EBK MATHEMATICS FOR MACHINE TECHNOLOGY
EBK MATHEMATICS FOR MACHINE TECHNOLOGY
8th Edition
ISBN: 9781337798396
Author: SMITH
Publisher: CENGAGE LEARNING - CONSIGNMENT
Question
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Chapter 20, Problem 19A
To determine

(a)

The indicated ratios in lowest fractional form.

Expert Solution
Check Mark

Answer to Problem 19A

The ratio of dimension A to dimension B is 21.

Explanation of Solution

Given:

The given figure is as follows:

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 19A , additional homework tip  1

Concept used:

The dimension can be calculated by subtracting the distance of near hole from the one which is farther.

Calculation:

From the given figure, it is clear that the measure of dimension A is given by,

  A=6020A=40

The measure of dimension B is given by,

  B=8060B=20

The ratio of dimension A to dimension B is given by,

  AB=4020AB=21

Thus, the ratio is 21.

Conclusion:

The ratio of Dimension A to Dimension B is 21.

To determine

(b)

The indicated ratios in lowest fractional form.

Expert Solution
Check Mark

Answer to Problem 19A

The ratio of dimension A to dimension C is 21.

Explanation of Solution

Given:

The given figure is as follows:

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 19A , additional homework tip  2

Concept used:

The dimension can be calculated by subtracting the distance of near hole from the one which is farther.

Calculation:

From the given figure, it is clear that the measure of dimension A is given by,

  A=6020A=40

The measure of dimension C is given by,

  C=12060C=60

The ratio of dimension A to dimension C is given by,

  AC=4060AC=23

Thus, the ratio is 23.

Conclusion:

The ratio of Dimension A to Dimension C is 23.

To determine

(c)

The indicated ratios in lowest fractional form.

Expert Solution
Check Mark

Answer to Problem 19A

The ratio of dimension C to dimension D is 32.

Explanation of Solution

Given:

The given figure is as follows:

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 19A , additional homework tip  3

Concept used:

The dimension can be calculated by subtracting the distance of near hole from the one which is farther.

Calculation:

From the given figure, it is clear that the measure of dimension C is given by,

  C=12060C=60

The measure of dimension D is given by,

  D=160120D=40

The ratio of dimension C to dimension D is given by,

  CD=6040CD=32

Thus, the ratio is 32.

Conclusion:

The ratio of Dimension C to Dimension D is 32.

To determine

(d)

The indicated ratios in lowest fractional form.

Expert Solution
Check Mark

Answer to Problem 19A

The ratio of dimension C to dimension E is 35.

Explanation of Solution

Given:

The given figure is as follows:

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 19A , additional homework tip  4

Concept used:

The dimension can be calculated by subtracting the distance of near hole from the one which is farther.

Calculation:

From the given figure, it is clear that the measure of dimension C is given by,

  C=12060C=60

The measure of dimension E is given by,

  E=12020E=100

The ratio of dimension C to dimension E is given by,

  CE=60100CE=35

Thus, the ratio is 35.

Conclusion:

The ratio of Dimension C to Dimension E is 35.

To determine

(e)

The indicated ratios in lowest fractional form.

Expert Solution
Check Mark

Answer to Problem 19A

The ratio of dimension D to dimension F is 27.

Explanation of Solution

Given:

The given figure is as follows:

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 19A , additional homework tip  5

Concept used:

The dimension can be calculated by subtracting the distance of near hole from the one which is farther.

Calculation:

From the given figure, it is clear that the measure of dimension D is given by,

  D=160120D=40

The measure of dimension F is given by,

  F=16020F=140

The ratio of dimension D to dimension F is given by,

  DF=40140DF=27

Thus, the ratio is 27.

Conclusion:

The ratio of Dimension D to Dimension F is 27.

To determine

(f)

The indicated ratios in lowest fractional form.

Expert Solution
Check Mark

Answer to Problem 19A

The ratio of dimension F to dimension B is 71.

Explanation of Solution

Given:

The given figure is as follows:

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 19A , additional homework tip  6

Concept used:

The dimension can be calculated by subtracting the distance of near hole from the one which is farther.

Calculation:

From the given figure, it is clear that the measure of dimension F is given by,

  F=16020F=140

The measure of dimension B is given by,

  B=8060B=20

The ratio of dimension F to dimension B is given by,

  FB=14020FB=71

Thus, the ratio is 71.

Conclusion:

The ratio of Dimension F to Dimension B is 71.

To determine

(g)

The indicated ratios in lowest fractional form.

Expert Solution
Check Mark

Answer to Problem 19A

The ratio of dimension F to dimension C is 73.

Explanation of Solution

Given:

The given figure is as follows:

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 19A , additional homework tip  7

Concept used:

The dimension can be calculated by subtracting the distance of near hole from the one which is farther.

Calculation:

From the given figure, it is clear that the measure of dimension F is given by,

  F=16020F=140

The measure of dimension C is given by,

  C=12060C=60

The ratio of dimension F to dimension C is given by,

  FC=14060FC=73

Thus, the ratio is 73.

Conclusion:

The ratio of Dimension F to Dimension C is 73.

To determine

(h)

The indicated ratios in lowest fractional form.

Expert Solution
Check Mark

Answer to Problem 19A

The ratio of dimension E to dimension A is 52.

Explanation of Solution

Given:

The given figure is as follows:

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 19A , additional homework tip  8

Concept used:

The dimension can be calculated by subtracting the distance of nearer hole from the one which is farther.

Calculation:

From the given figure, it is clear that the measure of dimension E is given by,

  E=12020E=100

The measure of dimension A is given by,

  A=6020A=40

The ratio of dimension E to dimension A is given by,

  EA=10040EA=52

Thus, the ratio is 52.

Conclusion:

The ratio of Dimension E to Dimension A is 52.

To determine

(i)

The indicated ratios in lowest fractional form.

Expert Solution
Check Mark

Answer to Problem 19A

The ratio of dimension D to dimension B is 21.

Explanation of Solution

Given:

The given figure is as follows:

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 19A , additional homework tip  9

Concept used:

The dimension can be calculated by subtracting the distance the near hole from the one which is farther.

Calculation:

From the given figure, it is clear that the measure of dimension D is given by,

  D=160120D=40

The measure of dimension B is given by,

  B=8060B=20

The ratio of dimension D to dimension B is given by,

  DB=4020DB=21

Thus, the ratio is 21.

Conclusion:

The ratio of Dimension D to Dimension B is 21.

To determine

(j)

The indicated ratios in lowest fractional form.

Expert Solution
Check Mark

Answer to Problem 19A

The ratio of dimension C to dimension F is 37.

Explanation of Solution

Given:

The given figure is as follows:

  EBK MATHEMATICS FOR MACHINE TECHNOLOGY, Chapter 20, Problem 19A , additional homework tip  10

Concept used:

The dimension can be calculated by subtracting the distance of nearer hole from the one which is farther.

Calculation:

From the given figure, it is clear that the measure of dimension C is given by,

  C=12060C=60

The measure of dimension F is given by,

  F=16020F=140

The ratio of dimension C to dimension F is given by,

  CF=60140CF=37

Thus, the ratio is 37.

Conclusion:

The ratio of Dimension C to Dimension F is 37.

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