Chemistry: Atoms First V1
Chemistry: Atoms First V1
1st Edition
ISBN: 9781259383120
Author: Burdge
Publisher: McGraw Hill Custom
Question
Book Icon
Chapter 20, Problem 20.95QP

(a)

Interpretation Introduction

Interpretation: The radius (r) of a nucleus is directly proportional to the ( r3 ) of mass number (A) to be shown and the volume for U235 nucleus should be determined.

Concept Introduction:

  • Half-life period: The time required to reduce half of its original value.
  • This is denoted by: t1/2
  • This term is popularly use in nuclear chemistry, to describe the stability & instability of atoms or radioactive decay.
  • For determination of first order rate constant K in half –life period we use

    K=0.693t1/2 Equation.

  • The half-life in first order does not depend upon the initial concentration.

Formula:

The volume of a sphere is V=43πr3

Age calculation:

lnNtN0=-kt

Calculate the age and rate constant:

K=0.693t1/2

(b)

Interpretation Introduction

Interpretation: The radius (r) of a nucleus is directly proportional to the ( r3 ) of mass number (A) to be shown and the volume for U235 nucleus should be determined.

Concept Introduction:

  • Half-life period: The time required to reduce half of its original value.
  • This is denoted by: t1/2
  • This term is popularly use in nuclear chemistry, to describe the stability & instability of atoms or radioactive decay.
  • For determination of first order rate constant K in half –life period we use

    K=0.693t1/2 Equation.

  • The half-life in first order does not depend upon the initial concentration.

Formula:

The volume of a sphere is V=43πr3

Age calculation:

lnNtN0=-kt

Calculate the age and rate constant:

K=0.693t1/2

To determine: The calculated volume for the U235 nucleus by substituting the equation derived in step-1.

Blurred answer
Students have asked these similar questions
How many protons, neutrons,and electrons are there in an atom of (a) 10 5B, (b) 36Ar, (c) 8538Sr, and (d) carbon-11?
The isotope of plutonium used for nuclear fission is 239Pu.Determine (a) the ratio of the number of neutrons in a239Pu nucleus to the number of protons, and (b) the number of electrons in a single plutonium atom.
Consider the nuclide cobalt-59 (5927Co). (a) The mass of 5927Co in atomic mass units is 58.933200 u. (Note this is the mass of the entire atom, not just the nucleus.) This mass is lower than the total mass of its constituent protons, neutrons, and electrons. Find the difference, in atomic mass units, between the total mass of the constituent particles, and the actual mass of the nuclide. (This is sometimes called the "mass defect.") The mass of a proton is 1.007276 u, the mass of a neutron is 1.008665 u, and the mass of an electron is 5.486 ✕ 10−4 u. (Round your answer to at least four decimal places.)   b) Since, according to special relativity theory, mass and energy are "equivalent," the mass defect, or "missing" mass found in part (a), is measurement of the energy it would take to break the bound 5927Co atom into its constituent particles. In other words, it is equivalent to the binding energy. Using the result of part (a), find the binding energy per nucleon, Eb/A for 5927Co in…

