ORGANIC CHEMISTRY-OWL V2 ACCESS
ORGANIC CHEMISTRY-OWL V2 ACCESS
8th Edition
ISBN: 9781305582422
Author: Brown
Publisher: CENGAGE L
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Chapter 20, Problem 20.55P

We now continue the use of organic chemistry reaction roadmaps. Because of the unique nature of the new reactions presented, we recommend that you make a new roadmap only for Chapters 20–23.

To make your own roadmap for Chapters 20–23, take a blank sheet of paper and write the following functional groups in the orientations shown. Fill the entire sheet of paper and leave plenty of room between functional groups. Most students find it helpful to use a poster-sized sheet of paper filled out in landscape orientation.

Chapter 20, Problem 20.55P, We now continue the use of organic chemistry reaction roadmaps. Because of the unique nature of the

We now continue the use of organic chemistry reaction roadmaps. Because of the unique nature of the new reactions presented, we recommend that you make a new roadmap only for Chapters 20–23.

To make your own roadmap for Chapters 20–23, take a blank sheet of paper and write the following functional groups in the orientations shown. Fill the entire sheet of paper and leave plenty of room between functional groups. Most students find it helpful to use a poster-sized sheet of paper filled out in landscape orientation.

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Interpretation Introduction

Interpretation:

A reaction roadmap has to be made for the reactions in the study Guide sections of chapters 20-23.

Concept Introduction:

Aromatic substitutions:

Aromatic substitution can be of two types, those are electrophilic and nucleophilic.  Aromatic electrophilic substitution is an organic reaction in which an atom that is attached to an aromatic system is replaced by an electrophile. For example nitration, sulphonation, acylation, alkylation, halogenation to aromatic ring is aromatic electrophilic substitution reaction.

Aromatic nucleophilic substitution reactions are those reactions where nucleophile replaces a good leaving group.

Sigmatropic reaction:

A sigmatropic reaction is a pericyclic reaction where the net result is change of one sigma bond to another sigma bond in an uncatalysed intramolecular process.

Explanation of Solution

The reaction road maps for the reactions in the study Guide section of chapters (20-23) will help us to find out the reactions in easy way. The section number indicates the respective reaction segments involved  in the study guide section.

Chapters 20 roadmap reaction legend,

Reaction 20.1:

Electrophilic addition to conjugate diene:

Conjugated diene undergoes both 1,2-addition and 1,4-addition reactions with electrophiles often giving mixtures of both kinds of products.  The ratio of 1,2-addition to 1,4-addition is temperature dependent.  1,2-addition products are kinetically controlled product and 1,4 addition products are thermodynamically controlled product.  When a conjugated diene reacts with HBr, initial protonation of one double bond gives a resonance stabilized allylic cation.  Reaction of bromide with one of the carbons of this intermediate bearing the partial positive charge gives the 1,2-addition product and the reaction at other gives the 1,4-addition product.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  1

Reaction 20.2:

Diels-Alder reaction:

Conjugated dienes react with certain type of molecules having double or triple bonds, known as dienophile, to form two new sigma bond and a ring structure on the lose of pi bond in a reaction called Diels-Alder reaction.  This reaction takes place in a concerted mechanism without intermediates and involves a redistribution of six pi electrons in a cyclic transition state where the pi bond breaking and new sigma bond making occurs simulteneously.  The configuration of the diene and dienophile is preserved.  Formation of the endo adduct is favoured.  This reaction is facilitated by having electron withdrawing groups on dienophile and electron donating groups on diene.  The diene must be on s-cis conformation to react.  Diels-Alder reaction is an example of [4+2] cycloaddition reaction.  The reaction is highly stereoselective.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  2

Reaction 20.3:

Claisen rearrangement:

The Claisen rearrangement is a powerful carbon-carbon bond forming chemical reaction.  This rearrangement transforms an allyl phenyl ether to an ortho-substituted phenol.  This rearrangement is an exothermic, concerted pericyclic reaction.  The kinetics are first order and the whole transformation proceeds through a highly ordered cyclic transition state and it is intramolecular.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  3

Reaction 20.4:

Cope rearrangement:

Cope rearrangement is the [3+3] sigmatropic reaction of 1,5-dienes.  This recation converts a 1,5-diene to give an isomeric 1,5-diene.  The reaction takes place in single step and involves the redistribution of six electrons in a cyclic transition state where two pi bonds are broken and new two pi bonds are made.  By analysing the chair and boat like transition states for the Cope rearrangement and also taking in account that the chair conformation has lower energy ,the product can be determined.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  4

Chapters 21 roadmap reaction legend,

Reaction 21.1:

Acid base reaction of phenol:

Water soluble phenols react with the strong bases to give water soluble salts.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  5

Reaction 21.2:

Kolbe synthesis:

