EBK MATHEMATICS FOR MACHINE TECHNOLOGY
EBK MATHEMATICS FOR MACHINE TECHNOLOGY
8th Edition
ISBN: 9781337798396
Author: SMITH
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Chapter 20, Problem 44A
To determine

(a)

Length of pin extension in (a).

Expert Solution
Check Mark

Answer to Problem 44A

Length of pin extension is 9.925mm.

Explanation of Solution

Given:

The number of times the pin extension is 1.25 and diameter of the pin is 7.94mm.

Concept used:

Relation between number of times pin extension is given as follows:

  N=LD ........ (1)

Here, number of times pin extension is N, length of the pin extension is L and diameter of the pin is D.

Calculation:

Substitute 1.25 for N and 7.94mm for D in equation (1).

  1.25=L7.94L=9.925mm

Thus, Length of pin extension is 9.925mm.

Conclusion:

Length of pin extension is 9.925mm.

To determine

(b)

Length of pin extension in (b).

Expert Solution
Check Mark

Answer to Problem 44A

Length of pin extension is 58.

Explanation of Solution

Given:

The number of times the pin extension is 114 and diameter of the pin is 12.

Calculation:

Substitute 114 for N and 12 for D in equation (1).

  114=L 1 2 L=54×12L=58

Thus, Length of pin extension is 58.

Conclusion:

Length of pin extension is 58.

To determine

(c)

Diameter of the pin in (c).

Expert Solution
Check Mark

Answer to Problem 44A

Diameter of the pin is 35.

Explanation of Solution

Given:

The number of times the pin extension is 114 and length of the pin is 34.

Calculation:

Substitute 114 for N and 34 for L in equation (1).

  114= 3 4 DD= 3 4 54D=35

Thus, Diameter of the pin is 35.

Conclusion:

Diameter of the pin is 35.

To determine

(d)

Diameter of the pin in (d).

Expert Solution
Check Mark

Answer to Problem 44A

Diameter of the pin is 6.349mm.

Explanation of Solution

Given:

The number of times the pin extension is 1.375 and length of the pin is 8.73mm.

Calculation:

Substitute 1.375 for N and 8.73mm for L in equation (1).

  1.375=8.73DD=8.731.375D=6.349mm

Thus, Diameter of the pin is 6.349mm.

Conclusion:

Diameter of the pin is 6.349mm.

To determine

(e)

Length of pin extension in (e).

Expert Solution
Check Mark

Answer to Problem 44A

Length of pin extension is 20.15mm.

Explanation of Solution

Given:

The number of times the pin extension is 1.25 and diameter of the pin is 16.12mm.

Concept used:

Relation between number of times pin extension is given as follows:

  N=LD ........ (1)

Here, number of times pin extension is N, length of the pin extension is L and diameter of the pin is D.

Calculation:

Substitute 1.25 for N and 16.12mm for D in equation (1).

  1.25=L16.12L=20.15mm

Thus, Length of pin extension is 20.15mm.

Conclusion:

Length of pin extension is 20.15mm.

To determine

(f)

Diameter of the pin in (f).

Expert Solution
Check Mark

Answer to Problem 44A

Diameter of the pin is 0.75054.

Explanation of Solution

Given:

The number of times the pin extension is 1.375 and length of the pin is 1.032.

Calculation:

Substitute 1.375 for N and 1.032 for L in equation (1).

  1.375=1.032DD=1.0321.375D=0.75054

Thus, Diameter of the pin is 0.75054.

Conclusion:

Diameter of the pin is 0.75054.

To determine

(g)

Length of pin extension in (g).

Expert Solution
Check Mark

Answer to Problem 44A

Length of pin extension is 1.09375.

Explanation of Solution

Given:

The number of times the pin extension is 1.25 and diameter of the pin is 0.875.

Concept used:

Relation between number of times pin extension is given as follows:

  N=LD ........ (1)

Here, number of times pin extension is N, length of the pin extension is L and diameter of the pin is D.

Calculation:

Substitute 1.25 for N and 0.875 for D in equation (1).

  1.25=L0.875L=1.09375

Thus, Length of pin extension is 1.09375.

Conclusion:

Length of pin extension is 1.09375.

To determine

(h)

Length of pin extension in (h).

Expert Solution
Check Mark

Answer to Problem 44A

Length of pin extension is 5.52mm.

Explanation of Solution

Given:

The number of times the pin extension is 1.5 and diameter of the pin is 3.68mm.

Concept used:

Relation between number of times pin extension is given as follows:

  N=LD ........ (1)

Here, number of times pin extension is N, length of the pin extension is L and diameter of the pin is D.

Calculation:

Substitute 1.5 for N and 3.68mm for D in equation (1).

  1.5=L3.68L=5.52mm

Thus, Length of pin extension is 5.52mm.

Conclusion:

Length of pin extension is 5.52mm.

To determine

(i)

Diameter of the pin in (i).

Expert Solution
Check Mark

Answer to Problem 44A

Diameter of the pin is 0.2497.

Explanation of Solution

Given:

The number of times the pin extension is 1.125 and length of the pin is 0.281.

Calculation:

Substitute 1.125 for N and 0.281 for L in equation (1).

  1.125=0.281DD=0.2811.125D=0.2497

Thus, Diameter of the pin is 0.2497.

Conclusion:

Diameter of the pin is 0.2497.

To determine

(j)

Length of pin extension in (j).

Expert Solution
Check Mark

Answer to Problem 44A

Length of pin extension is 7.5mm.

Explanation of Solution

Given:

The number of times the pin extension is 1.0 and diameter of the pin is 7.5mm.

Concept used:

Relation between number of times pin extension is given as follows:

  N=LD ........ (1)

Here, number of times pin extension is N, length of the pin extension is L and diameter of the pin is D.

Calculation:

Substitute 1.0 for N and 7.5mm for D in equation (1).

  1.0=L7.5L=7.5mm

Thus, Length of pin extension is 7.5mm.

Conclusion:

Length of pin extension is 7.5mm.

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Chapter 20 Solutions

EBK MATHEMATICS FOR MACHINE TECHNOLOGY

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