
(a)
Interpretation:
For magnesite decomposition the balanced equation has to be written.
Concept introduction:
Balanced equation: A balanced chemical equation is an equation which contains same elements in same number on both the sides (reactant and product side) of the chemical equation thereby obeying the law of conservation of mass.
The equation for a reaction, which has same number of atoms and charge of the ions in both reactants and product sides, is known as balanced equation.
Reactant: In a
Product: In a chemical reaction the species that present in right side is denoted as product that results from the reactant.
(a)

Answer to Problem 20.91P
Balance chemical eqaution is,
Explanation of Solution
Balance chemical eqaution is,
The
(b)
Interpretation:
For the given decomposition reaction the free energy
Concept introduction:
Free energy (or) entropy change is the term that is used to explain the total energy content in a
Where,
(b)

Answer to Problem 20.91P
For given decomposition reaction standard free energy values is
Explanation of Solution
Given decomposition reaction is,
Calculate the change in Gibb’s free energy at
Standard enthalpy change is,
Enthalpy values referred from Appendix Table.
The enthalpy change for the reaction is calculated as follows,
The enthalpy change is positive. Hence, the enthalpy
Entropy change
Calculate the change in entropy for this reaction as follows,
Where,
The
The enthalpy and entropy changes are positive sign for
Calculate the Free enrgy change
Standared Free energy change equation is
Calcualted enthalpy and entropy values are
Plugging these values into above standard free energy equation,
Therefore, for the given decomposition reaction standard free energy value is
(c)
Interpretation:
The minimum temperature at which the given reaction is spontaneous has to be identified.
Concept introduction:
Free energy (or) entropy change is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G. All spontaneous process is associated with the decrease of free energy in the system. The equation given below helps us to calculate the change in free energy in a system.
Where,
(c)

Answer to Problem 20.91P
The required minimum temperature is
Explanation of Solution
Given decomposition reaction is,
Calculate the change in Gibb’s free energy at
The reaction becomes spontaneous below the temprature where
Consider the follwing free energy equation,
Rearrange equation (2) to calculate temprature T,
Hence,
At temprature above
(d)
Interpretation:
For the
Concept introduction:
Free energy (or) entropy change is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G. All spontaneous process is associated with the decrease of free energy in the system. The equation given below helps us to calculate the change in free energy in a system.
Where,
Free energy change
Where,
(d)

Answer to Problem 20.91P
For given reaction, the equilbrium pressure
Explanation of Solution
Given,
Free energy equation is,
Solving for
Rearrange the above equation as shown below,
Then,
Therefore, the given equilbrium pressure
(e)
Interpretation:
For the following
Concept introduction:
Free energy (Gibbs free energy) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter
Free energy change
Where,
(e)

