An equation that corresponds to the process of ionization enthalpy and electron affinity by using elemental phosphorus as an example is to be written. An explanation is to be given corresponds to the fact that why first ionization energy increases as one proceed from left to right. The reason is to be stated for fact that first ionization energy of Aluminum and Sulfur lower than the Magnesium and Phosphorus respectively. The reasons for the increment in the successive ionization energies are to be stated. Any large jump observed between successive ionization enthalpy of Silicon after the removal of all electrons is to stated. Concept introduction: The energy needed to eject the loosely bound electron present in an atom is called ionization energy. It is also termed as ionization enthalpy. The energy required to add an electron in an atom is called electron affinity. On-going from left to right across the period the nuclear force increases therefore, first ionization enthalpy increases. To determine: The equations for the process of ionization enthalpy and electron affinity, the reason for the increment in the first ionization enthalpy which tends to increase from left to right across a period, the reason for lower value of first ionization energy of Aluminum than Magnesium, the reason for the lower value of first ionization energy of Sulfur than phosphorous, the reason for an increment in successive ionization enthalpies of an atom, if any large jumps between successive ionization enthalpies of Silicon after the removal of all the electrons.

Question

Indicate how to find the energy difference between two levels in cm-1, knowing that its value is 2.5x10-25 joules.

Answer 1

Question

Chapter 2, Problem 9RQ

Interpretation Introduction

Interpretation: An equation that corresponds to the process of ionization enthalpy and electron affinity by using elemental phosphorus as an example is to be written. An explanation is to be given corresponds to the fact that why first ionization energy increases as one proceed from left to right. The reason is to be stated for fact that first ionization energy of Aluminum and Sulfur lower than the Magnesium and Phosphorus respectively. The reasons for the increment in the successive ionization energies are to be stated. Any large jump observed between successive ionization enthalpy of Silicon after the removal of all electrons is to stated.

Concept introduction: The energy needed to eject the loosely bound electron present in an atom is called ionization energy. It is also termed as ionization enthalpy.

The energy required to add an electron in an atom is called electron affinity.

On-going from left to right across the period the nuclear force increases therefore, first ionization enthalpy increases.

To determine: The equations for the process of ionization enthalpy and electron affinity, the reason for the increment in the first ionization enthalpy which tends to increase from left to right across a period, the reason for lower value of first ionization energy of Aluminum than Magnesium, the reason for the lower value of first ionization energy of Sulfur than phosphorous, the reason for an increment in successive ionization enthalpies of an atom, if any large jumps between successive ionization enthalpies of Silicon after the removal of all the electrons.

Expert Solution & Answer

Trending nowThis is a popular solution!

See solution

Check out sample textbook solution

Students have asked these similar questions

Indicate how to find the energy difference between two levels in cm-1, knowing that its value is 2.5x10-25 joules.

The gyromagnetic ratio (gamma) for 1H is 2.675x108 s-1 T-1. If the applied field is 1,409 T what will be the separation between nuclear energy levels?

Chances Ad ~stract one 11. (10pts total) Consider the radical chlorination of 1,3-diethylcyclohexane depicted below. 4 • 6H total $4th total Statistical pro 21 total 2 H A 2H 래 • 4H totul < 3°C-H werkest bund - abstraction he leads to then mo fac a) (6pts) How many unique mono-chlorinated products can be formed and what are the structures for the thermodynamically and statistically favored products? рос 6 -વા J Number of Unique Mono-Chlorinated Products Thermodynamically Favored Product Statistically Favored Product b) (4pts) Draw the arrow pushing mechanism for the FIRST propagation step (p-1) for the formation of the thermodynamically favored product. Only draw the p-1 step. You do not need to include lone pairs of electrons. No enthalpy calculation necessary H H-Cl