Explanation The total force acting on the bar is equal to magnetic force minus gravitational force. Equate total force to mathematical expression for Newton’s second law of acceleration. Write the expression for net force ∑ F = m a = F B − F g (I) Here, m is the mass of the bar, a is the acceleration, F B is the magnetic force, F g is the force due to gravity F B and B are perpendicular to each other thus, ϕ will be equal to 90 ° . Write the expression for magnetic force F B = i l B sin ( 90 ° ) = i l B (II) Here, i is the current through the bar, l is the length of the bar, B is the magnetic field, ϕ is the angle between F B and B Write the expression for gravitational force F g = m g (III) Here, g is the acceleration due gravity Substitute equation (II) and (III) in equation (I) and rearrange to obtain an expression for a ∑ F = m a = i l B − m g a = i l B − m g m (IV) Analysing the figure 20.73, bar is parallel to 10.0 Ω resistor, and the parallel combination is in series with 25.0 Ω resistor. Write the expression for combined parallel resistance R p = R 1 R 2 R 1 + R 2 (V) Here, R p is the combined parallel resistance Write the expression for combined series resistance R s = R p + R 3 (VI) Here, R s is the combined series resistance The current through the circuit is I = V R s (VII) Here, I is the current, V is the voltage The current through bar will be half of the current through circuit i = I 2 (VIII) Conclusion: Substitute 10.0 Ω for both R 1 and R 2 in equation (V) R p = 10

10th Edition

ISBN: 9780321902788

Author: Hugh D. Young, Philip W. Adams, Raymond Joseph Chastain

Publisher: PEARSON

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Electromagnets

The word "electromagnet" is composed of two words, ‘electro’ and ‘magnet’. It is a type of magnet in which an electric current helps in the generation of a magnetic field. Electromagnets usually consist of two major parts, wire and a coil around which th…

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Chapter 20, Problem 82GP

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The acceleration of the bar just after the switch is closed.

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Chapter 20, Problem 81GP

Chapter 20, Problem 83GP

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Chapter 20 Solutions

College Physics (10th Edition)

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The acceleration of the bar just after the switch is closed.

Solution Summary: The author calculates the total force acting on the bar is equal to magnetic force minus gravitational force.

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The acceleration of the bar just after the switch is closed.

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Chapter 20 Solutions