(a)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(a)
Answer to Problem 89E
The formula of sodium oxide is Na2O
Explanation of Solution
To determine: The formula of sodium oxide.
The formula of sodium oxide is Na2O
The oxidation state of sodium is +1.
Oxygen is an anion having oxidation state −2
So, the formula of the given compound is Na2O
(b)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(b)
Answer to Problem 89E
The formula of sodium peroxide is Na2O2
Explanation of Solution
To determine: The formula of sodium peroxide.
The formula of sodium peroxide is Na2O2
The oxidation state of sodium is +1.
Oxygen is an anion having oxidation state −1. It is exception case which occurs only in peroxide condition.
Sodium peroxide is formed when two sodium and oxygen atoms is combined together.
So, the formula of the given compound is Na2O2
(c)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(c)
Answer to Problem 89E
The formula of potassium cyanide is KCN
Explanation of Solution
To determine: The formula of potassium cyanide
The formula of potassium cyanide is KCN
The oxidation state of potassium is +1
Cyanide (CN) is an anion having oxidation state −1
So, the formula of the given compound is KCN
(d)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(d)
Answer to Problem 89E
The formula of copper (II) nitrate is Cu(NO3)2
Explanation of Solution
To determine: The formula of copper (II) nitrate
The formula of copper (II) nitrate is Cu(NO3)2
The oxidation state of copper is +2.
Nitrate (NO3)2 is an anion having oxidation state −1
So, the formula of the given compound is Cu(NO3)2
(e)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(e)
Answer to Problem 89E
The formula of selenium tetrabromide is SeBr4
Explanation of Solution
To determine: The formula of selenium tetrabromide.
The formula of selenium tetrabromide is SeBr4
The oxidation state of selenium is +4.
Bromine is an anion having oxidation state −1
So, the formula of the given compound is SeBr4
(f)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(f)
Answer to Problem 89E
The formula of iodous acid is HIO2
Explanation of Solution
To determine: The formula of iodous acid
The formula of iodous acid is HIO2
The oxidation state of hydrogen cation is +1.
Iodite (IO2) is anion having oxidation state −1
So, the formula of the given compound is HIO2
(g)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(g)
Answer to Problem 89E
The formula of lead (IV) sulfide is PbS2
Explanation of Solution
To determine: The formula of of lead (IV) sulfide.
The formula of lead (IV) sulfide is PbS2
The oxidation state of lead (Pb) is +4.
Sulfide is an anion having oxidation state −2
So, the formula of the given compound is PbS2
(h)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(h)
Answer to Problem 89E
The formula of copper (I) chloride is CuCl
Explanation of Solution
To determine: The formula of copper (I) chloride.
The formula of copper (I) chloride is CuCl
The oxidation state of copper (Cu) is +1.
Chlorine (Cl) is an anion having oxidation state −1
So, the formula of the given compound is CuCl
(i)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(i)
Answer to Problem 89E
The formula of gallium arsenide is GaAs
Explanation of Solution
To determine: The formula of gallium arsenide
The formula of gallium arsenide is GaAs
The oxidation state of gallium (Ga) is +3.
Arsenic (As) is an anion having oxidation state +3
So, the formula of the given compound is GaAs
(j)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(j)
Answer to Problem 89E
The formula of cadmium selenide is CdSe
Explanation of Solution
To determine: The formula of cadmium selenide.
The formula of cadmium selenide is CdSe
The oxidation state of cadmium (Cd) is +2.
Selenium (Se) is an anion having oxidation state −2
So, the formula of the given compound is CdSe
(k)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(k)
Answer to Problem 89E
The formula of zinc sulfide is ZnS
Explanation of Solution
To determine: The formula of of zinc sulfide.
The formula of zinc sulfide is ZnS
The oxidation state of zinc (Zn) is +2.
Sulfide is an anion having oxidation state −2
So, the formula of the given compound is ZnS
(l)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(l)
Answer to Problem 89E
The formula of nitrous acid is HNO2
Explanation of Solution
To determine: The formula of of nitrous acid.
The formula of nitrous acid is HNO2
The oxidation state of hydrogen (H) is +1.
Nitrous (NO2) is an anion having oxidation state −1
So, the formula of the given compound is HNO2
(m)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as, group number−8. While naming an ionic compound, the cation is named first followed by the naming of the anion. If the cation exhibits more than one oxidation state then the current oxidation state of the cation is to be mentioned.
(m)
Answer to Problem 89E
The formula of diphosphorous pentaoxide is P2O5
Explanation of Solution
To determine: The formula of of diphosphorous pentaoxide.
The formula of diphosphorous pentaoxide is P2O5
The oxidation state of phosphorous (P) is +5.
Oxygen is an anion having oxidation state −2
So, the formula of the given compound is P2O5
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Chapter 2 Solutions
Bundle: Chemistry, 10th + Laboratory Handbook for General Chemistry, 3rd + Student Resource Center Printed Access Card + Student Solutions Manual for ... Access Card for Zumdahl/Zumdahl/DeCoste
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