CHEMISTRY >CUSTOM<
CHEMISTRY >CUSTOM<
14th Edition
ISBN: 9781259137815
Author: Julia Burdge
Publisher: McGraw-Hill Education
Question
Book Icon
Chapter 20, Problem 5QP
Interpretation Introduction

Interpretation:

The unknown atom, X, is to be identified in the given nuclear reactions.

Concept Introduction:

In a balanced radioactive decay:

Reactant mass number = Product mass number

Reactant atomic number = Product atomic number

In a balanced radioactive decay, the subscript on the individual particles represents the atomic number, while the superscript represents the atomic mass.

Expert Solution & Answer
Check Mark

Answer to Problem 5QP

Solution:

(a)

The term X is (b) (c)(d) (e) (f) 11(g) (h) 23(i)(j)Na.(k) (l)

(m)

The term X is (n) (o)(p) (q) 1(r) 1(s)(t)H.(u) (v)

(w)

The term X is (x) (y)(z) (aa) (bb)(cc)1(dd)(ee)(ff) 0(gg)(hh)n(ii) (jj).

(kk)

The term X is (ll) (mm)(nn) (oo) (pp) 26(qq) (rr) 56(ss)(tt)Fe(uu) (vv).

(ww)

The term X is (xx) (yy)(zz) (aaa) (bbb) 1(ccc) 0(ddd)(eee)β.(fff) (ggg)

Explanation of Solution

a) 1226Mg +11α+X.

The atomic mass and atomic number of α are 4 and 2 , respectively.

Now, apply the balancing rules as follows:

Reactant mass number = Product mass number

And

Reactant atomic number = Product atomic number

On the left side of the reaction, the sum of atomic numbers is calculated as follows:

(12) + (1)=13

On the right side of the reaction, the sum of atomic numbers is (2)(atomic number of X).

Thus, the atomic number of X is as follows:

(13)(2)=11.

On the left side of the reaction, the sum of mass numbers is as follows:

(26)+(1) = 27

On the right side of the reaction, the sum of mass numbers is (4)+(mass number of X).

Thus, the mass number of X is as follows:

(27)(4)=23

So, X will be 1123Na.

b) 2759Co+12H2760Co + X

Now, apply the balancing rules as follows:

Reactant mass number = Product mass number

And

Reactant atomic number = Product atomic number

On the left side of the reaction, the sum of atomic numbers is calculated as follows:

(27)+(1)=28

On the right side of the reaction, the sum of atomic numbers is (27) + (atomic number of X).

Thus, the atomic number of X is calculated as follows:

(28)(27)=1

Similarly,

On the left side of the reaction, the sum of mass numbers is calculated as follows:

(59)+( 2)= 61

On the right side of the reaction, the sum of mass numbers is (60)+(mass number of X).

Thus, the mass number of X is calculated as follows:

(61)(60)=1

So, X will be 11H.

c) 23592U + 10n 3694Kr+56139Ba + 3X

Now, apply the balancing rules as follows:

Reactant mass number = Product mass number

And

Reactant atomic number = Product atomic number

On the left side of the reaction, the sum of atomic numbers is as follows:

(92) + (0) = 92

On the right side of the reaction, the sum of atomic numbers is 36 + 56+ 3×(atomic number of X).

Thus, the atomic number of X is calculated as follows:

(92)(36 + 56)3=0

Similarly,

On the left side of the reaction, the sum of mass numbers is calculated as follows:

(235+1)=236

On the right side of the reaction, the sum of mass numbers is 94 + 139 + 3×(mass number of X).

Thus, the mass number of X is calculated as follows:

((236)(94 + 139)3)=1

So, X will be 10n.

d) 2453Cr +24α 01n+X.

Now, apply the balancing rules as follows:

Reactant mass number = Product mass number

And

Reactant atomic number = Product atomic number

On the left side of the reaction, the sum of atomic numbers is calculated as follows:

(24)+(2)=26

On the right side of the reaction, the sum of atomic numbers is (0)+(atomic number of X).

Thus, the atomic number of X is as follows:

(26)(0)=26

Similarly,

On the left side of the reaction, the sum of mass numbers is calculated as follows:

(53)+(4)=57

On the right side of the reaction, the sum of mass numbers is (1)+(mass number of X).

Thus, the mass number of X is as follows:

(57)(1)=56

So, X will be 2656Fe.

e) 820920F+X.

Now, apply the balancing rules as:

Reactant mass number = Product mass number

And

Reactant atomic number = Product atomic number

On the left side of the reaction, the sum of atomic numbers is 8.

On the right side of the reaction, the sum of atomic numbers is (9)+(atomic number of X).

Thus, atomic number of X is calculated as follows:

(8)(9)=1

Similarly,

On the left side of the reaction, the sum of mass numbers is 20.

On the right side of the reaction, the sum of mass numbers is (20)+(mass number of X).

