The optically active compound between c i s − Cr ( acac ) 2 ( H 2 O ) 2 , t r a n s − Cr ( acac ) 2 ( H 2 O ) 2 and Cr ( acac ) 3 is to be identified. Concept introduction: The following are the conditions for the optically active compounds, The compound should not have plane symmetry. The compound should not have center of symmetry. The mirror image of the compound should be non-superimposable. If plane passes through the molecule and the molecule is divided into two equal halves, then the molecule is said to have plane symmetry. Normally, trans complex compounds show plane of symmetry. A point is said to be the center of symmetry, if same molecules are present in the opposite direction to each other. A molecule is said to be non-superimposable, if its mirror image does not overlap each other completely. To determine: The optically active compound between c i s − Cr ( acac ) 2 ( H 2 O ) 2 , t r a n s − Cr ( acac ) 2 ( H 2 O ) 2 and Cr ( acac ) 3 .

Question

Identifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. acids: 0.2 mol of KOH is added to 1.0 L of a 0.5 M HF solution. bases: Х other: ☐ acids: 0.10 mol of HI is added to 1.0 L of a solution that is 1.4M in both HF and NaF. bases: other: ☐ 0,0,... ด ? 18 Ar

Answer 1

Question

Chapter 20, Problem 47E

Interpretation Introduction

Interpretation: The optically active compound between cis−Cr(acac)2(H2O)2 , trans−Cr(acac)2(H2O)2 and Cr(acac)3 is to be identified.

Concept introduction: The following are the conditions for the optically active compounds,

The compound should not have plane symmetry.

The compound should not have center of symmetry.

The mirror image of the compound should be non-superimposable.

If plane passes through the molecule and the molecule is divided into two equal halves, then the molecule is said to have plane symmetry. Normally, trans complex compounds show plane of symmetry.

A point is said to be the center of symmetry, if same molecules are present in the opposite direction to each other.

A molecule is said to be non-superimposable, if its mirror image does not overlap each other completely.

To determine: The optically active compound between cis−Cr(acac)2(H2O)2 , trans−Cr(acac)2(H2O)2 and Cr(acac)3 .

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