Kolbe synthesis is a carboxylation chemical reaction that involves heating of sodim phenoxide with carbon dioxide and then treating the final product with sulfuric acid.  This is basically nucleophilic addition of phenoxide to carbon dioxide that gives substituted cyclohexadienone which undergoes keto-enol tautomerism to regenerate aromatic ring.  This gives maily ortho product which is known as salicylic acid.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  6

Reaction 21.3:

Oxidation of phenols to quinone:

Phenols can be easily oxidised to quinone.  Oxidation of phenols by H2CrO4 give 1,2-quinones or 1,4- quinones.  This depends on the structure of the particular phenol.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  7

Reaction 21.4:

Oxidation at benzylic position:

The benzylic carbon bonded hydrogen is weak and oxidation at benzylic position is to break the benzylic CH bond and to make benzylic CO bond.  At least one benzylic CH bond is needed that can be oxidised to carboxyl group on treatment with hot H2CrO4 or hot KMnO4.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  8

Reaction 21.5:

Halogenation at benzylic position:

Halogenation is regioselective for benzylic position and occurs by a radical chain mechanism.  Bromination shows higher regioselectivity for a benzylic position than does chlorination.  The reaction occurs via a radical chain mechanism which is initiated when the halohen molecule undergoes homolytic cleavage and gives two halide radical.  One of the radical abstracts the benzylic hydrogen to create a resonance stabilised benzylic radical that reacts with another molecule of halogen to give the halogenated product and the new radical continues the chain reaction.  NBS is used as the source of bromine.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  9

Reaction 21.6:

Hydrogenolysis of benzylic ethers:

Bezylic ethers can be cleaved to give an alcohol or toluene using catalytic hydrogenation of (H2/Pd) and the process is called hydrogenolysis.  This makes benzyl ether useful as an alcohol protecting group.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  10

Chapters 22 roadmap reaction legend,

Reaction 22.1:

Halogenation:

In halogenation reaction, aromatic ring reacts with chlorine in the presence of lewis acid catalyst FeCl3 to give chloroarenes.  They react with bromine in the presence of lewis acid catalyst FeBr3 to give bromoarenes.  The electrophile is a halonium ion formed as an ion pair by the interaction of chlorine or bromine with a lewis acid.  The mechanism involves an initial reaction between chlorine and FeCl3 to generate a molecular complex that can rearrange to give a Cl+FeCl4- ion pair.  The Cl+ reacts as a very strong electrophile with the weakly nucleophilic aromatic pi electron cloud to form a resonance –stabilised cation intermediate that loses a proton to give the choloroarene product.  Halogenation of an aromatic ring substituted by strongly activating groups does not require a lewis acid catalyst.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  11

Reaction 22.2:

Nitration:

This is a type of electrophilic substitution on aromatic ring.  The electrophile is the nitronium ion NO2+ which is formed by the interaction of nitric acid and sulphuric acid.  The mechanism involves an initial protonation of nitric acid by sulphuric acid followed by loss of water to yield the nitronium ion NO2+.  The nitronium ion reacts as very strong electrophile with the weakly nucleophilic aromatic pi electron cloud to form a resonance stabilised cation intermediate that loses a proton to give the final product.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  12

Reaction 22.3:

Sulfonation:

This is a type of electrophilic substitution on aromatic ring.  The electrophile is either SO3 or HSO3+ depending on the experimental conditions.  The mechanism involves reaction of SO3 as a very strong eleectrophile with the weakly nucleophilic aromatic pi electron cloud to form a resonance stabilised cation intermediate that loses a proton to give the arylsulfonic acid product.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  13

Reaction 22.4:

Fridel-craft’s alkylation:

This is a type of electrophilic substitution on aromatic ring.  The electrophile is a carbocation formed as an ion pair interaction of haloalkane with lewis acid.  Rearrangements from a less stable carbocation to more stable carbocation are common,  the mechanism involves an initial reaction between the haloalkane and lewis acid AlCl3 to yield an intermediate that can be brought as carbocation and AlCl4 ion pair.  The carbocation of ion pair reacts as a very strong electrophile with the weakly nucleophilic aromatic pi electron cloud to form a resonance stabilised cation intermediate that loses a proton to give the final product.  Because carbocations are involved hence the problem arised in the reaction is rearrangement.  It is hard to stop the reaction at single alkylation as monoalkylated products are more reactive.  Electron withdrawing group on the reaction fails the reaction.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  14

Reaction 22.5:

Fridel-craft’s acylation:

This is a type of electrophilic substitution on aromatic ring.  The electrophile is an acylium cation formed as an ion pair by interaction of an acyl halide with a lewis acid.  The mechanism involves an initial reaction between the acid chloride and lewis acid AlCl3 to yield an intermediate that can be brought as acylium ion and AlCl4 ion pair.  The acylium ion part reacts as very strong electrophile with the weakly nucleophile aromatic pi electron cloud to form a resonance stablised cation intermediate that looses a proton to give the final product.  The acylium ion does not rearrange like carbocation and reaction can be stopped at monoacylation as the electron density of the ring decresaes.  Electron withdrawing group on the ring fails the reaction.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  15