Thus, the mass number of X is as follows:

(20)(20)=0

So, X will be 10β.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
You are trying to decide if there is a single reagent you can add that will make the following synthesis possible without any other major side products: xi 1. ☑ 2. H₂O хе i Draw the missing reagent X you think will make this synthesis work in the drawing area below. If there is no reagent that will make your desired product in good yield or without complications, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. There is no reagent that will make this synthesis work without complications. : ☐ S ☐
Predict the major products of this organic reaction: H OH 1. LiAlH4 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. G C टे
For each reaction below, decide if the first stable organic product that forms in solution will create a new C-C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 CI MgCl ? Will the first product that forms in this reaction create a new CC bond? Yes No MgBr ? Will the first product that forms in this reaction create a new CC bond? Yes No G टे

Chapter 20 Solutions

CHEMISTRY >CUSTOM<

Ch. 20.2 - Prob. 3CPCh. 20.2 - Prob. 4CPCh. 20.3 - Prob. 1PPACh. 20.3 - Prob. 1PPBCh. 20.3 - Practice Problem CONCEPTUALIZE The Think About It...Ch. 20.3 - Prob. 1CPCh. 20.3 - Prob. 2CPCh. 20.3 - Prob. 3CPCh. 20.4 - Practice Problem ATTEMPT Determine the age of a...Ch. 20.4 - Practice Problem BUILD How much 206 Pb will be in...Ch. 20.4 - Prob. 1PPCCh. 20.4 - Prob. 1CPCh. 20.4 - Prob. 2CPCh. 20.5 - Prob. 1PPACh. 20.5 - Prob. 1PPBCh. 20.5 - Practice Problem CONCEPTUALIZE One of the major...Ch. 20 - Prob. 1QPCh. 20 - Prob. 2QPCh. 20 - Prob. 3QPCh. 20 - Prob. 4QPCh. 20 - Prob. 5QPCh. 20 - Prob. 6QPCh. 20 - Prob. 7QPCh. 20 - Prob. 8QPCh. 20 - 20.9 why is it impossible for the isotope to...Ch. 20 - Prob. 10QPCh. 20 - Prob. 11QPCh. 20 - Prob. 12QPCh. 20 - Prob. 13QPCh. 20 - For each pair of isotopes listed, predict which...Ch. 20 - Prob. 15QPCh. 20 - Prob. 16QPCh. 20 - Prob. 17QPCh. 20 - Prob. 18QPCh. 20 - Prob. 19QPCh. 20 - Prob. 20QPCh. 20 - Prob. 21QPCh. 20 - Prob. 22QPCh. 20 - Prob. 23QPCh. 20 - Prob. 24QPCh. 20 - Prob. 25QPCh. 20 - Prob. 26QPCh. 20 - Prob. 27QPCh. 20 - Prob. 28QPCh. 20 - Prob. 29QPCh. 20 - Prob. 30QPCh. 20 - Prob. 31QPCh. 20 - Prob. 32QPCh. 20 - Prob. 33QPCh. 20 - Prob. 34QPCh. 20 - Prob. 35QPCh. 20 - Prob. 36QPCh. 20 - Prob. 37QPCh. 20 - Prob. 38QPCh. 20 - Prob. 39QPCh. 20 - Prob. 40QPCh. 20 - Prob. 41QPCh. 20 - Prob. 42QPCh. 20 - Prob. 43QPCh. 20 - Prob. 44QPCh. 20 - Prob. 45QPCh. 20 - Prob. 46QPCh. 20 - Prob. 47QPCh. 20 - Prob. 48QPCh. 20 - Prob. 49QPCh. 20 - Prob. 50QPCh. 20 - Prob. 51QPCh. 20 - Prob. 52QPCh. 20 - Prob. 53QPCh. 20 - Prob. 54QPCh. 20 - Prob. 55QPCh. 20 - Prob. 56QPCh. 20 - Prob. 57QPCh. 20 - Prob. 58QPCh. 20 - Prob. 59QPCh. 20 - Prob. 60QPCh. 20 - Prob. 61QPCh. 20 - Prob. 62APCh. 20 - Prob. 63APCh. 20 - Prob. 64APCh. 20 - Prob. 65APCh. 20 - Prob. 66APCh. 20 - Prob. 67APCh. 20 - Prob. 68APCh. 20 - Prob. 69APCh. 20 - Prob. 70APCh. 20 - Prob. 71APCh. 20 - Prob. 72APCh. 20 - Prob. 73APCh. 20 - Prob. 74APCh. 20 - Prob. 75APCh. 20 - Prob. 76APCh. 20 - Prob. 77APCh. 20 - Prob. 78APCh. 20 - Prob. 79APCh. 20 - Prob. 80APCh. 20 - Prob. 81APCh. 20 - Prob. 82APCh. 20 - Prob. 83APCh. 20 - Prob. 84APCh. 20 - Prob. 85APCh. 20 - Prob. 86APCh. 20 - Prob. 87APCh. 20 - Prob. 88APCh. 20 - Prob. 89APCh. 20 - Prob. 90APCh. 20 - Prob. 91APCh. 20 - Prob. 92APCh. 20 - Prob. 93APCh. 20 - Prob. 94APCh. 20 - Prob. 95APCh. 20 - Prob. 96APCh. 20 - Prob. 97APCh. 20 - Prob. 98APCh. 20 - Prob. 99APCh. 20 - Prob. 100APCh. 20 - Prob. 101APCh. 20 - Prob. 102APCh. 20 - Prob. 103APCh. 20 - Prob. 1SEPPCh. 20 - Prob. 2SEPPCh. 20 - Prob. 3SEPPCh. 20 - Prob. 4SEPP
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Text book image
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Text book image
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning