The decomposition of ethylene oxide at 690 K is monitored by measuring the total gas pressure as a function of time. The data obtained are t = 10 min, P col = 139.14 mmHg; 20 min, 151.67 mmHg; 40 min, 172.65 mmHg; 60 min, 189.15 mmHg; 100 min, 212.34mmHg; 200 min, 238.66 mmHg; ∞ , 249.88 mmHg. What is the order of the reaction ( CH 2 ) 2 O ( g ) → CH 4 ( g ) + CO ( g ) ?
The decomposition of ethylene oxide at 690 K is monitored by measuring the total gas pressure as a function of time. The data obtained are t = 10 min, P col = 139.14 mmHg; 20 min, 151.67 mmHg; 40 min, 172.65 mmHg; 60 min, 189.15 mmHg; 100 min, 212.34mmHg; 200 min, 238.66 mmHg; ∞ , 249.88 mmHg. What is the order of the reaction ( CH 2 ) 2 O ( g ) → CH 4 ( g ) + CO ( g ) ?
Solution Summary: The author explains that the order of a reaction is defined as the summation of the stoichiometric coefficient of reactants in the rate law expression.
The decomposition of ethylene oxide at 690 K is monitored by measuring the total gas pressure as a function of time. The data obtained are t = 10 min,
P
col
=
139.14
mmHg; 20 min, 151.67 mmHg; 40 min, 172.65 mmHg; 60 min, 189.15 mmHg; 100 min, 212.34mmHg; 200 min, 238.66 mmHg;
∞
, 249.88 mmHg. What is the order of the reaction
(
CH
2
)
2
O
(
g
)
→
CH
4
(
g
)
+
CO
(
g
)
?
3. Consider the compounds below and determine if they are aromatic, antiaromatic, or
non-aromatic. In case of aromatic or anti-aromatic, please indicate number of I
electrons in the respective systems. (Hint: 1. Not all lone pair electrons were explicitly
drawn and you should be able to tell that the bonding electrons and lone pair electrons
should reside in which hybridized atomic orbital 2. You should consider ring strain-
flexibility and steric repulsion that facilitates adoption of aromaticity or avoidance of anti-
aromaticity)
H H
N
N:
NH2
N
Aromaticity
(Circle)
Aromatic Aromatic Aromatic Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic TT
electrons
Me
H
Me
Aromaticity
(Circle)
Aromatic Aromatic Aromatic
Aromatic Aromatic
Antiaromatic Antiaromatic Antiaromatic Antiaromatic Antiaromatic
nonaromatic nonaromatic nonaromatic nonaromatic nonaromatic
aromatic πT
electrons
H
HH…
A chemistry graduate student is studying the rate of this reaction:
2 HI (g) →H2(g) +12(g)
She fills a reaction vessel with HI and measures its concentration as the reaction proceeds:
time
(minutes)
[IH]
0
0.800M
1.0
0.301 M
2.0
0.185 M
3.0
0.134M
4.0
0.105 M
Use this data to answer the following questions.
Write the rate law for this reaction.
rate
= 0
Calculate the value of the rate constant k.
k =
Round your answer to 2 significant digits. Also be
sure your answer has the correct unit symbol.
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