The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted. Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t 2g orbitals and higher energy orbitals. Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t 2g orbitals. To determine: The error in the given statement “ CoCl 4 2 − is an example of a strong-field case having two unpaired electrons.”

Question

Want to see the full answer?

Answer 1

Question

Chapter 20, Problem 11Q

(a)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “ CoCl42− is an example of a strong-field case having two unpaired electrons.”

(b)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “Because CN− is a weak-field ligand, Co(CN)63− will be a low-spin case having four unpaired electrons.”

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. ? Will the first MgBr product that forms in this reaction create a new CC bond? olo ? OH جمله O Yes Ⓒ No MgCl ? Will the first product that forms in this reaction create a new CC bond? Click and drag to start drawing a structure. Yes No X ☐ : ☐ टे PH

Assign all the protons

PROPOSE REACTION MECHANISM FOR ACID-CATALYZED REACTION OF 3-PENTANONE WITH DIMETHYLAMINE

Answer 2

Question

Chapter 20, Problem 11Q

(a)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “ CoCl42− is an example of a strong-field case having two unpaired electrons.”

(b)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “Because CN− is a weak-field ligand, Co(CN)63− will be a low-spin case having four unpaired electrons.”

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 20, Problem 11Q

(a)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “ CoCl42− is an example of a strong-field case having two unpaired electrons.”

(b)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “Because CN− is a weak-field ligand, Co(CN)63− will be a low-spin case having four unpaired electrons.”

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 20, Problem 11Q

(a)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “ CoCl42− is an example of a strong-field case having two unpaired electrons.”

(b)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “Because CN− is a weak-field ligand, Co(CN)63− will be a low-spin case having four unpaired electrons.”

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 20, Problem 11Q

(a)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “ CoCl42− is an example of a strong-field case having two unpaired electrons.”

(b)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “Because CN− is a weak-field ligand, Co(CN)63− will be a low-spin case having four unpaired electrons.”

Answer 6

Chapter 20, Problem 11Q

(a)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “ CoCl42− is an example of a strong-field case having two unpaired electrons.”

Answer 7

Chapter 20, Problem 11Q

(a)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “ CoCl42− is an example of a strong-field case having two unpaired electrons.”

Answer 8

(b)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “Because CN− is a weak-field ligand, Co(CN)63− will be a low-spin case having four unpaired electrons.”

Answer 9

(b)

Interpretation Introduction

Interpretation: The error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept introduction: Weak field ligand that has small crystal field splitting energy gives high spin due to presence of maximum unpaired electrons in lower energy t2g orbitals and higher energy orbitals.

Strong field ligand that has large crystal field splitting energy gives low spin due to presence of maximum paired electrons in lower energy t2g orbitals.

To determine: The error in the given statement “Because CN− is a weak-field ligand, Co(CN)63− will be a low-spin case having four unpaired electrons.”

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 13

Ch. 20 - What two first-row transition metals have...Ch. 20 - Prob. 2RQ Ch. 20 - Prob. 3RQ Ch. 20 - Prob. 4RQ Ch. 20 - Prob. 5RQ Ch. 20 - Prob. 6RQ Ch. 20 - Prob. 7RQ Ch. 20 - Prob. 8RQ Ch. 20 - Prob. 9RQ Ch. 20 - Prob. 10RQ

Solution Summary: The author explains the error in the given statements concerning each complex ion and the d orbital splitting diagrams is to be predicted.

Concept explainers

Want to see the full answer?

Chapter 20 Solutions