
Concepts of Genetics (11th Edition)
11th Edition
ISBN: 9780321948915
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Textbook Question
Chapter 20, Problem 15PDQ
You have recovered a cloned DNA segment from a vector and determine that the insert is 1300 bp in length. To characterize this cloned segment, you isolate the insert and decide to construct a restriction map. Using enzyme I and enzyme II, followed by gel electrophoresis, you determine the number and size of the fragments produced by enzymes I and II alone and in combination, as recorded in the following table. Construct a restriction map from these data, showing the positions of the restriction-enzyme cutting sites relative to one another and the distance between them in units of base pairs.
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Chapter 20 Solutions
Concepts of Genetics (11th Edition)
Ch. 20 - A plasmid that is both ampicillin and tetracycline...Ch. 20 - Prob. 2NSTCh. 20 - You have just created the worlds first genomic...Ch. 20 - Prob. 1CSCh. 20 - Prob. 2CSCh. 20 - Prob. 3CSCh. 20 - HOW DO WE KNOW? In this chapter we focused on how...Ch. 20 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 20 - What roles do restriction enzymes, vectors, and...Ch. 20 - The human insulin gene contains a number of...
Ch. 20 - Although many cloning applications involve...Ch. 20 - Using DNA sequencing on a cloned DNA segment, you...Ch. 20 - Restriction sites are palindromic; that is, they...Ch. 20 - List the advantages and disadvantages of using...Ch. 20 - What are the advantages of using a restriction...Ch. 20 - Prob. 10PDQCh. 20 - In the context of recombinant DNA technology, of...Ch. 20 - If you performed a PCR experiment starting with...Ch. 20 - Prob. 13PDQCh. 20 - Prob. 14PDQCh. 20 - You have recovered a cloned DNA segment from a...Ch. 20 - Prob. 16PDQCh. 20 - Although the capture and trading of great apes has...Ch. 20 - Prob. 18PDQCh. 20 - Prob. 19PDQCh. 20 - Prob. 20PDQCh. 20 - Prob. 21PDQCh. 20 - Prob. 22PDQCh. 20 - Prob. 23PDQCh. 20 - How is fluorescent in situ hybridization (FISH)...Ch. 20 - What is the difference between a knockout animal...Ch. 20 - Prob. 26PDQCh. 20 - When disrupting a mouse gene by knockout, why is...Ch. 20 - Prob. 28PDQCh. 20 - The gel presented here shows the pattern of bands...Ch. 20 - A widely used method for calculating the annealing...Ch. 20 - Most of the techniques described in this chapter...Ch. 20 - In humans, congenital heart disease is a common...Ch. 20 - The U.S. Department of Justice has established a...Ch. 20 - Prob. 34ESP
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