Answer to Problem 20.91P
For given reaction the equilbrium pressure
Explanation of Solution
Given,
Free energy equation is,
Calculate the Free enrgy change
Standared Free energy change equation iss,
Calcualted enthalpy and entropy values are
These values are plugging above standard free energy equation,
Next, we solving for
Rearrange the above equation,
Then,
Therefore, the given equilbrium pressure
Want to see more full solutions like this?
Chapter 20 Solutions
Chemistry: The Molecular Nature of Matter and Change
- Calculate Ecell for a hydrogen fuel cell at 95.0 oC using the following half-reactions with PH2 = 25.0 atm and PO2 = 25.0 atm. O2(g) + 4H+1(aq) + 4e-1 → 2H2O(l) Eo = 1.229 V 2H2(g) → 4H+1(aq) + 4e-1 Eo = 0.00 Varrow_forwardCalculate Ecell at 25.0 oC using the following half-reactions with [Ag+1] = 0.0100 M and [Sn+2] = 0.0200 M. Ag+1(aq) + 1e-1 Ag(s) Sn+2(aq) + 2e-1 Sn(s)arrow_forwardDone 18:19 www-awu.aleks.com Chapter 12 HW Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited .. LTE סוי 9 ✓ 20 ✓ 21 × 22 23 24 25 26 27 28 29 30 Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Classify each carbon atom as a 1º, 2º, 3º, or 4°. Highlight in red any 1° carbons, highlight in blue any 2° carbons. highlight in green any 3° carbons, and leave any 4° carbons unhighlighted. Skip Part Check Save For Later © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Accessibility ☑ คarrow_forward
- < Done 19:22 www-awu.aleks.com Chapter 12 HW Question 4 of 39 (2 points) | Question Attempt: 5 of Unlimited : .. LTE סוי 1 ✓ 2 ✓ 3 = 4 ✓ 5 ✓ 6 ✓ 7 ✓ 8 ✓ 9 = 10 11 ✓ 12 Consider the molecule (CH3)2CHCH2CHCн for the following questions. Part 1 of 2 Which of the following molecules is/are constitutional isomer(s) to (CH3)2CHCH2CH2CH3? Check all that apply. Part 2 of 2 (CH3),C(CH2)2CH3 CH3 H,C-CH-CH-CH, CH 3 None of the above. ☑ Which of the following molecules is/are identical molecules to (CH3)2CHCH2CH2CH₁₂? Check all that apply. CH3 H,C-CH-CH₂-CH2-CH, CH3(CH2)2CH(CH3)2 CH2-CH2-CH3 HỌC-CH=CH, 乂 ☑ а None of the above Check Save For Later Submit Assignment © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibilityarrow_forward18:11 LTE ا... US$50 off hotels is waiting for you Book now, hotels in Nashville are going fast QUTSLIVII 25 61 69 points) | QuestIVIT ALLēm... now Give the IUPAC name for each compound. Part 1 of 3 Part 2 of 3 X ☑ Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS CT US ...vacy Center | Accessibilityarrow_forwardDone 19:17 www-awu.aleks.com Chapter 12 HW Question 29 of 39 (6 points) | Question Attempt: 1 of Unlimited .III LTE סוי 27 28 = 29 30 31 32 = 33 34 35 Consider this structure. CH3CH2CH2 Part 1 of 3 3 CH2 CH2CH3 - C-CH2CH 3 H CH₂ Give the IUPAC name of this structure. 3-ethyl-3,4-dimethylheptane Part: 1/3 Part 2 of 3 Draw the skeletal structure. Skip Part < Check Click and drag to start drawing a structure. Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Хarrow_forward
- 18:57 .III LTE www-awu.aleks.com Chapter 12 HW Question 31 of 39 (8 points) | Question Attem... Give the IUPAC name of each compound. Part 1 of 4 Part 2 of 4 Х Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS OF US vacy Center | Accessibilityarrow_forwardWhat is the missing reactant in this organic reaction? CH3-C-CH2-NH2 + R - CH3 O: 0 CH3-N-CH2-C-NH-CH2-C-CH3 + H2O Specifically, in the drawing area below draw the condensed structure of R. If there is more than one reasonable answer, you can draw any one of them. If there is no reasonable answer, check the No answer box under the drawing area. Note for advanced students: you may assume no products other than those shown above are formed. Explanation Check Click anywhere to draw the first atom of your structure. C © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accesarrow_forwardDone 18:17 • www-awu.aleks.com Chapter 12 HW Question 24 of 39 (4 points) | Question Attempt: 1 of Unlimited ▼ 20 ✓ 21 × 22 23 24 25 26 raw the structure corresponding to each IUPAC name. Part 1 of 2 .III LTE 22 27 28 סוי 29 29 3 A skeletal structure corresponding to the IUPAC name 3-ethyl-4-methylhexane. Part 2 of 2 Click and drag to start drawing a structure. A condensed structure corresponding to the IUPAC name 2,2,4- trimethylpentane. Click anywhere to draw the first atom of your structure. Check Save For Later Submit < Х ப: G © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility : Garrow_forward
- Done 18:25 www-awu.aleks.com .III LTE Chapter 12 HW Question 29 of 39 (6 points) | Question Attempt: 1 of Unlimi... Oli 23 24 25 26 27 28 29 30 Consider this structure. CH2 CH2CH2 CH2CH2CH₂ C -C. -CH2CH3 H CH Part: 0 / 3 Part 1 of 3 Give the IUPAC name of this structure. Skip Part < Check ☑ Save For Later © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility ....................arrow_forwardCalculate Ecell at 25.0 oC using the following line notation. Zn(s)|Zn+2(aq, 0.900 M)||Cu+2(aq, 0.000200 M)|Cu(s)arrow_forwardPredict the product of this organic reaction: O OH + H + OH A P + H2O Specifically, in the drawing area below draw the skeletal ("line") structure of P. If there isn't any P because this reaction won't happen, check the No reaction box under the drawing area. Explanation Check Click and drag to start drawing a structure. X G ☐ :arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





