Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined. Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

Question

(a 4 shows scanning electron microscope (SEM) images of extruded actions of packing bed for two capillary columns of different diameters, al 750 (bottom image) and b) 30-μm-i.d. Both columns are packed with the same stationary phase, spherical particles with 1-um diameter. A) When the columns were prepared, the figure shows that the column with the larger diameter has more packing irregularities. Explain this observation. B) Predict what affect this should have on band broadening and discuss your prediction using the van Deemter terms. C) Does this figure support your explanations in application question 33? Explain why or why not and make any changes in your answers in light of this figure. Figure 4 SEM images of sections of packed columns for a) 750 and b) 30-um-i.d. capillary columns.³

Answer 1

Question

Chapter 20, Problem 19E

(a)

Interpretation Introduction

Interpretation : Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined.

Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

(b)

Interpretation Introduction

Interpretation: Asample having 28.0mg ⁶⁴Cu then decay events produced in first second is to be calculated. Considering the atomic mass of is ⁶⁴Cu 64.0 u

Concept Introduction:Spontaneous breakdown of an atomic nucleus and results in release of energy from nucleus is called radioactive decay.

(c)

Interpretation Introduction

Interpretation: The time required to decrease the radioactivity below 25% of the initial measured value needs to be determined.

Concept Introduction : The rate law equation for first order reaction is as follows:

ln(CC0) = -kt

Where;

C0 = initial radioactivity at t= 0

C = radioactivity at time t

k = rate constant

t = time

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(a 4 shows scanning electron microscope (SEM) images of extruded actions of packing bed for two capillary columns of different diameters, al 750 (bottom image) and b) 30-μm-i.d. Both columns are packed with the same stationary phase, spherical particles with 1-um diameter. A) When the columns were prepared, the figure shows that the column with the larger diameter has more packing irregularities. Explain this observation. B) Predict what affect this should have on band broadening and discuss your prediction using the van Deemter terms. C) Does this figure support your explanations in application question 33? Explain why or why not and make any changes in your answers in light of this figure. Figure 4 SEM images of sections of packed columns for a) 750 and b) 30-um-i.d. capillary columns.³

fcrip = ↓ bandwidth Il temp 32. What impact (increase, decrease, or no change) does each of the following conditions have on the individual components of the van Deemter equation and consequently, band broadening? Increase temperature Longer column Using a gas mobile phase instead of liquid Smaller particle stationary phase Multiple Paths Diffusion Mass Transfer

34. Figure 3 shows Van Deemter plots for a solute molecule using different column inner diameters (i.d.). A) Predict whether decreasing the column inner diameters increase or decrease bandwidth. B) Predict which van Deemter equation coefficient (A, B, or C) has the greatest effect on increasing or decreasing bandwidth as a function of i.d. and justify your answer. Figure 3 Van Deemter plots for hydroquinone using different column inner diameters (i.d. in μm). The data was obtained from liquid chromatography experiments using fused-silica capillary columns packed with 1.0-μm particles. 35 20 H(um) 큰 20 15 90 0+ 1500 100 75 550 01 02 594 05 μ(cm/sec) 30 15 10

Answer 2

Question

Chapter 20, Problem 19E

(a)

Interpretation Introduction

Interpretation : Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined.

Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

(b)

Interpretation Introduction

Interpretation: Asample having 28.0mg ⁶⁴Cu then decay events produced in first second is to be calculated. Considering the atomic mass of is ⁶⁴Cu 64.0 u

Concept Introduction:Spontaneous breakdown of an atomic nucleus and results in release of energy from nucleus is called radioactive decay.

(c)

Interpretation Introduction

Interpretation: The time required to decrease the radioactivity below 25% of the initial measured value needs to be determined.

Concept Introduction : The rate law equation for first order reaction is as follows:

ln(CC0) = -kt

Where;

C0 = initial radioactivity at t= 0

C = radioactivity at time t

k = rate constant

t = time

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Answer 3

Question

Chapter 20, Problem 19E

(a)

Interpretation Introduction

Interpretation : Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined.

Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

(b)

Interpretation Introduction

Interpretation: Asample having 28.0mg ⁶⁴Cu then decay events produced in first second is to be calculated. Considering the atomic mass of is ⁶⁴Cu 64.0 u

Concept Introduction:Spontaneous breakdown of an atomic nucleus and results in release of energy from nucleus is called radioactive decay.

(c)

Interpretation Introduction

Interpretation: The time required to decrease the radioactivity below 25% of the initial measured value needs to be determined.

Concept Introduction : The rate law equation for first order reaction is as follows:

ln(CC0) = -kt

Where;

C0 = initial radioactivity at t= 0

C = radioactivity at time t

k = rate constant

t = time

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Answer 4

Question

Chapter 20, Problem 19E

(a)

Interpretation Introduction

Interpretation : Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined.

Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

(b)

Interpretation Introduction

Interpretation: Asample having 28.0mg ⁶⁴Cu then decay events produced in first second is to be calculated. Considering the atomic mass of is ⁶⁴Cu 64.0 u

Concept Introduction:Spontaneous breakdown of an atomic nucleus and results in release of energy from nucleus is called radioactive decay.

(c)

Interpretation Introduction

Interpretation: The time required to decrease the radioactivity below 25% of the initial measured value needs to be determined.

Concept Introduction : The rate law equation for first order reaction is as follows:

ln(CC0) = -kt

Where;

C0 = initial radioactivity at t= 0

C = radioactivity at time t

k = rate constant

t = time

Expert Solution & Answer

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Answer 5

Chapter 20, Problem 19E

(a)

Interpretation Introduction

Interpretation : Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined.

Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

(b)

Interpretation Introduction

Interpretation: Asample having 28.0mg ⁶⁴Cu then decay events produced in first second is to be calculated. Considering the atomic mass of is ⁶⁴Cu 64.0 u

Concept Introduction:Spontaneous breakdown of an atomic nucleus and results in release of energy from nucleus is called radioactive decay.

(c)

Interpretation Introduction

Interpretation: The time required to decrease the radioactivity below 25% of the initial measured value needs to be determined.

Concept Introduction : The rate law equation for first order reaction is as follows:

ln(CC0) = -kt

Where;

C0 = initial radioactivity at t= 0

C = radioactivity at time t

k = rate constant

t = time

Answer 6

Chapter 20, Problem 19E

(a)

Interpretation Introduction

Interpretation : Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined.

Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

Answer 7

Chapter 20, Problem 19E

(a)

Interpretation Introduction

Interpretation : Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined.

Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

Answer 8

(b)

Interpretation Introduction

Interpretation: Asample having 28.0mg ⁶⁴Cu then decay events produced in first second is to be calculated. Considering the atomic mass of is ⁶⁴Cu 64.0 u

Concept Introduction:Spontaneous breakdown of an atomic nucleus and results in release of energy from nucleus is called radioactive decay.

Answer 9

(b)

Interpretation Introduction

Interpretation: Asample having 28.0mg ⁶⁴Cu then decay events produced in first second is to be calculated. Considering the atomic mass of is ⁶⁴Cu 64.0 u

Concept Introduction:Spontaneous breakdown of an atomic nucleus and results in release of energy from nucleus is called radioactive decay.

Answer 10

(c)

Interpretation Introduction

Interpretation: The time required to decrease the radioactivity below 25% of the initial measured value needs to be determined.

Concept Introduction : The rate law equation for first order reaction is as follows:

ln(CC0) = -kt

Where;

C0 = initial radioactivity at t= 0

C = radioactivity at time t

k = rate constant

t = time

Answer 11

(c)

Interpretation Introduction

Interpretation: The time required to decrease the radioactivity below 25% of the initial measured value needs to be determined.

Concept Introduction : The rate law equation for first order reaction is as follows:

ln(CC0) = -kt

Where;

C0 = initial radioactivity at t= 0

C = radioactivity at time t

k = rate constant

t = time

Answer 12

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Answer 23

Ch. 20 - Prob. 1E Ch. 20 - Prob. 2E Ch. 20 - Prob. 3E Ch. 20 - Prob. 4E Ch. 20 - Prob. 5E Ch. 20 - Prob. 6E Ch. 20 - Prob. 7E Ch. 20 - Prob. 8E Ch. 20 - Prob. 9E Ch. 20 - Prob. 10E

Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined. Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

Solution Summary: The author explains how the value of k in s-1 is determined based on the half-life of the radioactive copper-64.

Interpretation : Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined.

Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

Interpretation: Asample having 28.0mg ⁶⁴Cu then decay events produced in first second is to be calculated. Considering the atomic mass of is ⁶⁴Cu 64.0 u

Concept Introduction:Spontaneous breakdown of an atomic nucleus and results in release of energy from nucleus is called radioactive decay.

Chapter 20 Solutions

Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined. Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

Solution Summary: The author explains how the value of k in s-1 is determined based on the half-life of the radioactive copper-64.

Interpretation : Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined. Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.

Interpretation: Asample having 28.0mg 64Cu then decay events produced in first second is to be calculated. Considering the atomic mass of is 64Cu 64.0 u Concept Introduction:Spontaneous breakdown of an atomic nucleus and results in release of energy from nucleus is called radioactive decay.

Chapter 20 Solutions

Interpretation : Radioactive copper-64 decays with a half-life of 12.8 days. Then the value of k in s-1 is to be determined.

Concept Introduction : The time required to disintegrate exactly half of the radioactive substance is called half-life period.