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(a)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(a)
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Answer to Problem 89E
The formula of sodium oxide is
Explanation of Solution
To determine: The formula of sodium oxide.
The formula of sodium oxide is
The oxidation state of sodium is
Oxygen is an anion having oxidation state
So, the formula of the given compound is
(b)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(b)
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Answer to Problem 89E
The formula of sodium peroxide is
Explanation of Solution
To determine: The formula of sodium peroxide.
The formula of sodium peroxide is
The oxidation state of sodium is
Oxygen is an anion having oxidation state
Sodium peroxide is formed when two sodium and oxygen atoms is combined together.
So, the formula of the given compound is
(c)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(c)
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Answer to Problem 89E
The formula of potassium cyanide is
Explanation of Solution
To determine: The formula of potassium cyanide
The formula of potassium cyanide is
The oxidation state of potassium is
Cyanide
So, the formula of the given compound is
(d)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(d)
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Answer to Problem 89E
The formula of copper (II) nitrate is
Explanation of Solution
To determine: The formula of copper (II) nitrate
The formula of copper (II) nitrate is
The oxidation state of copper is
Nitrate
So, the formula of the given compound is
(e)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(e)
![Check Mark](/static/check-mark.png)
Answer to Problem 89E
The formula of selenium tetrabromide is
Explanation of Solution
To determine: The formula of selenium tetrabromide.
The formula of selenium tetrabromide is
The oxidation state of selenium is
Bromine is an anion having oxidation state
So, the formula of the given compound is
(f)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(f)
![Check Mark](/static/check-mark.png)
Answer to Problem 89E
The formula of iodous acid is
Explanation of Solution
To determine: The formula of iodous acid
The formula of iodous acid is
The oxidation state of hydrogen cation is
Iodite
So, the formula of the given compound is
(g)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(g)
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Answer to Problem 89E
The formula of lead (IV) sulfide is
Explanation of Solution
To determine: The formula of of lead (IV) sulfide.
The formula of lead (IV) sulfide is
The oxidation state of lead
Sulfide is an anion having oxidation state
So, the formula of the given compound is
(h)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(h)
![Check Mark](/static/check-mark.png)
Answer to Problem 89E
The formula of copper (I) chloride is
Explanation of Solution
To determine: The formula of copper (I) chloride.
The formula of copper (I) chloride is
The oxidation state of copper
Chlorine
So, the formula of the given compound is
(i)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(i)
![Check Mark](/static/check-mark.png)
Answer to Problem 89E
The formula of gallium arsenide is
Explanation of Solution
To determine: The formula of gallium arsenide
The formula of gallium arsenide is
The oxidation state of gallium
Arsenic
So, the formula of the given compound is
(j)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(j)
![Check Mark](/static/check-mark.png)
Answer to Problem 89E
The formula of cadmium selenide is
Explanation of Solution
To determine: The formula of cadmium selenide.
The formula of cadmium selenide is
The oxidation state of cadmium
Selenium
So, the formula of the given compound is
(k)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(k)
![Check Mark](/static/check-mark.png)
Answer to Problem 89E
The formula of zinc sulfide is
Explanation of Solution
To determine: The formula of of zinc sulfide.
The formula of zinc sulfide is
The oxidation state of zinc
Sulfide is an anion having oxidation state
So, the formula of the given compound is
(l)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(l)
![Check Mark](/static/check-mark.png)
Answer to Problem 89E
The formula of nitrous acid is
Explanation of Solution
To determine: The formula of of nitrous acid.
The formula of nitrous acid is
The oxidation state of hydrogen
Nitrous
So, the formula of the given compound is
(m)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(m)
![Check Mark](/static/check-mark.png)
Answer to Problem 89E
The formula of diphosphorous pentaoxide is
Explanation of Solution
To determine: The formula of of diphosphorous pentaoxide.
The formula of diphosphorous pentaoxide is
The oxidation state of phosphorous
Oxygen is an anion having oxidation state
So, the formula of the given compound is
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Chapter 2 Solutions
Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition
- Don't used hand raiting and don't used Ai solutionarrow_forward* How many milliliters of 97.5(±0.5) wt% H2SO4 with a density of 1.84(±0.01) g/mL will you need to prepare 2.000 L of 0.110 M H2SO4? * If the uncertainty in delivering H2SO4 is ±0.01 mL, calculate the absolute uncertainty in the molarity (0.110 M). Assume there is negligible uncertainty in the formula mass of NaOH and in the final volume (2.000 L) and assume random error.arrow_forwardYou are tasked with creating a calibration curve for the absorbance of cobalt solutions of various concentrations. You must prepare 5 standards with concentrations between 1.00 mg/L and 10.0 mg/L Co2+. You have a stock solution with a concentration of 40 mg/L Co2+ and all the standard lab glassware including transfer pipets and flasks. Explain how you would make your 5 standard solutions of various concentrations, including what glassware you would use to measure and prepare each solution.arrow_forward
- Predict the product and write the mechanism. CH3-CH=CH-CH2-CH3 + NBS- hv CCl4arrow_forwardHow exactly is carbon disulfide used in industry? Specifically, where does it come in during rubber or textile production and what is the chemical processes?arrow_forwardA researcher has developed a new analytical method to determine the percent by mass iron in solids. To test the new method, the researcher purchases a standard reference material sample that is 2.85% iron by mass. Analysis of the iron standard with the new method returns values of 2.75%, 2.89%, 2.77%, 2.81%, and 2.87%. Does the new method produce a result that is significantly different from the standard value at the 95% confidence level?arrow_forward
- Create a drawing of an aceral with at least 2 isopropoxy groups, and a total of 11 carbon atomsarrow_forward4. Predict the major product(s) for each of the following reactions. HBr (1 equiv.) peroxide, A a. b. NBS, peroxide, Aarrow_forwardIn addition to the separation techniques used in this lab (magnetism, evaporation, and filtering), there are other commonly used separation techniques. Some of these techniques are:Distillation – this process is used to separate components that have significantly different boiling points. The solution is heated and the lower boiling point substance is vaporized first. The vapor can be collected and condensed and the component recovered as a pure liquid. If the temperature of the mixture is then raised, the next higher boiling component will come off and be collected. Eventually only non-volatile components will be left in the original solution.Centrifugation – a centrifuge will separate mixtures based on their mass. The mixture is placed in a centrifuge tube which is then spun at a high speed. Heavier components will settle at the bottom of the tube while lighter components will be at the top. This is the technique used to separate red blood cells from blood plasma.Sieving – this is…arrow_forward
- Living By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax
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