Chemistry (7th Edition)
Chemistry (7th Edition)
7th Edition
ISBN: 9780321943170
Author: John E. McMurry, Robert C. Fay, Jill Kirsten Robinson
Publisher: PEARSON
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Chapter 20, Problem 20.108SP

(b)

Interpretation Introduction

Interpretation:

The valence bond description of the bonding in [NiBr4]2(tetrahedral) complex, orbital diagram and which hybrid orbital of the metal ions are used for bonding with a specific number of unpaired electrons should be determined.

Concept introduction:

  • In valence bond theory, the donation of pairs of electrons by ligands to the central metal atom or ion results in the metal-ligand bond.
  • The metal ion possesses a requisite number of valence orbitals of almost equal energy in order to accommodate the electrons given by ligands.
  • The unpaired (n-1) d electrons, pair up as fully as possible prior to hybridization thus making some (n-1) d orbitals vacant. The central metal atom then makes available the number of empty orbitals equal to its coordination number for the formation of coordinate bonds with suitable ligand orbitals.
  • With the approach of the ligands, metal-ligand bonds are then formed by the overlap of these orbitals with those of the ligands, that is by donation of electron pairs by the ligands to the empty hybridized orbitals.

(c)

Interpretation Introduction

Interpretation:

The valence bond description of the bonding in [Fe( CN)6]3 ( low-spin ) complex, orbital diagram and which hybrid orbital of the metal ions are used for bonding with a specific number of unpaired electrons should be determined.

Concept introduction:

  • In valence bond theory, the donation of pairs of electrons by ligands to the central metal atom or ion results in the metal-ligand bond.
  • The metal ion possesses a requisite number of valence orbitals of almost equal energy in order to accommodate the electrons given by ligands.
  • The unpaired (n-1) d electrons, pair up as fully as possible prior to hybridization thus making some (n-1) d orbitals vacant. The central metal atom then makes available the number of empty orbitals equal to its coordination number for the formation of coordinate bonds with suitable ligand orbitals.
  • With the approach of the ligands, metal-ligand bonds are then formed by the overlap of these orbitals with those of the ligands, that is by donation of electron pairs by the ligands to the empty hybridized orbitals.

(d)

Interpretation Introduction

Interpretation:

The valence bond description of the bonding in [MnCl6]3 (high-spin) complex, orbital diagram and which hybrid orbital of the metal ions are used for bonding with a specific number of unpaired electrons should be determined.

Concept introduction:

  • In valence bond theory, the donation of pairs of electrons by ligands to the central metal atom or ion results in the metal-ligand bond.
  • The metal ion possesses a requisite number of valence orbitals of almost equal energy in order to accommodate the electrons given by ligands.
  • The unpaired (n-1) d electrons, pair up as fully as possible prior to hybridization thus making some (n-1) d orbitals vacant. The central metal atom then makes available the number of empty orbitals equal to its coordination number for the formation of coordinate bonds with suitable ligand orbitals.
  • With the approach of the ligands, metal-ligand bonds are then formed by the overlap of these orbitals with those of the ligands, that is by donation of electron pairs by the ligands to the empty hybridized orbitals.

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Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? O ? A . If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. . If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. ㅇ 80 F5 F6 A 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Cente FIG
In methyl orange preparation, if the reaction started with 0.5 mole of sulfanilic acid to form the diazonium salt of this compound and then it converted to methyl orange [0.2 mole]. If the efficiency of the second step was 50%, Calculate: A. Equation(s) of Methyl Orange synthesis: Diazotization and coupling reactions. B. How much diazonium salt was formed in this reaction? C. The efficiency percentage of the diazotization reaction D. Efficiency percentage of the whole reaction.
Hand written equations please

Chapter 20 Solutions

Chemistry (7th Edition)

