Degarmo's Materials And Processes In Manufacturing
13th Edition
ISBN: 9781119492825
Author: Black, J. Temple, Kohser, Ronald A., Author.
Publisher: Wiley,
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Chapter 20, Problem 95RQ
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2) Use the method of MEMBERS to determine the true magnitude and
direction of the forces in members1 and 2 of the frame shown below
in Fig 3.2.
300lbs/ft
member-1
member-2
30°
Fig 3.2.
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5670 mm
The apartment in the ground floor of three floors building in Fig. in Baghdad city. The details of
walls, roof, windows and door are shown. The window is a double glazing and air space thickness
is 1.3cm Poorly Fitted-with Storm Sash with wood strip and storm window of 0.6 cm glass
thickness. The thickness of door is 2.5 cm. The door is Poor Installation. There are two peoples
in each room. The height of room is 280 cm. assume the indoor design conditions are 25°C DBT
and 50 RH, and moisture content of 8 gw/kga. The moisture content of outdoor is 10.5 gw/kga.
Calculate heat gain for living room :
الشقة في الطابق الأرضي من مبنى ثلاثة طوابق في مدينة بغداد يظهر في مخطط الشقة تفاصيل الجدران والسقف
والنوافذ والباب. النافذة عبارة عن زجاج مزدوج وسمك الفراغ الهوائي 1.3 سم ضعيف الاحكام مع ساتر حماية مع إطار
خشبي والنافذة بسماكة زجاج 0.6 سم سماكة الباب 2.5 سم. الباب هو تركيب ضعيف هناك شخصان في كل غرفة.
ارتفاع الغرفة 280 سم. افترض أن ظروف التصميم الداخلي هي DBT25 و R50 ، ومحتوى الرطوبة 8…
Chapter 20 Solutions
Degarmo's Materials And Processes In Manufacturing
Ch. 20 - Why are the fabrication processes applied to...Ch. 20 - How does the fabrication of a shaped product from...Ch. 20 - What are some of the methods used to shape...Ch. 20 - What are some of the ways that plastic sheet,...Ch. 20 - Prob. 5RQCh. 20 - What types of polymers are most commonly blow...Ch. 20 - What are some common blow molded products, in...Ch. 20 - Why do blow molding molds typically contain a...Ch. 20 - Prob. 9RQCh. 20 - Prob. 10RQ
Ch. 20 - Prob. 11RQCh. 20 - Prob. 12RQCh. 20 - Prob. 13RQCh. 20 - Prob. 14RQCh. 20 - Prob. 15RQCh. 20 - What are some of the benefits of a hot runner...Ch. 20 - Why is the cycle time for the injection molding of...Ch. 20 - Prob. 18RQCh. 20 - Prob. 19RQCh. 20 - What are some of the ways by which a polymer...Ch. 20 - Prob. 21RQCh. 20 - How can the extrusion process be used to produce...Ch. 20 - Prob. 23RQCh. 20 - Prob. 24RQCh. 20 - Prob. 25RQCh. 20 - What is the difference between open-cell and...Ch. 20 - Prob. 27RQCh. 20 - What types of products are produced by...Ch. 20 - Prob. 29RQCh. 20 - What are some of the general properties of...Ch. 20 - What are some of the attractive features of laser...Ch. 20 - What property of plastics is responsible for...Ch. 20 - Prob. 33RQCh. 20 - Prob. 34RQCh. 20 - Prob. 35RQCh. 20 - Prob. 36RQCh. 20 - Prob. 37RQCh. 20 - Prob. 38RQCh. 20 - Why might threaded inserts be preferred over other...Ch. 20 - What are some of the ways in which metal inserts...Ch. 20 - Prob. 41RQCh. 20 - Why does locating a parting line on a sharp corner...Ch. 20 - Prob. 43RQCh. 20 - Prob. 44RQCh. 20 - Prob. 45RQCh. 20 - What property changes occur during vulcanization?Ch. 20 - Prob. 47RQCh. 20 - Prob. 48RQCh. 20 - How are glass fibers produced?Ch. 20 - Prob. 50RQCh. 20 - Prob. 51RQCh. 20 - What are glass-ceramics? How are they produced?Ch. 20 - Prob. 53RQCh. 20 - Describe the differences between the injection...Ch. 20 - Prob. 55RQCh. 20 - What is the difference between slip casting and...Ch. 20 - Prob. 57RQCh. 20 - Prob. 58RQCh. 20 - How does cementation differ from sintering?Ch. 20 - What are the benefits and limitations of machining...Ch. 20 - Prob. 61RQCh. 20 - Why are joining operations usually avoided when...Ch. 20 - Prob. 63RQCh. 20 - Discuss some of the design guidelines that relate...Ch. 20 - Prob. 65RQCh. 20 - Why are the processes used to fabricate...Ch. 20 - How are metals and ceramics combined in the...Ch. 20 - What are some of the processes that can be used to...Ch. 20 - What conditions might be attractive for...Ch. 20 - Prob. 70RQCh. 20 - Prob. 71RQCh. 20 - Prob. 72RQCh. 20 - Prob. 73RQCh. 20 - What are some of the ways that liquefied matrix...Ch. 20 - Prob. 75RQCh. 20 - Prob. 76RQCh. 20 - Prob. 77RQCh. 20 - In what way is pultrusion similar to wire drawing?Ch. 20 - Prob. 79RQCh. 20 - What are some typical products that are made by...Ch. 20 - Prob. 81RQCh. 20 - Prob. 82RQCh. 20 - Prob. 83RQCh. 20 - Prob. 84RQCh. 20 - Prob. 85RQCh. 20 - Prob. 86RQCh. 20 - What is the difference between reaction injection...Ch. 20 - Prob. 88RQCh. 20 - Prob. 89RQCh. 20 - What is a common property objective in...Ch. 20 - Prob. 91RQCh. 20 - Prob. 92RQCh. 20 - Prob. 93RQCh. 20 - What is the major concern when considering the...Ch. 20 - Prob. 95RQCh. 20 - Prob. 1PCh. 20 - Figure 20.A depicts the handles of two large...Ch. 20 - Tires are the dominant product of the rubber...Ch. 20 - Prob. 4PCh. 20 - Prob. 6PCh. 20 - Prob. 8PCh. 20 - Prob. 1.1CSCh. 20 - For plastic (high-density polyethylene)...Ch. 20 - What might be the pros and cons of weldable...Ch. 20 - Prob. 1.5CSCh. 20 - Prob. 1.6CSCh. 20 - Prob. 1.7CSCh. 20 - Crashworthiness is an important safety...Ch. 20 - Prob. 1.9CSCh. 20 - Prob. 1.10CSCh. 20 - Prob. 1.11CSCh. 20 - Prob. 2.1CSCh. 20 - Prob. 2.2CSCh. 20 - Prob. 2.3CSCh. 20 - Prob. 2.4CSCh. 20 - Prob. 2.5CS
