Explanation Given info: The mass of the lead is 5.00 kg , the initial temperature is 20.0 ° C and the specific heat of the lead is 128 J / kg ⋅ ° C . The melting point of the lead is 327 ° C . Write the expression for the change in the temperature is calculated as, Δ T = T 2 − T 1 Here, T 1 is the initial temperature of the material. T 2 is the final temperature of the material. Δ T is the change in temperature. Substitute 20.0 ° C for T 1 and 327 ° C for T 2 in the above equation top find the change in temperature of lead. Δ T = 327 ° C − 20.0 ° C = 307 ° C Thus, the change in temperature of lead is 307 ° C . The formula to calculate the amount of energy required for the rise of temperature is, Q = c m Δ T Here, Q is the amount of heat needed for the change in temperature. m is the mass of the lead. c is the specific heat of the lead. Δ T is the change in temperature of lead. Substitute 5.00 kg for m , 307 ° C for Δ T and 128 J / kg for c in the above equation

9th Edition

ISBN: 9781133947271

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

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Question

Chapter 20, Problem 20.5OQ

To determine

The required amount of energy to raise the temperature of the lead from 20.0 °C to its melting point.

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Chapter 20 Solutions

Physics for Scientists and Engineers

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The required amount of energy to raise the temperature of the lead from 20.0 ° C to its melting point.

Solution Summary: The author calculates the amount of energy required to raise the temperature of the lead from 20.0°C to its melting point.

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The required amount of energy to raise the temperature of the lead from 20.0 °C to its melting point.

Chapter 20 Solutions