
Concept explainers
(a)
Interpretation: The name of the given structures of complex ion is to be stated.
Concept introduction: Rules followed in the naming of coordination compound:
- In naming of coordination compound, the name of anion (ligand) comes first. Metal ion is named second, which is the name of element.
- An ‘o’ is added to the root name of anion.
- Greek prefix is used to express the number of ligands.
- Roman numeral is used to denote the oxidation state of metal ion.
- In case of more than one type of ligand present in a compound, they are named alphabetically.
- The suffix ‘-ate’ is added to metal ion if complex ion contains negative charge. Latin names are also used to identify the name of metals.
To determine: The name of the given structure of complex ion.
(b)
Interpretation: The name of the given structures of complex ion is to be stated.
Concept introduction: Rules followed in the naming of coordination compound:
- In naming of coordination compound, the name of anion (ligand) comes first. Metal ion is named second, which is the name of element.
- An ‘o’ is added to the root name of anion.
- Greek prefix is used to express the number of ligands.
- Roman numeral is used to denote the oxidation state of metal ion.
- In case of more than one type of ligand present in a compound, they are named alphabetically.
- The suffix ‘-ate’ is added to metal ion if complex ion contains negative charge. Latin names are also used to identify the name of metals.
To determine: The name of the given structure of complex ion.
(c)
Interpretation: The name of the given structures of complex ion is to be stated.
Concept introduction: Rules followed in the naming of coordination compound:
- In naming of coordination compound, the name of anion (ligand) comes first. Metal ion is named second, which is the name of element.
- An ‘o’ is added to the root name of anion.
- Greek prefix is used to express the number of ligands.
- Roman numeral is used to denote the oxidation state of metal ion.
- In case of more than one type of ligand present in a compound, they are named alphabetically.
- The suffix ‘-ate’ is added to metal ion if complex ion contains negative charge. Latin names are also used to identify the name of metals.
To determine: The name of the given structure of complex ion.
The name of complex ion

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Chapter 20 Solutions
EBK CHEMISTRY: AN ATOMS FIRST APPROACH
- Potassium (K) blends with germanium (Ge) to form a Zintl phase with a chemical formula of K4Ge4. Which of the following elements would you expect potassium to blend with to form an alloy? Electronegativities: As (2.0), Cl (3.0), Ge (1.8), K (0.8), S (2.5), Ti (1.5) Group of answer choices Arsenic (As) Sulfur (S) Chlorine (Cl) Titanium (Ti)arrow_forwardConsider two elements, X and Z. Both have cubic-based unit cells with the same edge lengths. X has a bcc unit cell while Z has a fcc unit cell. Which of the following statements is TRUE? Group of answer choices Z has a larger density than X X has more particles in its unit cell than Z does X has a larger density than Z Z has a larger unit cell volume than Xarrow_forwardHow many particles does a face-centered cubic (fcc) unit cell contain? Group of answer choices 2 14 8 4arrow_forward
- V Highlight all of the carbon atoms that have at least one beta (B) hydrogen, using red for one ẞ hydrogen, blue for two ẞ hydrogens, and green for three ẞ hydrogens. If none of the carbon atoms have ẞ hydrogens, check the box underneath the molecule. ED X None of the carbon atoms have ẞ hydrogens. Explanation esc 2 Check * F1 F2 1 2 80 # 3 Q W tab A caps lock shift fn control F3 N S option O 694 $ F4 F5 F6 005 % E R D F LL 6 olo 18 Ar B © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility A DII F7 F8 87 & * 8 T Y U G H 4 F9 F10 ( 9 0 E F11 F12 உ J K L + || X C V B N M H H command option commandarrow_forwardConsider the reaction below and answer the following questions. Part 1 of 4 Br NaOCH2CH3 Identify the mechanisms involved. Check all that apply. SN 1 SN 2 E1 E2 None of the above Part 2 of 4 Skip Part Check esc F1 F2 lock 1 2 Q W A S #3 80 F3 F4 F5 F6 Save For © 2025 McGraw Hill LLC. All Rights Reserved. Terms ˇˇ % & 4 5 6 89 7 IK A 分 བ F7 F8 F9 F * E R T Y U 8 9 D F G H K V B N M 0 Oarrow_forwardWhat kind of holes are not generated when solid-state particles adopt a close packing pattern? Group of answer choices tetrahedral cubic octahedral None of the other choices are correctarrow_forward
- For the reaction below: 1. Draw all reasonable elimination products to the right of the arrow. 2. In the box below the reaction, redraw any product you expect to be a major product. 田 Major Product: Check ☐ + I Na OH esc F1 F2 2 1 @ 2 Q W tab A caps lock S #3 80 F3 69 4 σ F4 % 95 S Click and drag to sta drawing a structure mm Save For Later 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use GO DII F5 F6 F7 F8 F9 F10 6 CO 89 & 7 LU E R T Y U 8* 9 0 D F G H J K L Z X C V B N M 36arrow_forwardProblem 7 of 10 Draw the major product of this reaction. Ignore inorganic byproducts. S' S 1. BuLi 2. ethylene oxide (C2H4O) Select to Draw a Submitarrow_forwardFeedback (4/10) 30% Retry Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the reactant and missing intermediates involved in this reaction. Include all lone pairs and charges as appropriate. Ignore inorganic byproducts. Incorrect, 6 attempts remaining :0: Draw the Reactant H H3CO H- HIO: Ö-CH3 CH3OH2* protonation H. a H (+) H Ο CH3OH2 O: H3C protonation CH3OH deprotonation > CH3OH nucleophilic addition H. HO 0:0 Draw Intermediate a Xarrow_forward
- Can I please get the blank spaces answered/answers?arrow_forward1. Identify the following alkenes as E or Z NH₂ Br 2. Draw the structures based on the IUPAC names (3R,4R)-3-bromo-4-fluoro- 1-hexene (Z)-4-bromo-2-iodo-3-ethyl- 3-heptene تر 3. For the following, predict all possible elimination product(s) and circle the major product. HO H₂SO4 Heat 80 F4 OH H2SO4 Heat 어요 F5 F6 1 A DII 4 F7 F8 F9 % & 5 6 7 * ∞ 8 BAB 3 E R T Y U 9 F D G H J K O A F11 F10arrow_forwardDraw the major product of this reaction. Ignore inorganic byproducts. ○ O 1. H₂O, pyridine 2. neutralizing work-up a N W X 人 Parrow_forward
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