(a) The ratios E F , E G , E H , F G , F H , G H , G E and H F in the lowest form for first condition.

Question

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Answer 1

Question

Chapter 20, Problem 18A

To determine

(a)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for first condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 1

Calculation:

Divide E by F to get the ratio EF as follows:

EF=8÷6EF=86EF=43

Divide E by G to get the ratio EG as follows:

EG=8÷4EG=84EG=21

Divide E by H to get the ratio EH as follows:

EH=8÷3EH=83

Divide F by G to get the ratio FG as follows:

FG=6÷4FG=64FG=32

Divide F by H to get the ratio FH as follows:

FH=6÷3FH=63FH=21

Divide G by H to get the ratio GH as follows:

GH=4÷3GH=43

Divide G by E to get the ratio GE as follows:

GE=4÷8GE=48GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷6HF=36HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

To determine

(b)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for second condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 2

Calculation:

Divide E by F to get the ratio EF as follows:

EF=10÷8EF=108EF=54

Divide E by G to get the ratio EG as follows:

EG=10÷5EG=105EG=21

Divide E by H to get the ratio EH as follows:

EH=10÷4EH=104EH=52

Divide F by G to get the ratio FG as follows:

FG=8÷5FG=85

Divide F by H to get the ratio FH as follows:

FH=8÷4FH=84FH=21

Divide G by H to get the ratio GH as follows:

GH=5÷4GH=54

Divide G by E to get the ratio GE as follows:

GE=5÷10GE=510GE=12

Divide H by F to get the ratio HF as follows:

HF=4÷8HF=48HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

To determine

(c)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for third condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 3

Calculation:

Divide E by F to get the ratio EF as follows:

EF=12÷9EF=129EF=43

Divide E by G to get the ratio EG as follows:

EG=12÷6EG=126EG=21

Divide E by H to get the ratio EH as follows:

EH=12÷3EH=123EH=41

Divide F by G to get the ratio FG as follows:

FG=9÷6FG=96FG=32

Divide F by H to get the ratio FH as follows:

FH=9÷3FH=93FH=31

Divide G by H to get the ratio GH as follows:

GH=6÷3GH=63GH=21

Divide G by E to get the ratio GE as follows:

GE=6÷12GE=612GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷9HF=39HF=13

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

To determine

(d)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for fourth condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 4

Calculation:

Divide E by F to get the ratio EF as follows:

EF=15÷12EF=1512EF=54

Divide E by G to get the ratio EG as follows:

EG=15÷10EG=1510EG=32

Divide E by H to get the ratio EH as follows:

EH=15÷6EH=156EH=52

Divide F by G to get the ratio FG as follows:

FG=12÷10FG=1210FG=65

Divide F by H to get the ratio FH as follows:

FH=12÷6FH=126FH=21

Divide G by H to get the ratio GH as follows:

GH=10÷6GH=106GH=53

Divide G by E to get the ratio GE as follows:

GE=10÷15GE=1015GE=23

Divide H by F to get the ratio HF as follows:

HF=6÷12HF=612HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

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Answer 2

Question

Chapter 20, Problem 18A

To determine

(a)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for first condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 1

Calculation:

Divide E by F to get the ratio EF as follows:

EF=8÷6EF=86EF=43

Divide E by G to get the ratio EG as follows:

EG=8÷4EG=84EG=21

Divide E by H to get the ratio EH as follows:

EH=8÷3EH=83

Divide F by G to get the ratio FG as follows:

FG=6÷4FG=64FG=32

Divide F by H to get the ratio FH as follows:

FH=6÷3FH=63FH=21

Divide G by H to get the ratio GH as follows:

GH=4÷3GH=43

Divide G by E to get the ratio GE as follows:

GE=4÷8GE=48GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷6HF=36HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

To determine

(b)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for second condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 2

Calculation:

Divide E by F to get the ratio EF as follows:

EF=10÷8EF=108EF=54

Divide E by G to get the ratio EG as follows:

EG=10÷5EG=105EG=21

Divide E by H to get the ratio EH as follows:

EH=10÷4EH=104EH=52

Divide F by G to get the ratio FG as follows:

FG=8÷5FG=85

Divide F by H to get the ratio FH as follows:

FH=8÷4FH=84FH=21

Divide G by H to get the ratio GH as follows:

GH=5÷4GH=54

Divide G by E to get the ratio GE as follows:

GE=5÷10GE=510GE=12

Divide H by F to get the ratio HF as follows:

HF=4÷8HF=48HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

To determine

(c)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for third condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 3

Calculation:

Divide E by F to get the ratio EF as follows:

