Bundle: Introductory Chemistry: A Foundation, Loose-leaf Version, 9th + OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card

9th Edition

ISBN: 9780357000922

Author: Steven S. Zumdahl, Donald J. DeCoste

Publisher: Cengage Learning

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Chapter 2, Problem 97AP

97. Indicate the number of significant digits in the answer when each of the following expressions is evaluated (you do not have to evaluate the expression).

( 6.25 ) / ( 74.11143 )

( 1.45 ) ( 0.08431 ) ( 6.022 × 10 23 )

( 4.75512 ) ( 9.74441 ) / ( 3.14 )

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Chapter 2, Problem 96QAP

Chapter 2, Problem 98AP

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To divide numbers in scientific notation: divide the digit terms and subtract the exponents. (A x 10)/(B x 10²) (A/B) x 10 Y-z (5.6 x 105)/(1.8 x 10²) = (5.6/1.8) x 105-2 (You may have to put numbers back in proper notation!) Perform these calculations (2.2 x 104) (1.3 x 10²) = (1.6 x 1033)/(1.3 x 10-6) = (4.6 x 1022) (1.2 x 10-8) = (5.6 x 107)/(1.0 x 10²) = (2.6 x 10²) (1.1 x 10-²) = = 3.1 x 10³ not used this semester. Before Adding and subtracting in scientific notation performing this function you must make the exponents the same first. 1.0 x 102 Example: 1.2 x 105 + You can't just add the digit terms because one is really a very large number so either take them both out of notation then add 120000 + 100 = 120100 or write one of the numbers out of proper notation in order to get the same exponent: now write in proper notation 1.201 x 105 1200 x 102 +1.0 x 10² = 1201 x 10²

Find the difference between the value of x2 and the sum of x1 plus x3.; let x4 be equivalent to the sum of x1 and x3 and let x5 be the difference between x2 and x5. This calculation scheme is shown below. Make notes about any similarities or differences between the values in your notes. x4 = x1 + x3 x5 = x2 – x4 Data Analyis This section will include all data collected during the lab. Thermochemical Data Tinitial (°C) Tfinal (°C) ΔT (°C) moles NaOH qreaction (kJ) ΔHrxn Reaction 1 25.0 30.3 +5.3 0.025 -1.11 -44.4 Reaction 2 25.0 37.0 +12.0 0.025 -2.51 -100.4 Reaction 3 25.0 31.7 +6.7 0.025 -1.40 -56.1 Reaction 1: NaOH(s) → Na+(aq) + OH-(aq) + x1 kJ 1g /39.977g/mol = 0.025 moles Moles NaOH = 0.025 qsolution = (4.184 J/g °C) (50.0g) (30.3°C -25.0°C) = -1108.76 J/ 1000 qreaction (kJ) = -1.11 kJ ΔH = -1.11 kJ/ 0.025 moles ΔHrxn = -44.4 kJ/mol…

between significant digits are always significant. figures. Example: 5,007 has 4 significant figures. 3) Trailing zeros in a number are significant only If the number contalns a decimal polnt. Example: 100.0 has 4 significant figures. 100 has 1 significant figure. 4) Zeros in the beginning of a number whose only function Is to place the decimal polnt are not significant. Example: 0.0025 has 2 significant figures. 5) Zeros following a decimal significant figure are significant. Example: 0.000470 has 3 significant figures. 0.47000 has 5 signlficant figures. Determine the number of significant figures in the following numbers. 1. 0.02 6. 5,000. 4. 2. 0.020 2. 7. 6,051.006 3. 501 3 8. 0.0005 1. 4. 501.0 9. 0.1020 5. 5,000 10. 10,001 5 Determine the location of the last significant place value by placing a bar over the digit. Example: 1.700) 9,010.0 4.7x10-8 10,8 00,000 3.0Tx 1021 0.00410 1. 8040 6. 90,100 0.0300 699.5 2,000X162 0.90100 2. 0.0300 7. 4.7 x 108 3. 699.5 8. 10,800,000. 3.…

Chapter 2 Solutions

Bundle: Introductory Chemistry: A Foundation, Loose-leaf Version, 9th + OWLv2 with MindTap Reader, 1 term (6 months) Printed Access Card

Ch. 2.1 - Exercise 2.1 Write the numbers 357 and 0.0055 in...Ch. 2.2 - What if you were not allowed to use units for one...Ch. 2.5 - Exercise 2.2 Give the number of significant...Ch. 2.5 - Exercise 2.3 Give the answer for each calculation...Ch. 2.6 - Exercise 2.4 Wine is often bottled in 0.750-L...Ch. 2.6 - Exercise 2.5 Racing cars at the Indianapolis Motor...Ch. 2.7 - Exercise 2.6 Which temperature is colder, 172 K or...Ch. 2.7 - Exercise 2.7 Hot tubs are often maintained at 41...Ch. 2.7 - Exercise 2.8 An antifreeze solution in a car’s...Ch. 2.8 - Exercise 2.9A student wants to identify the main...

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97. Indicate the number of significant digits in the answer when each of the following expressions is evaluated (you do not have to evaluate the expression). ( 6.25 ) / ( 74.11143 ) ( 1.45 ) ( 0.08431 ) ( 6.022 × 10 23 ) ( 4.75512 ) ( 9.74441 ) / ( 3.14 )

Solution Summary: The author explains that the number of significant digits in the answer should be determined without performing the calculations.

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