
(a)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(a)

Answer to Problem 89E
The formula of sodium oxide is
Explanation of Solution
To determine: The formula of sodium oxide.
The formula of sodium oxide is
The oxidation state of sodium is
Oxygen is an anion having oxidation state
So, the formula of the given compound is
(b)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(b)

Answer to Problem 89E
The formula of sodium peroxide is
Explanation of Solution
To determine: The formula of sodium peroxide.
The formula of sodium peroxide is
The oxidation state of sodium is
Oxygen is an anion having oxidation state
Sodium peroxide is formed when two sodium and oxygen atoms is combined together.
So, the formula of the given compound is
(c)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(c)

Answer to Problem 89E
The formula of potassium cyanide is
Explanation of Solution
To determine: The formula of potassium cyanide
The formula of potassium cyanide is
The oxidation state of potassium is
Cyanide
So, the formula of the given compound is
(d)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(d)

Answer to Problem 89E
The formula of copper (II) nitrate is
Explanation of Solution
To determine: The formula of copper (II) nitrate
The formula of copper (II) nitrate is
The oxidation state of copper is
Nitrate
So, the formula of the given compound is
(e)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(e)

Answer to Problem 89E
The formula of selenium tetrabromide is
Explanation of Solution
To determine: The formula of selenium tetrabromide.
The formula of selenium tetrabromide is
The oxidation state of selenium is
Bromine is an anion having oxidation state
So, the formula of the given compound is
(f)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(f)

Answer to Problem 89E
The formula of iodous acid is
Explanation of Solution
To determine: The formula of iodous acid
The formula of iodous acid is
The oxidation state of hydrogen cation is
Iodite
So, the formula of the given compound is
(g)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(g)

Answer to Problem 89E
The formula of lead (IV) sulfide is
Explanation of Solution
To determine: The formula of of lead (IV) sulfide.
The formula of lead (IV) sulfide is
The oxidation state of lead
Sulfide is an anion having oxidation state
So, the formula of the given compound is
(h)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(h)

Answer to Problem 89E
The formula of copper (I) chloride is
Explanation of Solution
To determine: The formula of copper (I) chloride.
The formula of copper (I) chloride is
The oxidation state of copper
Chlorine
So, the formula of the given compound is
(i)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(i)

Answer to Problem 89E
The formula of gallium arsenide is
Explanation of Solution
To determine: The formula of gallium arsenide
The formula of gallium arsenide is
The oxidation state of gallium
Arsenic
So, the formula of the given compound is
(j)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(j)

Answer to Problem 89E
The formula of cadmium selenide is
Explanation of Solution
To determine: The formula of cadmium selenide.
The formula of cadmium selenide is
The oxidation state of cadmium
Selenium
So, the formula of the given compound is
(k)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(k)

Answer to Problem 89E
The formula of zinc sulfide is
Explanation of Solution
To determine: The formula of of zinc sulfide.
The formula of zinc sulfide is
The oxidation state of zinc
Sulfide is an anion having oxidation state
So, the formula of the given compound is
(l)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(l)

Answer to Problem 89E
The formula of nitrous acid is
Explanation of Solution
To determine: The formula of of nitrous acid.
The formula of nitrous acid is
The oxidation state of hydrogen
Nitrous
So, the formula of the given compound is
(m)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(m)

Answer to Problem 89E
The formula of diphosphorous pentaoxide is
Explanation of Solution
To determine: The formula of of diphosphorous pentaoxide.
The formula of diphosphorous pentaoxide is
The oxidation state of phosphorous
Oxygen is an anion having oxidation state
So, the formula of the given compound is
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Chapter 2 Solutions
Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition
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- What is the skeletal structure of the product of the following organic reaction?arrow_forwardIf a reaction occurs, what would be the major products? Please include a detailed explanation as well as a drawing showing how the reaction occurs and what the final product is.arrow_forwardWhat is the major organic product of the following nucleophilic acyl substitution reaction of an acid chloride below?arrow_forward
- Living By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax





