All the geometrical isomers of Pt(CN) 2 Br 2 ( H 2 O ) 2 are to be drawn. The optical isomer is to be identified from these isomers. The structure of this optical isomer is to be drawn. Concept introduction: In geometrical isomerism, atoms or group of atoms are arranged at different positions around a bond. The following are the conditions for the optically active compounds, The compound should not have plane symmetry. The compound should not have center of symmetry. The mirror image of the compound should be non-superimposable. To determine: All the geometrical isomers of Pt(CN) 2 Br 2 ( H 2 O ) 2 ; the optical isomer from these isomers; the structure of this optical isomer.

Question

Want to see the full answer?

Answer 1

Question

Chapter 20, Problem 48E

Interpretation Introduction

Interpretation: All the geometrical isomers of Pt(CN)2Br2(H2O)2 are to be drawn. The optical isomer is to be identified from these isomers. The structure of this optical isomer is to be drawn.

Concept introduction: In geometrical isomerism, atoms or group of atoms are arranged at different positions around a bond. The following are the conditions for the optically active compounds,

The compound should not have plane symmetry.

The compound should not have center of symmetry.

The mirror image of the compound should be non-superimposable.

To determine: All the geometrical isomers of Pt(CN)2Br2(H2O)2 ; the optical isomer from these isomers; the structure of this optical isomer.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Using the conditions of spontaneity to deduce the signs of AH and AS Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option. reaction observations conclusions A This reaction is always spontaneous, but proceeds slower at temperatures above 120. °C. ΔΗ is (pick one) AS is (pick one) ΔΗ is (pick one) B This reaction is spontaneous except above 117. °C. AS is (pick one) ΔΗ is (pick one) This reaction is slower below 20. °C than C above. AS is |(pick one) ? 18 Ar 1

Calculating the pH at equivalence of a titration Try Again Your answer is incorrect. 0/5 a A chemist titrates 70.0 mL of a 0.7089 M hydrocyanic acid (HCN) solution with 0.4574M KOH solution at 25 °C. Calculate the pH at equivalence. The pK of hydrocyanic acid is 9.21. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of KOH solution added. pH = 11.43] G 00. 18 Ar B•

Biological Macromolecules Naming and drawing the products of aldose oxidation and reduction aw a Fischer projection of the molecule that would produce L-ribonic acid if it were subjected to mildly oxidizing reaction conditions. Click and drag to start drawing a structure. X AP ‡ 1/5 Naor Explanation Check McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center Accessibil