Manufacturing Engineering & Technology
7th Edition
ISBN: 9780133128741
Author: Serope Kalpakjian, Steven Schmid
Publisher: Prentice Hall
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Chapter 20, Problem 14RQ
Which rapid-prototyping operations can produce transparent workpieces?
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Chapter 20 Solutions
Manufacturing Engineering & Technology
Ch. 20 - What is the basic difference between additive...Ch. 20 - What is stereolithography?Ch. 20 - What is virtual prototyping, and how does it...Ch. 20 - What is fused-deposition modeling?Ch. 20 - Prob. 5RQCh. 20 - Prob. 6RQCh. 20 - Explain what each of the following means: (a) 3DP,...Ch. 20 - What starting materials can be used in...Ch. 20 - What are the cleaning and finishing operations in...Ch. 20 - Which rapid-prototyping technologies do not...
Ch. 20 - What are the advantages of electron beam melting?Ch. 20 - What is the Keltool process?Ch. 20 - What is a self-replicating machine?Ch. 20 - Which rapid-prototyping operations can produce...Ch. 20 - Which rapid-prototyping operations can produce...Ch. 20 - How can a mold for sand casting be produced using...Ch. 20 - Examine a ceramic coffee cup and determine in...Ch. 20 - How would you rapidly manufacture tooling for...Ch. 20 - Explain the significance of rapid tooling in...Ch. 20 - List the processes described in this chapter that...Ch. 20 - Few parts in commercial products today are...Ch. 20 - Can rapid-prototyped parts be made of paper?...Ch. 20 - Careful analysis of a rapid-prototyped part...Ch. 20 - Why are the metal parts in three-dimensional...Ch. 20 - Make a list of the advantages and limitations of...Ch. 20 - In making a prototype of a toy automobile, list...Ch. 20 - Using an approximate cost of 400 per gallon for...Ch. 20 - The extruder head in a fused-deposition modeling...Ch. 20 - Using the data for Problem 20.28 and assuming that...Ch. 20 - Rapid-prototyping machines represent a large...Ch. 20 - One of the major advantages of stereolithography...Ch. 20 - A manufacturing technique is being proposed that...Ch. 20 - Identify the rapid-prototyping processes described...Ch. 20 - Design a machine that uses rapid-prototyping...Ch. 20 - Because of relief of residual stresses during...Ch. 20 - Prob. 37SDPCh. 20 - Prob. 39SDPCh. 20 - Prob. 40SDP
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- determine the direction and magnitude of angular velocity ω3 of link CD in the four-bar linkage using the relative velocity graphical methodarrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forward
- The evaporator of a vapor compression refrigeration cycle utilizing R-123 as the refrigerant isbeing used to chill water. The evaporator is a shell and tube heat exchanger with the water flowingthrough the tubes. The water enters the heat exchanger at a temperature of 54°F. The approachtemperature difference of the evaporator is 3°R. The evaporating pressure of the refrigeration cycleis 4.8 psia and the condensing pressure is 75 psia. The refrigerant is flowing through the cycle witha flow rate of 18,000 lbm/hr. The R-123 leaves the evaporator as a saturated vapor and leaves thecondenser as a saturated liquid. Determine the following:a. The outlet temperature of the chilled waterb. The volumetric flow rate of the chilled water (gpm)c. The UA product of the evaporator (Btu/h-°F)d. The heat transfer rate between the refrigerant and the water (tons)arrow_forward(Read image) (Answer given)arrow_forwardProblem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and (y2), respectively. Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s]. Givens: y1 = 4.112 m y2 = 0.387 m b = 0.942 m Answers: ( 1 ) 1880.186 lit/s ( 2 ) 4042.945 lit/s ( 3 ) 2553.11 lit/s ( 4 ) 3130.448 lit/sarrow_forward
- Problem (14): A pump is being used to lift water from an underground tank through a pipe of diameter (d) at discharge (Q). The total head loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h where (V) is the flow velocity in the pipe. The elevation difference between the pump and tank surface is (h). Given the values of h [cm], d [cm], and K [-], calculate the maximum discharge Q [Lit/s] beyond which cavitation would take place at the pump entrance. Assume Turbulent flow conditions. Givens: h = 120.31 cm d = 14.455 cm K = 8.976 Q Answers: (1) 94.917 lit/s (2) 49.048 lit/s ( 3 ) 80.722 lit/s 68.588 lit/s 4arrow_forwardProblem (13): A pump is being used to lift water from the bottom tank to the top tank in a galvanized iron pipe at a discharge (Q). The length and diameter of the pipe section from the bottom tank to the pump are (L₁) and (d₁), respectively. The length and diameter of the pipe section from the pump to the top tank are (L2) and (d2), respectively. Given the values of Q [L/s], L₁ [m], d₁ [m], L₂ [m], d₂ [m], calculate total head loss due to friction (i.e., major loss) in the pipe (hmajor-loss) in [cm]. Givens: L₁,d₁ Pump L₂,d2 오 0.533 lit/s L1 = 6920.729 m d1 = 1.065 m L2 = 70.946 m d2 0.072 m Answers: (1) 3.069 cm (2) 3.914 cm ( 3 ) 2.519 cm ( 4 ) 1.855 cm TABLE 8.1 Equivalent Roughness for New Pipes Pipe Riveted steel Concrete Wood stave Cast iron Galvanized iron Equivalent Roughness, & Feet Millimeters 0.003-0.03 0.9-9.0 0.001-0.01 0.3-3.0 0.0006-0.003 0.18-0.9 0.00085 0.26 0.0005 0.15 0.045 0.000005 0.0015 0.0 (smooth) 0.0 (smooth) Commercial steel or wrought iron 0.00015 Drawn…arrow_forwardThe flow rate is 12.275 Liters/s and the diameter is 6.266 cm.arrow_forward
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