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(a)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(a)
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Answer to Problem 89E
The formula of sodium oxide is
Explanation of Solution
To determine: The formula of sodium oxide.
The formula of sodium oxide is
The oxidation state of sodium is
Oxygen is an anion having oxidation state
So, the formula of the given compound is
(b)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(b)
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Answer to Problem 89E
The formula of sodium peroxide is
Explanation of Solution
To determine: The formula of sodium peroxide.
The formula of sodium peroxide is
The oxidation state of sodium is
Oxygen is an anion having oxidation state
Sodium peroxide is formed when two sodium and oxygen atoms is combined together.
So, the formula of the given compound is
(c)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(c)
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Answer to Problem 89E
The formula of potassium cyanide is
Explanation of Solution
To determine: The formula of potassium cyanide
The formula of potassium cyanide is
The oxidation state of potassium is
Cyanide
So, the formula of the given compound is
(d)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(d)
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Answer to Problem 89E
The formula of copper (II) nitrate is
Explanation of Solution
To determine: The formula of copper (II) nitrate
The formula of copper (II) nitrate is
The oxidation state of copper is
Nitrate
So, the formula of the given compound is
(e)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(e)
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Answer to Problem 89E
The formula of selenium tetrabromide is
Explanation of Solution
To determine: The formula of selenium tetrabromide.
The formula of selenium tetrabromide is
The oxidation state of selenium is
Bromine is an anion having oxidation state
So, the formula of the given compound is
(f)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(f)
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Answer to Problem 89E
The formula of iodous acid is
Explanation of Solution
To determine: The formula of iodous acid
The formula of iodous acid is
The oxidation state of hydrogen cation is
Iodite
So, the formula of the given compound is
(g)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(g)
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Answer to Problem 89E
The formula of lead (IV) sulfide is
Explanation of Solution
To determine: The formula of of lead (IV) sulfide.
The formula of lead (IV) sulfide is
The oxidation state of lead
Sulfide is an anion having oxidation state
So, the formula of the given compound is
(h)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(h)
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Answer to Problem 89E
The formula of copper (I) chloride is
Explanation of Solution
To determine: The formula of copper (I) chloride.
The formula of copper (I) chloride is
The oxidation state of copper
Chlorine
So, the formula of the given compound is
(i)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(i)
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Answer to Problem 89E
The formula of gallium arsenide is
Explanation of Solution
To determine: The formula of gallium arsenide
The formula of gallium arsenide is
The oxidation state of gallium
Arsenic
So, the formula of the given compound is
(j)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(j)
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Answer to Problem 89E
The formula of cadmium selenide is
Explanation of Solution
To determine: The formula of cadmium selenide.
The formula of cadmium selenide is
The oxidation state of cadmium
Selenium
So, the formula of the given compound is
(k)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(k)
![Check Mark](/static/check-mark.png)
Answer to Problem 89E
The formula of zinc sulfide is
Explanation of Solution
To determine: The formula of of zinc sulfide.
The formula of zinc sulfide is
The oxidation state of zinc
Sulfide is an anion having oxidation state
So, the formula of the given compound is
(l)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(l)
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Answer to Problem 89E
The formula of nitrous acid is
Explanation of Solution
To determine: The formula of of nitrous acid.
The formula of nitrous acid is
The oxidation state of hydrogen
Nitrous
So, the formula of the given compound is
(m)
Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(m)
![Check Mark](/static/check-mark.png)
Answer to Problem 89E
The formula of diphosphorous pentaoxide is
Explanation of Solution
To determine: The formula of of diphosphorous pentaoxide.
The formula of diphosphorous pentaoxide is
The oxidation state of phosphorous
Oxygen is an anion having oxidation state
So, the formula of the given compound is
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Chapter 2 Solutions
Student Solutions Manual for Zumdahl/Zumdahl/DeCoste?s Chemistry, 10th Edition
- NH2 1. CH3–MgCl 2. H3O+ ? As the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C - C bond as its major product: If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new C - C bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new C - C bond. Х ☐: Carrow_forwardPredict the major products of this organic reaction. If there will be no major products, check the box under the drawing area instead. No reaction. : + Х è OH K Cr O 2 27 2 4' 2 Click and drag to start drawing a structure.arrow_forwardLaminar compounds are characterized by havinga) a high value of the internal surface of the solid.b) a high adsorption potential.arrow_forward
- Intercalation compounds have their sheetsa) negatively charged.b) positively charged.arrow_forwardIndicate whether the following two statements are correct or not:- Polythiazine, formed by N and S, does not conduct electricity- Carbon can have a specific surface area of 3000 m2/garrow_forwardIndicate whether the following two statements are correct or not:- The S8 heterocycle is the origin of a family of compounds- Most of the elements that give rise to stable heterocycles belong to group d.arrow_forward
- Living By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHERIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningWorld of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage LearningChemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax
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