EF=12÷9EF=129EF=43

Divide E by G to get the ratio EG as follows:

EG=12÷6EG=126EG=21

Divide E by H to get the ratio EH as follows:

EH=12÷3EH=123EH=41

Divide F by G to get the ratio FG as follows:

FG=9÷6FG=96FG=32

Divide F by H to get the ratio FH as follows:

FH=9÷3FH=93FH=31

Divide G by H to get the ratio GH as follows:

GH=6÷3GH=63GH=21

Divide G by E to get the ratio GE as follows:

GE=6÷12GE=612GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷9HF=39HF=13

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

To determine

(d)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for fourth condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 4

Calculation:

Divide E by F to get the ratio EF as follows:

EF=15÷12EF=1512EF=54

Divide E by G to get the ratio EG as follows:

EG=15÷10EG=1510EG=32

Divide E by H to get the ratio EH as follows:

EH=15÷6EH=156EH=52

Divide F by G to get the ratio FG as follows:

FG=12÷10FG=1210FG=65

Divide F by H to get the ratio FH as follows:

FH=12÷6FH=126FH=21

Divide G by H to get the ratio GH as follows:

GH=10÷6GH=106GH=53

Divide G by E to get the ratio GE as follows:

GE=10÷15GE=1015GE=23

Divide H by F to get the ratio HF as follows:

HF=6÷12HF=612HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

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Answer 3

Question

Chapter 20, Problem 18A

To determine

(a)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for first condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 1

Calculation:

Divide E by F to get the ratio EF as follows:

EF=8÷6EF=86EF=43

Divide E by G to get the ratio EG as follows:

EG=8÷4EG=84EG=21

Divide E by H to get the ratio EH as follows:

EH=8÷3EH=83

Divide F by G to get the ratio FG as follows:

FG=6÷4FG=64FG=32

Divide F by H to get the ratio FH as follows:

FH=6÷3FH=63FH=21

Divide G by H to get the ratio GH as follows:

GH=4÷3GH=43

Divide G by E to get the ratio GE as follows:

GE=4÷8GE=48GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷6HF=36HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

To determine

(b)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for second condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 2

Calculation:

Divide E by F to get the ratio EF as follows:

EF=10÷8EF=108EF=54

Divide E by G to get the ratio EG as follows:

EG=10÷5EG=105EG=21

Divide E by H to get the ratio EH as follows:

EH=10÷4EH=104EH=52

Divide F by G to get the ratio FG as follows:

FG=8÷5FG=85

Divide F by H to get the ratio FH as follows:

FH=8÷4FH=84FH=21

Divide G by H to get the ratio GH as follows:

GH=5÷4GH=54

Divide G by E to get the ratio GE as follows:

GE=5÷10GE=510GE=12

Divide H by F to get the ratio HF as follows:

HF=4÷8HF=48HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

To determine

(c)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for third condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 3

Calculation:

Divide E by F to get the ratio EF as follows:

EF=12÷9EF=129EF=43

Divide E by G to get the ratio EG as follows:

EG=12÷6EG=126EG=21

Divide E by H to get the ratio EH as follows:

EH=12÷3EH=123EH=41

Divide F by G to get the ratio FG as follows:

FG=9÷6FG=96FG=32

Divide F by H to get the ratio FH as follows:

FH=9÷3FH=93FH=31

Divide G by H to get the ratio GH as follows:

GH=6÷3GH=63GH=21

Divide G by E to get the ratio GE as follows:

GE=6÷12GE=612GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷9HF=39HF=13

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

To determine

(d)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for fourth condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 4

Calculation:

Divide E by F to get the ratio EF as follows:

EF=15÷12EF=1512EF=54

Divide E by G to get the ratio EG as follows:

EG=15÷10EG=1510EG=32

Divide E by H to get the ratio EH as follows:

EH=15÷6EH=156EH=52

Divide F by G to get the ratio FG as follows:

FG=12÷10FG=1210FG=65

Divide F by H to get the ratio FH as follows:

FH=12÷6FH=126FH=21

Divide G by H to get the ratio GH as follows:

GH=10÷6GH=106GH=53

Divide G by E to get the ratio GE as follows:

GE=10÷15GE=1015GE=23

Divide H by F to get the ratio HF as follows:

HF=6÷12HF=612HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

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Answer 4

Question

Chapter 20, Problem 18A

To determine

(a)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for first condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 1

Calculation:

Divide E by F to get the ratio EF as follows:

EF=8÷6EF=86EF=43

Divide E by G to get the ratio EG as follows:

EG=8÷4EG=84EG=21

Divide E by H to get the ratio EH as follows:

