
Concept explainers
Review Question 20.1 What aspects of compass behavior near a magnet give us information about the direction of magnetic influence, and what aspects give us information about the strength?

The aspects of compass behavior near a magnet, which give us information about magnetic influence and strength.
Answer to Problem 1RQ
Solution:
The needle of a compass gets deflected towards the magnet instead of showing the actual direction of the Earth’s north and south poles. The stronger the magnetic influence, the larger is the deflection from the ideal position.
Explanation of Solution
Introduction:
A compass works on the magnetic principle that the needle of the compass shows the direction of the North pole as the Earth’s core is considered a big magnet.
Explanation:
The Earth contains molten metals inside it, which at a large scale is considered a big bar magnet with its north and south poles associated with the Earth’s north and south poles.
The compass itself contains a small magnet, whose north pole gets aligned towards Earth’s north pole when no other magnetic field is present. Whenever a new magnetic field is introduced near the compass, it gets deflected towards this new magnetic field as the magnet at the Earth’s core is situated at larger distance. Thus, even a small magnetic influence succeeds to change the position of the needle of the compass.
Also, the magnetic force between two bodies is directly proportional to the strength of the magnetic poles of the bodies. Hence, stronger the magnetic influence, the greater will be the deflection of the needle from the north pole of the compass.
Conclusion:
The compass will get deflected towards the magnet even when there is a small magnetic influence.
Want to see more full solutions like this?
Chapter 20 Solutions
College Physics
- Your colleague gives you a sample that are supposed to consist of Pt-Ni nanoparticles, TiO2 nanorod arrays, and SiO2 monolith plates (see right panel schematic). The bimetallic Pt-Ni nanoparticles are expected to decorate on the side surfaces of the aligned TiO2 nanorod arrays. These aligned TiO2 nanoarrays grew on the flat SiO2 monolith. Let's assume that the sizes of the Pt-Ni nanoparticles are > 10 nm. We further assume that you have access to a modern SEM that can produce a probe size as small as 1 nm with a current as high as 1 nA. You are not expected to damage/destroy the sample. Hint: keep your answers concise and to the point. TiO₂ Nanorods SiO, monolith a) What do you plan to do if your colleague wants to know if the Pt and Ni formed uniform alloy nanoparticles? (5 points) b) If your colleague wants to know the spatial distribution of the PtNi nanoparticles with respect to the TiO2 nanoarrays, how do you accomplish such a goal? (5 points) c) Based on the experimental results…arrow_forwardFind the current in 5.00 and 7.00 Ω resistors. Please explain all reasoningarrow_forwardFind the amplitude, wavelength, period, and the speed of the wave.arrow_forward
- A long solenoid of length 6.70 × 10-2 m and cross-sectional area 5.0 × 10-5 m² contains 6500 turns per meter of length. Determine the emf induced in the solenoid when the current in the solenoid changes from 0 to 1.5 A during the time interval from 0 to 0.20 s. Number Unitsarrow_forwardA coat hanger of mass m = 0.255 kg oscillates on a peg as a physical pendulum as shown in the figure below. The distance from the pivot to the center of mass of the coat hanger is d = 18.0 cm and the period of the motion is T = 1.37 s. Find the moment of inertia of the coat hanger about the pivot.arrow_forwardReview Conceptual Example 3 and the drawing as an aid in solving this problem. A conducting rod slides down between two frictionless vertical copper tracks at a constant speed of 3.9 m/s perpendicular to a 0.49-T magnetic field. The resistance of th rod and tracks is negligible. The rod maintains electrical contact with the tracks at all times and has a length of 1.4 m. A 1.1-Q resistor is attached between the tops of the tracks. (a) What is the mass of the rod? (b) Find the change in the gravitational potentia energy that occurs in a time of 0.26 s. (c) Find the electrical energy dissipated in the resistor in 0.26 s.arrow_forward
- A camera lens used for taking close-up photographs has a focal length of 21.5 mm. The farthest it can be placed from the film is 34.0 mm. (a) What is the closest object (in mm) that can be photographed? 58.5 mm (b) What is the magnification of this closest object? 0.581 × ×arrow_forwardGiven two particles with Q = 4.40-µC charges as shown in the figure below and a particle with charge q = 1.40 ✕ 10−18 C at the origin. (Note: Assume a reference level of potential V = 0 at r = ∞.) Three positively charged particles lie along the x-axis of the x y coordinate plane.Charge q is at the origin.Charge Q is at (0.800 m, 0).Another charge Q is at (−0.800 m, 0).(a)What is the net force (in N) exerted by the two 4.40-µC charges on the charge q? (Enter the magnitude.) N(b)What is the electric field (in N/C) at the origin due to the two 4.40-µC particles? (Enter the magnitude.) N/C(c)What is the electrical potential (in kV) at the origin due to the two 4.40-µC particles? kV(d)What If? What would be the change in electric potential energy (in J) of the system if the charge q were moved a distance d = 0.400 m closer to either of the 4.40-µC particles?arrow_forward(a) Where does an object need to be placed relative to a microscope in cm from the objective lens for its 0.500 cm focal length objective to produce a magnification of -25? (Give your answer to at least three decimal places.) 0.42 × cm (b) Where should the 5.00 cm focal length eyepiece be placed in cm behind the objective lens to produce a further fourfold (4.00) magnification? 15 × cmarrow_forward
- In a LASIK vision correction, the power of a patient's eye is increased by 3.10 D. Assuming this produces normal close vision, what was the patient's near point in m before the procedure? (The power for normal close vision is 54.0 D, and the lens-to-retina distance is 2.00 cm.) 0.98 x marrow_forwardDon't use ai to answer I will report you answerarrow_forwardA shopper standing 2.00 m from a convex security mirror sees his image with a magnification of 0.200. (Explicitly show on paper how you follow the steps in the Problem-Solving Strategy for mirrors found on page 1020. Your instructor may ask you to turn in this work.) (a) Where is his image (in m)? (Use the correct sign.) -0.4 m in front of the mirror ▾ (b) What is the focal length (in m) of the mirror? -0.5 m (c) What is its radius of curvature (in m)? -1.0 marrow_forward
- College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegeCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
- Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningAn Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage Learning





