering Chemistry with Pearson eText -- Access Card Package (8th Edition)
Ch. 20.1 - Classify the following monosaccharides as an...Ch. 20.1 - Prob. 20.2PCh. 20.2 - Prob. 20.3PCh. 20.2 - Prob. 20.4PCh. 20.2 - Prob. 20.6PCh. 20.3 - D-Talose, a constituent of certain antibiotics,...Ch. 20.3 - Prob. 20.8PCh. 20.3 - Draw the structure that completes the mutarotation...Ch. 20.4 - Prob. 20.10KCPCh. 20.4 - Prob. 20.11P
Ch. 20.4 - Prob. 20.12PCh. 20.4 - Prob. 20.13PCh. 20.4 - Prob. 20.1CIAPCh. 20.4 - Prob. 20.2CIAPCh. 20.4 - All cells in your body contain glycoproteins...Ch. 20.5 - Draw the structure of the and anomers that...Ch. 20.6 - Prob. 20.15PCh. 20.6 - Prob. 20.16PCh. 20.6 - Prob. 20.17KCPCh. 20.7 - Prob. 20.4CIAPCh. 20.7 - Prob. 20.5CIAPCh. 20.7 - Prob. 20.6CIAPCh. 20.7 - Prob. 20.7CIAPCh. 20.7 - Prob. 20.18PCh. 20.7 - Prob. 20.19PCh. 20.7 - Prob. 20.8CIAPCh. 20.7 - Prob. 20.9CIAPCh. 20.7 - Prob. 20.10CIAPCh. 20 - During the digestion of starch from potatoes, the...Ch. 20 - Prob. 20.21UKCCh. 20 - Consider the trisaccharide A, B, C shown in...Ch. 20 - Hydrolysis of both glycosidic bonds in the...Ch. 20 - Prob. 20.24UKCCh. 20 - Are one or more of the disaccharides maltose,...Ch. 20 - Prob. 20.26UKCCh. 20 - Prob. 20.27UKCCh. 20 - Prob. 20.28APCh. 20 - What is the family-name ending for a sugar?Ch. 20 - Prob. 20.30APCh. 20 - Classify the four carbohydrates (a)(d) by...Ch. 20 - Prob. 20.32APCh. 20 - How many chiral carbon atoms are there in each of...Ch. 20 - Prob. 20.34APCh. 20 - Prob. 20.35APCh. 20 - Name four important monosaccharides and tell where...Ch. 20 - Prob. 20.37APCh. 20 - Prob. 20.38APCh. 20 - What is the structural relationship between...Ch. 20 - Prob. 20.40APCh. 20 - In Section 15.6, you saw that aldehydes react with...Ch. 20 - Sucrose and D-glucose rotate plane-polarized light...Ch. 20 - Prob. 20.43APCh. 20 - Prob. 20.44APCh. 20 - Prob. 20.45APCh. 20 - What is mutarotation? Do all chiral molecules do...Ch. 20 - What are anomers, and how do the anomers of a...Ch. 20 - What is the structural difference between the ...Ch. 20 - D-Gulose, an aldohexose isomer of glucose, has the...Ch. 20 - Prob. 20.50APCh. 20 - In its open-chain form, D-altrose has the...Ch. 20 - Prob. 20.52APCh. 20 - Prob. 20.53APCh. 20 - Prob. 20.54APCh. 20 - Prob. 20.55APCh. 20 - What is the structural difference between a...Ch. 20 - What are glycosides, and how can they be formed?Ch. 20 - Prob. 20.58APCh. 20 - Prob. 20.59APCh. 20 - Give the names of three important disaccharides....Ch. 20 - Lactose and maltose are reducing disaccharides,...Ch. 20 - Amylose (a form of starch) and cellulose are both...Ch. 20 - Prob. 20.63APCh. 20 - Prob. 20.64APCh. 20 - Prob. 20.65APCh. 20 - Gentiobiose, a rare disaccharide found in saffron,...Ch. 20 - Prob. 20.67APCh. 20 - Prob. 20.68APCh. 20 - Prob. 20.69APCh. 20 - Amylopectin (a form of starch) and glycogen are...Ch. 20 - What is the physiological purpose of starch in a...Ch. 20 - Prob. 20.72APCh. 20 - Prob. 20.73APCh. 20 - Prob. 20.74CPCh. 20 - Prob. 20.75CPCh. 20 - Prob. 20.76CPCh. 20 - Prob. 20.77CPCh. 20 - Prob. 20.78CPCh. 20 - Write the open-chain structure of the only...Ch. 20 - Prob. 20.80CPCh. 20 - Prob. 20.81CPCh. 20 - When a person cannot digest galactose, its reduced...Ch. 20 - Describe the differences between mono-, di-, and...Ch. 20 - Prob. 20.84CPCh. 20 - Prob. 20.85CPCh. 20 - Many people who are lactose intolerant can eat...Ch. 20 - Prob. 20.87GPCh. 20 - Prob. 20.88GPCh. 20 - Prob. 20.89GP
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- Problem 14 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:36 CO Problem 9 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of the catalytic efficiency (specificity constant) given that the enzyme concentration in this experiment is 5.0 μ.Μ. 1 [S] ¨‚ μM-1 1 V sμM-1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| O Гarrow_forwardProblem 11 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a noncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 13 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- 12:33 CO Problem 7 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of Vmax. Report your answer to three significant figures. 1 , mM-1 1 [S] V' sμM-¹ 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward12:33 CO Problem 5 of 15 4G 54% Done On the following Lineweaver-Burk 1 plot, identify the by dragging the Vmax point to the appropriate value on the line. NI 35 30- 25 20- 15- 10 5. 1 Vmax -15 10 -5 0 5 10 15 20 20 ||| で Г 25 30 1/[S]arrow_forward12:20 V 0.1- 0:09. 0.08 0:07 0.06 -0.05- 0:04- -0.03- -0.02- 4G 56% Problem 1 of 15 Done On the following Michaelis-Menten plot, estimate the value of - Vmax by 1 2 dragging the line to the appropriate value on the y-axis. 0.01 V max 0 0.5 ||| 1.5 2.5 3.5 4 ISLarrow_forward
- 12:33 CO 4G 54% Problem 6 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the Km. 1 mM-1 1 [S]' " s mM-1 V 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forwardV 0.1- 0:09 0:08 0:07- -0.06 -0.05 0:04- 0:03 0:02 0:01- Problem 2 of 15 Done On the following Michaelis-Menten plot, estimate the value of Kм by dragging the point to the appropriate value on the x-axis. I T | 0 0.5 1.5 2 KM -0:01- ||| 25 2.5 3 3.5 4 Г [S] powered by desmosarrow_forward9. Sketch NMR of the following compound. Clearly label each H-atom in the molecule and where it appears in your NMR. Clearly label the splitting (coupling) pattern (singlet, doublet etc) for each set of equivalent protons. For each signal, clearly label the integration value or the number of protons represented by the signal. Brarrow_forward
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