Explain the length of taps permitted to the individual appliances when both wall-mounted oven and a counter-mounted cooking unit are connected to one branch circuit.

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Crystallographic planes Crystallographic planes are denoted by Miller indices. 5b Algorithm for Miller indices 1. Read off intercepts of plane with axes in terms of a, b, c 2. Take reciprocals of intercepts 3. Reduce to smallest integer values 4. Enclose in parentheses, no commas. 353 1/3 1/5 1/3 535 (535) In the cubic system, a plane and a direction with the same indices are orthogonal. E.g. [100] direction is perpendicular to (100) plane. Correspondingly, [123] direction is perpendicular to (123) plane. [2,3,3] Plane intercepts axes at 3a, 2b, 2c 2 11 1 Reciprocal numbers are: 3'2'2 b. Indices of the plane (Miller): (2,3,3) 2 a Indices of the direction: [2,3,3] X (200) (100) (110) (111) (100) Indices of crystallographic plane can be found from cross product of indices of any two non-parallel directions in this plane.

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Chapter 20.2, Problem 6R

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Explain the length of taps permitted to the individual appliances when both wall-mounted oven and a counter-mounted cooking unit are connected to one branch circuit.

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Crystallographic planes Crystallographic planes are denoted by Miller indices. 5b Algorithm for Miller indices 1. Read off intercepts of plane with axes in terms of a, b, c 2. Take reciprocals of intercepts 3. Reduce to smallest integer values 4. Enclose in parentheses, no commas. 353 1/3 1/5 1/3 535 (535) In the cubic system, a plane and a direction with the same indices are orthogonal. E.g. [100] direction is perpendicular to (100) plane. Correspondingly, [123] direction is perpendicular to (123) plane. [2,3,3] Plane intercepts axes at 3a, 2b, 2c 2 11 1 Reciprocal numbers are: 3'2'2 b. Indices of the plane (Miller): (2,3,3) 2 a Indices of the direction: [2,3,3] X (200) (100) (110) (111) (100) Indices of crystallographic plane can be found from cross product of indices of any two non-parallel directions in this plane.

Crystallographic positions Crystallographic position is denoted by three numbers, which are coefficients of the position vector, e.g. ½½½ for the red atom. Here the 'new' atom is at a/2 + b/2 + c/2 Silicon crystal has so-called "diamond type lattice". Each Si atom has 4 nearest neighbors. Diamond lattice starts with a FCC lattice and then adds four additional INTERNAL atoms at locations r = a/4+b/4+c/4 away from each of the atoms. In other words, diamond lattice is formed by two FCC lattices sifted by the vector r.

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