Ch. 20 - Prob. 20.11PCh. 20 - Prob. 20.12ACh. 20 - Prob. 20.13PCh. 20 - Prob. 20.14ACh. 20 - Prob. 20.15PCh. 20 - Prob. 20.16ACh. 20 - Prob. 20.17PCh. 20 - Prob. 20.18ACh. 20 - Prob. 20.19PCh. 20 - Prob. 20.20PCh. 20 - Prob. 20.21ACh. 20 - Prob. 20.22PCh. 20 - Prob. 20.23ACh. 20 - Prob. 20.24PCh. 20 - Prob. 20.25ACh. 20 - Prob. 20.26PCh. 20 - Prob. 20.27PCh. 20 - Prob. 20.28PCh. 20 - Prob. 20.29PCh. 20 - Prob. 20.30CPCh. 20 - Prob. 20.31CPCh. 20 - Prob. 20.32CPCh. 20 - Prob. 20.33CPCh. 20 - Prob. 20.34CPCh. 20 - Prob. 20.35CPCh. 20 - Prob. 20.36CPCh. 20 - Prob. 20.37CPCh. 20 - Prob. 20.38CPCh. 20 - Prob. 20.39CPCh. 20 - Prob. 20.40SPCh. 20 - Prob. 20.41SPCh. 20 - Prob. 20.42SPCh. 20 - Prob. 20.43SPCh. 20 - Titanium, used to make jet aircraft engines, is...Ch. 20 - Prob. 20.45SPCh. 20 - Prob. 20.46SPCh. 20 - Prob. 20.47SPCh. 20 - Prob. 20.48SPCh. 20 - Prob. 20.49SPCh. 20 - Prob. 20.50SPCh. 20 - Prob. 20.51SPCh. 20 - Prob. 20.52SPCh. 20 - Prob. 20.53SPCh. 20 - Prob. 20.54SPCh. 20 - Prob. 20.55SPCh. 20 - Prob. 20.56SPCh. 20 - Prob. 20.57SPCh. 20 - Prob. 20.58SPCh. 20 - Prob. 20.59SPCh. 20 - Prob. 20.60SPCh. 20 - Prob. 20.61SPCh. 20 - Prob. 20.62SPCh. 20 - Prob. 20.63SPCh. 20 - Prob. 20.64SPCh. 20 - Prob. 20.65SPCh. 20 - Prob. 20.66SPCh. 20 - Prob. 20.67SPCh. 20 - Prob. 20.68SPCh. 20 - Prob. 20.69SPCh. 20 - Prob. 20.70SPCh. 20 - Prob. 20.71SPCh. 20 - Prob. 20.72SPCh. 20 - Prob. 20.73SPCh. 20 - Prob. 20.74SPCh. 20 - Prob. 20.75SPCh. 20 - Prob. 20.76SPCh. 20 - Prob. 20.77SPCh. 20 - Prob. 20.78SPCh. 20 - Prob. 20.79SPCh. 20 - Prob. 20.80SPCh. 20 - Prob. 20.81SPCh. 20 - Prob. 20.82SPCh. 20 - Prob. 20.83SPCh. 20 - Prob. 20.84SPCh. 20 - Prob. 20.85SPCh. 20 - Prob. 20.86SPCh. 20 - Prob. 20.87SPCh. 20 - Prob. 20.88SPCh. 20 - Prob. 20.89SPCh. 20 - Prob. 20.90SPCh. 20 - Prob. 20.91SPCh. 20 - Prob. 20.92SPCh. 20 - Prob. 20.93SPCh. 20 - Prob. 20.94SPCh. 20 - Prob. 20.95SPCh. 20 - Prob. 20.96SPCh. 20 - Prob. 20.97SPCh. 20 - Prob. 20.98SPCh. 20 - Prob. 20.99SPCh. 20 - Prob. 20.100SPCh. 20 - Prob. 20.101SPCh. 20 - Prob. 20.102SPCh. 20 - Prob. 20.103SPCh. 20 - Prob. 20.104SPCh. 20 - Prob. 20.105SPCh. 20 - Prob. 20.106SPCh. 20 - Prob. 20.107SPCh. 20 - Prob. 20.108SPCh. 20 - Prob. 20.109SPCh. 20 - Prob. 20.110SPCh. 20 - Prob. 20.111SPCh. 20 - Prob. 20.112SPCh. 20 - Prob. 20.113SPCh. 20 - Prob. 20.114SPCh. 20 - Prob. 20.115SPCh. 20 - Prob. 20.116SPCh. 20 - Prob. 20.117SPCh. 20 - Prob. 20.118SPCh. 20 - Prob. 20.119SPCh. 20 - Prob. 20.120SPCh. 20 - Prob. 20.121SPCh. 20 - Prob. 20.122SPCh. 20 - Prob. 20.123SPCh. 20 - Prob. 20.124CPCh. 20 - Prob. 20.125CPCh. 20 - Prob. 20.126CPCh. 20 - Prob. 20.127CPCh. 20 - Prob. 20.128CPCh. 20 - Prob. 20.129CPCh. 20 - Prob. 20.130CPCh. 20 - Prob. 20.131CPCh. 20 - Prob. 20.132CPCh. 20 - Prob. 20.133CPCh. 20 - Prob. 20.134CPCh. 20 - Prob. 20.135CPCh. 20 - Prob. 20.136CPCh. 20 - Prob. 20.137CPCh. 20 - Prob. 20.138CPCh. 20 - Prob. 20.139CPCh. 20 - Prob. 20.140CPCh. 20 - Prob. 20.141CPCh. 20 - Prob. 20.142CPCh. 20 - Prob. 20.143CPCh. 20 - Prob. 20.144CPCh. 20 - Prob. 20.145CPCh. 20 - Prob. 20.146CPCh. 20 - Prob. 20.147CPCh. 20 - Prob. 20.148CPCh. 20 - Prob. 20.149MPCh. 20 - Prob. 20.150MPCh. 20 - Prob. 20.151MPCh. 20 - Prob. 20.152MPCh. 20 - Prob. 20.153MPCh. 20 - Prob. 20.154MPCh. 20 - Prob. 20.155MPCh. 20 - Prob. 20.156MPCh. 20 - Prob. 20.157MP
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