Chapter 20 Solutions

Chemistry: Atoms First V1

Ch. 20.2 - Prob. 20.2.1SRCh. 20.2 - Prob. 20.2.2SRCh. 20.2 - Prob. 20.2.3SRCh. 20.2 - Prob. 20.2.4SRCh. 20.3 - Prob. 20.3WECh. 20.3 - Prob. 3PPACh. 20.3 - Prob. 3PPBCh. 20.3 - Prob. 3PPCCh. 20.3 - Prob. 20.4WECh. 20.3 - Prob. 4PPACh. 20.3 - Prob. 4PPBCh. 20.3 - Prob. 4PPCCh. 20.3 - Prob. 20.3.1SRCh. 20.3 - Prob. 20.3.2SRCh. 20.3 - Prob. 20.3.3SRCh. 20.4 - Prob. 20.5WECh. 20.4 - Prob. 5PPACh. 20.4 - Prob. 5PPBCh. 20.4 - Prob. 5PPCCh. 20.4 - Prob. 20.4.1SRCh. 20.4 - Prob. 20.4.2SRCh. 20 - Prob. 20.1QPCh. 20 - Prob. 20.2QPCh. 20 - Prob. 20.3QPCh. 20 - Prob. 20.4QPCh. 20 - Prob. 20.5QPCh. 20 - Prob. 20.6QPCh. 20 - Prob. 20.7QPCh. 20 - Prob. 20.8QPCh. 20 - Prob. 20.9QPCh. 20 - Prob. 20.10QPCh. 20 - Prob. 20.11QPCh. 20 - Prob. 20.12QPCh. 20 - Prob. 20.13QPCh. 20 - Prob. 20.14QPCh. 20 - Prob. 20.15QPCh. 20 - Prob. 20.16QPCh. 20 - Prob. 20.17QPCh. 20 - Prob. 20.18QPCh. 20 - Prob. 20.19QPCh. 20 - Prob. 20.20QPCh. 20 - Prob. 20.21QPCh. 20 - Prob. 20.22QPCh. 20 - Prob. 20.23QPCh. 20 - Prob. 20.24QPCh. 20 - Prob. 20.25QPCh. 20 - Prob. 20.26QPCh. 20 - Prob. 20.27QPCh. 20 - Prob. 20.28QPCh. 20 - Prob. 20.29QPCh. 20 - Prob. 20.30QPCh. 20 - Prob. 20.31QPCh. 20 - Prob. 20.32QPCh. 20 - Prob. 20.33QPCh. 20 - Prob. 20.34QPCh. 20 - Prob. 20.35QPCh. 20 - Prob. 20.36QPCh. 20 - Prob. 20.37QPCh. 20 - Prob. 20.38QPCh. 20 - Prob. 20.39QPCh. 20 - Prob. 20.1VCCh. 20 - Prob. 20.2VCCh. 20 - Prob. 20.3VCCh. 20 - Prob. 20.4VCCh. 20 - Prob. 20.40QPCh. 20 - Prob. 20.41QPCh. 20 - Prob. 20.42QPCh. 20 - Prob. 20.43QPCh. 20 - Prob. 20.44QPCh. 20 - Prob. 20.45QPCh. 20 - Prob. 20.46QPCh. 20 - Prob. 20.47QPCh. 20 - Prob. 20.48QPCh. 20 - Prob. 20.49QPCh. 20 - Prob. 20.50QPCh. 20 - Prob. 20.51QPCh. 20 - Prob. 20.52QPCh. 20 - Prob. 20.53QPCh. 20 - Prob. 20.54QPCh. 20 - Prob. 20.55QPCh. 20 - Prob. 20.56QPCh. 20 - Prob. 20.57QPCh. 20 - Prob. 20.58QPCh. 20 - Prob. 20.59QPCh. 20 - Prob. 20.60QPCh. 20 - Prob. 20.61QPCh. 20 - Prob. 20.62QPCh. 20 - Prob. 20.63QPCh. 20 - Prob. 20.64QPCh. 20 - Prob. 20.65QPCh. 20 - Prob. 20.66QPCh. 20 - Prob. 20.67QPCh. 20 - Prob. 20.68QPCh. 20 - Prob. 20.69QPCh. 20 - Prob. 20.70QPCh. 20 - Prob. 20.71QPCh. 20 - Prob. 20.72QPCh. 20 - Prob. 20.73QPCh. 20 - Prob. 20.74QPCh. 20 - Prob. 20.75QPCh. 20 - Prob. 20.76QPCh. 20 - Prob. 20.77QPCh. 20 - Prob. 20.78QPCh. 20 - Prob. 20.79QPCh. 20 - Prob. 20.80QPCh. 20 - Prob. 20.81QPCh. 20 - Prob. 20.82QPCh. 20 - Prob. 20.83QPCh. 20 - Prob. 20.84QPCh. 20 - Prob. 20.85QPCh. 20 - Prob. 20.86QPCh. 20 - Prob. 20.87QPCh. 20 - Prob. 20.88QPCh. 20 - Prob. 20.89QPCh. 20 - Prob. 20.90QPCh. 20 - Prob. 20.91QPCh. 20 - Prob. 20.92QPCh. 20 - Prob. 20.93QPCh. 20 - Prob. 20.94QPCh. 20 - Prob. 20.95QPCh. 20 - Prob. 20.96QPCh. 20 - Prob. 20.97QPCh. 20 - Prob. 20.98QPCh. 20 - Prob. 20.99QPCh. 20 - Prob. 20.100QPCh. 20 - Prob. 20.101QP
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Text book image
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Text book image
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co