EH=8÷3EH=83

Divide F by G to get the ratio FG as follows:

FG=6÷4FG=64FG=32

Divide F by H to get the ratio FH as follows:

FH=6÷3FH=63FH=21

Divide G by H to get the ratio GH as follows:

GH=4÷3GH=43

Divide G by E to get the ratio GE as follows:

GE=4÷8GE=48GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷6HF=36HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

To determine

(b)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for second condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 2

Calculation:

Divide E by F to get the ratio EF as follows:

EF=10÷8EF=108EF=54

Divide E by G to get the ratio EG as follows:

EG=10÷5EG=105EG=21

Divide E by H to get the ratio EH as follows:

EH=10÷4EH=104EH=52

Divide F by G to get the ratio FG as follows:

FG=8÷5FG=85

Divide F by H to get the ratio FH as follows:

FH=8÷4FH=84FH=21

Divide G by H to get the ratio GH as follows:

GH=5÷4GH=54

Divide G by E to get the ratio GE as follows:

GE=5÷10GE=510GE=12

Divide H by F to get the ratio HF as follows:

HF=4÷8HF=48HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

To determine

(c)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for third condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 3

Calculation:

Divide E by F to get the ratio EF as follows:

EF=12÷9EF=129EF=43

Divide E by G to get the ratio EG as follows:

EG=12÷6EG=126EG=21

Divide E by H to get the ratio EH as follows:

EH=12÷3EH=123EH=41

Divide F by G to get the ratio FG as follows:

FG=9÷6FG=96FG=32

Divide F by H to get the ratio FH as follows:

FH=9÷3FH=93FH=31

Divide G by H to get the ratio GH as follows:

GH=6÷3GH=63GH=21

Divide G by E to get the ratio GE as follows:

GE=6÷12GE=612GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷9HF=39HF=13

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

To determine

(d)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for fourth condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 4

Calculation:

Divide E by F to get the ratio EF as follows:

EF=15÷12EF=1512EF=54

Divide E by G to get the ratio EG as follows:

EG=15÷10EG=1510EG=32

Divide E by H to get the ratio EH as follows:

EH=15÷6EH=156EH=52

Divide F by G to get the ratio FG as follows:

FG=12÷10FG=1210FG=65

Divide F by H to get the ratio FH as follows:

FH=12÷6FH=126FH=21

Divide G by H to get the ratio GH as follows:

GH=10÷6GH=106GH=53

Divide G by E to get the ratio GE as follows:

GE=10÷15GE=1015GE=23

Divide H by F to get the ratio HF as follows:

HF=6÷12HF=612HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

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Answer 5

Chapter 20, Problem 18A

To determine

(a)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for first condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 1

Calculation:

Divide E by F to get the ratio EF as follows:

EF=8÷6EF=86EF=43

Divide E by G to get the ratio EG as follows:

EG=8÷4EG=84EG=21

Divide E by H to get the ratio EH as follows:

EH=8÷3EH=83

Divide F by G to get the ratio FG as follows:

FG=6÷4FG=64FG=32

Divide F by H to get the ratio FH as follows:

FH=6÷3FH=63FH=21

Divide G by H to get the ratio GH as follows:

GH=4÷3GH=43

Divide G by E to get the ratio GE as follows:

GE=4÷8GE=48GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷6HF=36HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

To determine

(b)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for second condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 2

Calculation:

Divide E by F to get the ratio EF as follows:

EF=10÷8EF=108EF=54

Divide E by G to get the ratio EG as follows:

EG=10÷5EG=105EG=21

Divide E by H to get the ratio EH as follows:

EH=10÷4EH=104EH=52

Divide F by G to get the ratio FG as follows:

FG=8÷5FG=85

Divide F by H to get the ratio FH as follows:

FH=8÷4FH=84FH=21

Divide G by H to get the ratio GH as follows:

GH=5÷4GH=54

Divide G by E to get the ratio GE as follows:

GE=5÷10GE=510GE=12

Divide H by F to get the ratio HF as follows:

HF=4÷8HF=48HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

To determine

(c)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for third condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 3

Calculation:

Divide E by F to get the ratio EF as follows:

EF=12÷9EF=129EF=43

Divide E by G to get the ratio EG as follows:

EG=12÷6EG=126EG=21

Divide E by H to get the ratio EH as follows:

EH=12÷3EH=123EH=41

Divide F by G to get the ratio FG as follows:

FG=9÷6FG=96FG=32

Divide F by H to get the ratio FH as follows:

FH=9÷3FH=93FH=31

Divide G by H to get the ratio GH as follows:

