For the hydrolysis of ATP process, the K value should be founded at 37 o C . Concept introduction: Free energy (Gibbs free energy ) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G . All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG ° rxn ) is the difference in free energy of the reactants and products in their standard state. ΔG ° rxn = ∑ nΔG f ° (Products)- ∑ nΔG f ° (Reactants) Free energy change ΔG : change in the free energy takes place while reactants convert to product where both are in standard state. It depends on the equilibrium constant K ΔG = ΔG o + RT ln ( K ) ΔG o =- RT ln ( K ) Where, T is the temperature ΔG is the free energy ΔG o , ΔH o and ΔS o is standard free energy, enthalpy and entropy values.
For the hydrolysis of ATP process, the K value should be founded at 37 o C . Concept introduction: Free energy (Gibbs free energy ) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G . All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG ° rxn ) is the difference in free energy of the reactants and products in their standard state. ΔG ° rxn = ∑ nΔG f ° (Products)- ∑ nΔG f ° (Reactants) Free energy change ΔG : change in the free energy takes place while reactants convert to product where both are in standard state. It depends on the equilibrium constant K ΔG = ΔG o + RT ln ( K ) ΔG o =- RT ln ( K ) Where, T is the temperature ΔG is the free energy ΔG o , ΔH o and ΔS o is standard free energy, enthalpy and entropy values.
Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.
Chapter 20, Problem 20.100P
(a)
Interpretation Introduction
Interpretation:
For the hydrolysis of ATP process, the K value should be founded at 37oC.
Concept introduction:
Free energy (Gibbs free energy) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G. All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG°rxn) is the difference in free energy of the reactants and products in their standard state.
ΔG°rxn=∑nΔGf°(Products)-∑nΔGf°(Reactants)
Free energy changeΔG: change in the free energy takes place while reactants convert to product where both are in standard state. It depends on the equilibrium constant K
ΔG =ΔGo+RTln(K)ΔGo=- RTln(K)
Where,
T is the temperature
ΔG is the free energy
ΔGo, ΔHo and ΔSo is standard free energy, enthalpy and entropy values.
(b)
Interpretation Introduction
Interpretation:
For the metabolism of 1mol glucose, the ΔGrxno value should be founded.
Concept introduction:
Free energy (Gibbs free energy) is the term that is used to explain the total energy content in a thermodynamic system that can be converted into work. The free energy is represented by the letter G. All spontaneous process is associated with the decrease of free energy in the system. The standard free energy change (ΔG°rxn) is the difference in free energy of the reactants and products in their standard state.
ΔG°rxn=∑mΔGf°(Products)-∑nΔGf°(Reactants)
Where,
nΔGf°(Reactants) is the standard entropy of the reactants
mΔGf°(products) is the standard free energy of the products
(c)
Interpretation Introduction
Interpretation:
How many moles of ATP are produced by phosphorylation in glycolysis of 1 mole of glucose should be determined.
Concept introduction:
Moles: One mole is equivalent to the mass of the substance consists same number of units equal to the atoms present in 12g of 12C.
From given mass of substance moles could be calculated by using the following formula,
Molar mass: It is obtained by dividing the mass of substance with the amount of substance and the S.I. unit of molar mass is kg/mol. It is numerically equal to the molecular weight since molecular weight is sum of all individual atom weight present in molecule which is represented in amu.
You have started a patient on a new drug. Each dose introduces 40 pg/mL of drug after redistribution and prior to elimination. This drug is administered at 24 h intervals and has a half life of 24 h. What will the concentration of drug be after each of the first six doses? Show your work
a. What is the concentration after the fourth dose? in pg/mL
b. What is the concentration after the fifth dose? in pg/mL
c. What is the concentration after the sixth dose? in pg/mL
None
identify the formal charge in the case.
below by indicating the magnitude,
sign, and location of the charge
magnitude and sign of formal charge
location of formal charge (atom
number):
N
Chapter 20 Solutions
Chemistry: The Molecular Nature of Matter and Change
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