Reaction 22.6:

Alkylation using alkene:

This is a type of electrophilic substitution on aromatic ring.  The electrophile is a carbocation fromed by the reaction between the alkene and acids.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  16

Reaction 22.7:

Alkylation using alcohols:

This is a type of electrophilic substitution on aromatic ring.  The electrophile is a carbocation formed from an alcohol reacting with acid.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  17

Chapters 23 roadmap reaction legend,

Reaction 23.1:

Alkylation of ammonia and amine:

Alkylation of amine is a type of organic reaction between an alkyl halide and ammonia or amine.  This is nucleophilic aliphatic substitution and the reaction product is higher substitued amine.  But the problem with the reaction is the overalkylation.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  18

Reaction 23.2:

Alkylation of azide ion followed by reduction:

Azides are prepared by the treatment of a primary or secondary haloakane or an epoxide with KN3 and are reduced to primary amines by a variety of reducing agents, including lithium aluminium hydride,

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  19

Reaction 23.3:

Nitrosation of tertiary aromatic amines:

This is an electrophilic aromatic substitution.  The electrophile here is the nitrosyl cation which is very weak and participates in electrophilic aromatic substitution only with highly activated aromatic rings.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  20

Reaction 23.4:

Formation of N-nitrosamine from secondary amines:

This is an electrophilic aromatic substitution.  The electrophile here is the nitrosyl cation which reacts with secondary amine to give N-nitrsoamine.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  21

Reaction 23.5:

Diazotisation reaction:

Diazonium salta are organic compounds having RN2+X- entity where R is alkyl or aryl group and X is mainly halide ion.  The diazo compounds can be formed by treatment of aromatic amines with nitrous acid and additional acid.  Usually nitrous acid is generated in. situ from sodium nitrate and excess mineral acid.  The reaction is done at very low temperature of 0ο-5οC.  The reaction is shown below,

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  22

Reaction 23.6:

Conversion of primary aryl amine to phenol:

Formation of an arenediazonium salt followed by loss of nitrogen gives an aryl cation intermediate which then reacts with water to give a phenol.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  23

Reaction 23.7:

Schiemann reaction:

The Schiemann reaction is a chemical reaction in which a primary amine is transformed to an aryl fluoride via diazonium tetrafluoroborate intermediate.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  24

Reaction 23.8:

Sandmeyer reaction:

The Sandmeyer reaction is a chemical reaction used to synthesize aryl halides from aryl diazonium salts using copper salts as reagents or catalysts.  It is an example of a radical nucleophilic aromatic substitution.  The Sandmeyer reaction provides a method through which the unique transformation on benzene such as halogenation, cyanation, trifluoromethylation and hydroxylations can be done.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  25

Reaction 23.9:

Reaction of arenediazonium salt with KI:

Reaction of arenediazonium salt with KI is the most convinient way of introducing iodide to benzene ring.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  26

Reaction 23.10:

Reduction of arenediazonium salt with hypophosphorus acid:

By this pathway amine or nitro group can be removed from benzene ring.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  27

Reaction 23.11:

Hoffmann elimination:

Reaction of a quarternary ammonium halide with moist silver oxide to produce a quarternary ammonium hydroxide followed by heating to give an alkene is a reaction known as Hoffmann elimination.  The mechanism involves the simultenous deprotonation of a beta hydrogen by base and los of the amino group in an anti geometry.  In this process less substituted alkene is formed.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  28

Reaction 23.12:

Cope elimination:

Treatment of the tertiary amine with hydrogen peroxide gives an amine oxide which on heating gives an alkene and an N,N-dialkylhydroxyamine in the reaction is known as Cope elimination.  The elimination is syn stereoselective and involves a cyclic flow of six electrons in planar transition state.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  29

Reaction 23.12:

Reaction of cyclic beta amino alcohol with nitrous acid:

Treating a cyclic beta amino alcohol with nitrous acid leads to rearrangement and a ring expanded ketone.  The mechanism involves an initial formation of diazonium ion followed by simulteneous loss of nitrogen and rearrangement by a 1,2-shift to give a resonance stabilised cation that loses a proton to give the product cyclic ketone.

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  30

Thus, the reaction roadmap for the reactions in the study Guide section of chapters can be made as shown below for the chapters question 20-23,

ORGANIC CHEMISTRY-OWL V2 ACCESS, Chapter 20, Problem 20.55P , additional homework tip  31

                    Figure-1

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Chapter 20 Solutions

ORGANIC CHEMISTRY-OWL V2 ACCESS

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