GH=6÷3GH=63GH=21

Divide G by E to get the ratio GE as follows:

GE=6÷12GE=612GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷9HF=39HF=13

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

To determine

(d)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for fourth condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 4

Calculation:

Divide E by F to get the ratio EF as follows:

EF=15÷12EF=1512EF=54

Divide E by G to get the ratio EG as follows:

EG=15÷10EG=1510EG=32

Divide E by H to get the ratio EH as follows:

EH=15÷6EH=156EH=52

Divide F by G to get the ratio FG as follows:

FG=12÷10FG=1210FG=65

Divide F by H to get the ratio FH as follows:

FH=12÷6FH=126FH=21

Divide G by H to get the ratio GH as follows:

GH=10÷6GH=106GH=53

Divide G by E to get the ratio GE as follows:

GE=10÷15GE=1015GE=23

Divide H by F to get the ratio HF as follows:

HF=6÷12HF=612HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Answer 6

Chapter 20, Problem 18A

To determine

(a)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for first condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 1

Calculation:

Divide E by F to get the ratio EF as follows:

EF=8÷6EF=86EF=43

Divide E by G to get the ratio EG as follows:

EG=8÷4EG=84EG=21

Divide E by H to get the ratio EH as follows:

EH=8÷3EH=83

Divide F by G to get the ratio FG as follows:

FG=6÷4FG=64FG=32

Divide F by H to get the ratio FH as follows:

FH=6÷3FH=63FH=21

Divide G by H to get the ratio GH as follows:

GH=4÷3GH=43

Divide G by E to get the ratio GE as follows:

GE=4÷8GE=48GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷6HF=36HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Answer 7

Chapter 20, Problem 18A

To determine

(a)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for first condition.

Answer 8

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 1

Calculation:

Divide E by F to get the ratio EF as follows:

EF=8÷6EF=86EF=43

Divide E by G to get the ratio EG as follows:

EG=8÷4EG=84EG=21

Divide E by H to get the ratio EH as follows:

EH=8÷3EH=83

Divide F by G to get the ratio FG as follows:

FG=6÷4FG=64FG=32

Divide F by H to get the ratio FH as follows:

FH=6÷3FH=63FH=21

Divide G by H to get the ratio GH as follows:

GH=4÷3GH=43

Divide G by E to get the ratio GE as follows:

GE=4÷8GE=48GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷6HF=36HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,83,32,21,43,12and12 respectively.

Answer 13

To determine

(b)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for second condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 2

Calculation:

Divide E by F to get the ratio EF as follows:

EF=10÷8EF=108EF=54

Divide E by G to get the ratio EG as follows:

EG=10÷5EG=105EG=21

Divide E by H to get the ratio EH as follows:

EH=10÷4EH=104EH=52

Divide F by G to get the ratio FG as follows:

FG=8÷5FG=85

Divide F by H to get the ratio FH as follows:

FH=8÷4FH=84FH=21

Divide G by H to get the ratio GH as follows:

GH=5÷4GH=54

Divide G by E to get the ratio GE as follows:

GE=5÷10GE=510GE=12

Divide H by F to get the ratio HF as follows:

HF=4÷8HF=48HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Answer 14

To determine

(b)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for second condition.

Answer 15

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 2

Calculation:

Divide E by F to get the ratio EF as follows:

EF=10÷8EF=108EF=54

Divide E by G to get the ratio EG as follows:

EG=10÷5EG=105EG=21

Divide E by H to get the ratio EH as follows:

EH=10÷4EH=104EH=52

Divide F by G to get the ratio FG as follows:

FG=8÷5FG=85

Divide F by H to get the ratio FH as follows:

FH=8÷4FH=84FH=21

Divide G by H to get the ratio GH as follows:

GH=5÷4GH=54

Divide G by E to get the ratio GE as follows:

GE=5÷10GE=510GE=12

Divide H by F to get the ratio HF as follows:

HF=4÷8HF=48HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,21,52,85,21,54,12and12 respectively.

Answer 20

To determine

(c)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for third condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 3

Calculation:

Divide E by F to get the ratio EF as follows:

EF=12÷9EF=129EF=43

Divide E by G to get the ratio EG as follows:

EG=12÷6EG=126EG=21

Divide E by H to get the ratio EH as follows:

EH=12÷3EH=123EH=41

Divide F by G to get the ratio FG as follows:

FG=9÷6FG=96FG=32

Divide F by H to get the ratio FH as follows:

FH=9÷3FH=93FH=31

Divide G by H to get the ratio GH as follows:

GH=6÷3GH=63GH=21

Divide G by E to get the ratio GE as follows:

GE=6÷12GE=612GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷9HF=39HF=13

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Answer 21

To determine

(c)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for third condition.