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- How do i solve this problem?arrow_forwardQ4/ A compressor is driven motor by mean of a flat belt of thickness 10 mm and a width of 250 mm. The motor pulley is 300 mm diameter and run at 900 rpm and the compressor pulley is 1500 mm diameter. The shaft center distance is 1.5 m. The angle of contact of the smaller pulley is 220° and on the larger pulley is 270°. The coefficient of friction between the belt and the small pulley is 0.3, and between the belt and the large pulley is 0.25. The maximum allowable belt stress is 2 MPa and the belt density is 970 kg/m³. (a) What is the power capacity of the drive and (b) If the small pulley replaced by V-grooved pulley of diameter 300 mm, grooved angle of 34° and the coefficient of friction between belt and grooved pulley is 0.35. What will be the power capacity in this case, assuming that the diameter of the large pulley remain the same of 1500 mm.arrow_forwardYou are tasked with designing a power drive system to transmit power between a motor and a conveyor belt in a manufacturing facility as illustrated in figure. The design must ensure efficient power transmission, reliability, and safety. Given the following specifications and constraints, design drive system for this application: Specifications: Motor Power: The electric motor provides 10 kW of power at 1,500 RPM. Output Speed: The output shaft should rotate at 150 rpm. Design Decisions: Transmission ratio: Determine the necessary drive ratio for the system. Shaft Diameter: Design the shafts for both the motor and the conveyor end. Material Selection: Choose appropriate materials for the gears, shafts. Bearings: Select suitable rolling element bearings. Constraints: Space Limitation: The available space for the gear drive system is limited to a 1-meter-long section. Attribute 4 of CEP Depth of knowledge required Fundamentals-based, first principles analytical approach…arrow_forward
- - | العنوان In non-continuous dieless drawing process for copper tube as shown in Fig. (1), take the following data: Do-20mm, to=3mm, D=12mm, ti/to=0.6 and v.-15mm/s. Calculate: (1) area reduction RA, (2) drawing velocity v. Knowing that: ti: final thickness V. Fig. (1) ofthrearrow_forwardA direct extrusion operation produces the cross section shown in Fig. (2) from an aluminum billet whose diameter 160 mm and length - 700 mm. Determine the length of the extruded section at the end of the operation if the die angle -14° 60 X Fig. (2) Note: all dimensions in mm.arrow_forwardFor hot rolling processes, show that the average strain rate can be given as: = (1+5)√RdIn(+1)arrow_forward
- : +0 usão العنوان on to A vertical true centrifugal casting process is used to produce bushings that are 250 mm long and 200 mm in outside diameter. If the rotational speed during solidification is 500 rev/min, determine the inside radii at the top and bottom of the bushing if R-2R. Take: -9.81 mis ۲/۱ ostrararrow_forward: +0 العنوان use only In conventional drawing of a stainless steel wire, the original diameter D.-3mm, the area reduction at each die stand r-40%, and the proposed final diameter D.-0.5mm, how many die stands are required to complete this process. онarrow_forwardIn non-continuous dieless drawing process for copper tube as shown in Fig. (1), take the following data: Do-20mm, to=3mm, D=12mm, ti/to=0.6 and vo-15mm/s. Calculate: (1) area reduction RA, (2) drawing velocity v. Knowing that: t₁: final thickness D₁ V. Fig. (1) Darrow_forward
- A vertical true centrifugal casting process is used to produce bushings that are 250 mm long and 200 mm in outside diameter. If the rotational speed during solidification is 500 rev/min, determine the inside radii at the top and bottom of the bushing if R-2Rb. Take: 8-9.81 m/sarrow_forwardIn conventional drawing of a stainless steel wire, the original diameter D.-3mm, the area reduction at each die stand r-40%, and the proposed final diameter D₁-0.5mm, how many die stands are required to complete this process.arrow_forwardA vertical true centrifugal casting process is used to produce bushings that are 250 mm long and 200 mm in outside diameter. If the rotational speed during solidification is 500 rev/min, determine the inside radii at the top and bottom of the bushing if R-2Rb. Take: 8-9.81 m/sarrow_forward
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