(a) Interpretation: The number of rubidium atoms in arrangement A. Concept introduction: In arrangement A, all the atoms are lined up with one another to form a square grid. The atoms are assumed to be a circle and are aligned in such a way that each atom with diameter 4 .95 A o can occupy a space of Small Square with side equal to the diameter of the atom.
(a) Interpretation: The number of rubidium atoms in arrangement A. Concept introduction: In arrangement A, all the atoms are lined up with one another to form a square grid. The atoms are assumed to be a circle and are aligned in such a way that each atom with diameter 4 .95 A o can occupy a space of Small Square with side equal to the diameter of the atom.
Interpretation: The number of rubidium atoms in arrangement A.
Concept introduction: In arrangement A, all the atoms are lined up with one another to form a square grid. The atoms are assumed to be a circle and are aligned in such a way that each atom with diameter 4.95Ao can occupy a space of Small Square with side equal to the diameter of the atom.
Interpretation Introduction
(b)
Interpretation: The number of rubidium atoms in arrangement B.
Concept introduction:
In B type arrangement, the atoms sit in a depression and form a close- packing arrangement. The triangle is assumed to be formed by considering the four atoms in the bottom row, three atoms in the third row, two atoms in the middle row, one atom in the first row.
Interpretation Introduction
(c)
Interpretation: The increase in the number of atoms on going from arrangement A to arrangement B and if the density is greater in arrangement A or arrangement B.
Concept introduction:
From going arrangement A to arrangement B,
The increase in the number of atoms is calculated by the by the formula,
Fill in the blanks by selecting the appropriate term from below:
For a process that is non-spontaneous and that favors products at equilibrium, we know that a) ΔrG∘ΔrG∘ _________, b) ΔunivSΔunivS _________, c) ΔsysSΔsysS _________, and d) ΔrH∘ΔrH∘ _________.
Highest occupied molecular orbital
Lowest unoccupied molecular orbital
Label all nodes and regions of highest and lowest electron density for both orbitals.
Relative Intensity
Part VI. consider the multi-step reaction below for compounds A, B, and C.
These compounds were subjected to mass spectrometric analysis and
the following spectra for A, B, and C was obtained.
Draw the structure of B and C and match all three compounds
to the correct spectra.
Relative Intensity
Relative Intensity
20
NaоH
0103
Br
(B)
H2504
→ (c)
(A)
100-
MS-NU-0547
80
40
20
31
10
20
100-
MS2016-05353CM
80
60
100
MS-NJ-09-3
80
60
40
20
45
J.L
80
S1
84
M+
absent
राग
135 137
S2
62
164 166
11
S3
25
50
75
100
125
150
175
m/z
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NEET Chemistry | Group 14 Carbon Family | Theory & Problem Solving | In English | Misostudy; Author: Misostudy;https://www.youtube.com/watch?v=enOGIrcHh54;License: Standard YouTube License, CC-BY