Answer 22

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 3

Calculation:

Divide E by F to get the ratio EF as follows:

EF=12÷9EF=129EF=43

Divide E by G to get the ratio EG as follows:

EG=12÷6EG=126EG=21

Divide E by H to get the ratio EH as follows:

EH=12÷3EH=123EH=41

Divide F by G to get the ratio FG as follows:

FG=9÷6FG=96FG=32

Divide F by H to get the ratio FH as follows:

FH=9÷3FH=93FH=31

Divide G by H to get the ratio GH as follows:

GH=6÷3GH=63GH=21

Divide G by E to get the ratio GE as follows:

GE=6÷12GE=612GE=12

Divide H by F to get the ratio HF as follows:

HF=3÷9HF=39HF=13

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 43,21,41,32,31,21,12and13 respectively.

Answer 27

To determine

(d)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for fourth condition.

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 4

Calculation:

Divide E by F to get the ratio EF as follows:

EF=15÷12EF=1512EF=54

Divide E by G to get the ratio EG as follows:

EG=15÷10EG=1510EG=32

Divide E by H to get the ratio EH as follows:

EH=15÷6EH=156EH=52

Divide F by G to get the ratio FG as follows:

FG=12÷10FG=1210FG=65

Divide F by H to get the ratio FH as follows:

FH=12÷6FH=126FH=21

Divide G by H to get the ratio GH as follows:

GH=10÷6GH=106GH=53

Divide G by E to get the ratio GE as follows:

GE=10÷15GE=1015GE=23

Divide H by F to get the ratio HF as follows:

HF=6÷12HF=612HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Answer 28

To determine

(d)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for fourth condition.

Answer 29

Expert Solution

Answer to Problem 18A

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Answer 30

Expert Solution

Answer 31

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Given:

Diameters are given in the table below:

EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 18A , additional homework tip 4

Calculation:

Divide E by F to get the ratio EF as follows:

EF=15÷12EF=1512EF=54

Divide E by G to get the ratio EG as follows:

EG=15÷10EG=1510EG=32

Divide E by H to get the ratio EH as follows:

EH=15÷6EH=156EH=52

Divide F by G to get the ratio FG as follows:

FG=12÷10FG=1210FG=65

Divide F by H to get the ratio FH as follows:

FH=12÷6FH=126FH=21

Divide G by H to get the ratio GH as follows:

GH=10÷6GH=106GH=53

Divide G by E to get the ratio GE as follows:

GE=10÷15GE=1015GE=23

Divide H by F to get the ratio HF as follows:

HF=6÷12HF=612HF=12

Thus, the ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Conclusion:

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form are 54,32,52,65,21,53,23and12 respectively.

Answer 34

Ch. 20 - Use a decimal equivalents table to find the...Ch. 20 - Compute (27.52.5+4.36)21.75 . Express the result...Ch. 20 - A cylinder has a volume, V, of 32.85 mm3. Use the...Ch. 20 - The volume V of a cube is V=s3 , where s is the...Ch. 20 - Multiply 15.328.75 .Ch. 20 - Express the decimal fraction 0.4275 as a common...Ch. 20 - Prob. 7A Ch. 20 - Express the following ratios in lowest fractional...Ch. 20 - Prob. 9A Ch. 20 - Express the following ratios in lowest fractional...

(a) The ratios E F , E G , E H , F G , F H , G H , G E and H F in the lowest form for first condition.

Concept explainers

Videos

(a)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for first condition.

Answer to Problem 18A

Explanation of Solution

(b)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for second condition.

Answer to Problem 18A

Explanation of Solution

(c)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for third condition.

Answer to Problem 18A

Explanation of Solution

(d)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for fourth condition.

Answer to Problem 18A

Explanation of Solution

Want to see more full solutions like this?

Chapter 20 Solutions

(a) The ratios E F , E G , E H , F G , F H , G H , G E and H F in the lowest form for first condition.

Concept explainers

Videos

(a) The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for first condition.

Answer to Problem 18A

Explanation of Solution

(b) The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for second condition.

Answer to Problem 18A

Explanation of Solution

(c) The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for third condition.

Answer to Problem 18A

Explanation of Solution

(d) The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for fourth condition.

Answer to Problem 18A

Explanation of Solution

Want to see more full solutions like this?

Chapter 20 Solutions

(a)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for first condition.

(b)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for second condition.

(c)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for third condition.

(d)

The ratios EF,EG,EH,FG,FH,GH,GEandHF in the lowest form for fourth condition.