PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS
6th Edition
ISBN: 9781429206099
Author: Tipler
Publisher: MAC HIGHER
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 2, Problem 88P

(a)

To determine

Minimum negative acceleration to avoid collision.

(a)

Expert Solution
Check Mark

Answer to Problem 88P

Minimum negative acceleration to avoid collision is 0.75m/s2 .

Explanation of Solution

Given:

Velocity of passenger train is 29m/s .

Separation between passenger and freight train when engineer sees it is 360m .

Velocity of freight train is 6m/s .

Reaction time of engineer is 0.4s

Formula used:

Write the expression for relative velocity.

  vir=(v1v2)  ........(1)

Here, vir is initial relative velocity, v1 is velocity of passenger train and v2 is velocity of freight train

Write the expression for distance covered between them during reaction time .

  s=(v1v2)tr  ........(2)

Here, s is distance covered between them during reaction time and tr is reaction time

Write the expression for remaining distance between trainsafter reaction time

  s1=(360s)  ........(3)

Here, s1 is remaining distance between trains after reaction time.

Write the expression for final relative velocity between the trains

  vrf2=(vri22amins1)  ........(4)

Here, vrf is final relative velocity which will be equal to zero in the case.

Calculation:

Substitute 29m/s for v1 and 6m/s for v2 in equation (1).

  vir=(296)vir=23m/s .

Substitute 29m/s for v1 , 6m/s for v2 and 0.4s for tr in equation (2).

  s=(296)0.4s=9.2m .

Substitute 9.2m for s in equation (3)

  s1=(3609.2)s1=350.8m

Substitute 23m/s for vir and 350.8m for s1 in equation (4)

  0=2322(amin)(350.8)amin=0.75m/s2

Conclusion:

Thus, the minimum negative acceleration to avoid collision is 0.75m/s2

(b)

To determine

Velocity of passenger train at minimum acceleration to avoid collision

(b)

Expert Solution
Check Mark

Answer to Problem 88P

Velocity of passenger train at minimum acceleration to avoid collision is 10.07m/s .

Explanation of Solution

Given:

Reaction time is 0.8s

Formula used:

Write expression for distance remaining between trains after reaction time

  s2=360(v1v2)tr  ........(5)

Here, s2 is distance remaining between trains after reaction time and tr is reaction time.

Write expression for final relative velocity.

  vfr=vir2as2  ........(6)

Here, vfr is final relative velocity.

Write expression for final relative velocity.

  vfr=v1v2  ........(7)

Calculation:

Substitute 29m/s for v1 and 6m/s for v2 and 0.8s for tr in equation (5)

  s2=360(23)0.8s2=341.6m .

Substitute 23m/s for vir , 0.75m/s2 for a and 341.6m for s2 in equation (6)

  vfr= 2322(0.75)(341.6)vfr=4.07m/s .

Substitute 4.07m/s for vfr and 6m/s for v2 in equation (7)

  4.07=v16v1=10.07m/s

Conclusion:

Thus, the velocity of passenger train at minimum acceleration to avoid collision is 10.07m/s .

(c)

To determine

Distance covered by passenger train between sighting and collision

(c)

Expert Solution
Check Mark

Answer to Problem 88P

The distance covered by passenger train between sighting and collision is 516.16m .

Explanation of Solution

Formula used:

Write the expression for time when train just collides.

  s2=virt12(0.75t2)  ........(8)

Write the expression for distance covered by passenger train between sighting and collision

  s3=v1(t+tr)12at2  ........(9)

Here, s3 is distance covered by passenger train between sighting and collision, t is time when train just collides.

Calculation:

Substitute 341.6m for s2 and 23m/s for vir in equation (8)

  341.6=23t12(0.75t2)t=25.23s .

Substitute 29m/s for v1 , 25.23s for t and 0.8s for tr in equation (9).

  s3=29(25.23+0.8)12(0.75)(25.23)2s3=516.16m

Conclusion:

Distance covered by passenger train between sighting and collision is 516.16m .

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Given: ruler 11.56 g, small washer 1.85 g each, large washer 24.30g each Use the data in Data Tables 4 and 5 to experimentally determine the mass of your ruler.  Use one of your 2 trials with 1 small washer at 0 cm, one of your 2 trials with 2 small washers at 0 cm, and one of your 2 trials with 3 small washers at 0 cm to find three experimental values for the mass of the ruler. How do you experimentalls determine the mass?
Compare the 3 experimental masses of your ruler to the measured mass of your ruler (Data Table 1) by calculating the percent error for each experimental value.  Which trial provided the best data for determining the mass of the ruler? Please help, I am not sure how to calculate this.  Thanks!
Please help, everytime I try to input the data only one point shows on the graph. Please graph unsing centripetal force, Fc,  versus V E2 from Activity 1. Include a line of best fit and record the equation of the line. Thank you!

Chapter 2 Solutions

PHYSICS F/SCI.+ENGRS.,STAND.-W/ACCESS

Ch. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86PCh. 2 - Prob. 87PCh. 2 - Prob. 88PCh. 2 - Prob. 89PCh. 2 - Prob. 90PCh. 2 - Prob. 91PCh. 2 - Prob. 92PCh. 2 - Prob. 93PCh. 2 - Prob. 94PCh. 2 - Prob. 95PCh. 2 - Prob. 96PCh. 2 - Prob. 97PCh. 2 - Prob. 98PCh. 2 - Prob. 99PCh. 2 - Prob. 100PCh. 2 - Prob. 101PCh. 2 - Prob. 102PCh. 2 - Prob. 103PCh. 2 - Prob. 104PCh. 2 - Prob. 105PCh. 2 - Prob. 106PCh. 2 - Prob. 107PCh. 2 - Prob. 108PCh. 2 - Prob. 109PCh. 2 - Prob. 110PCh. 2 - Prob. 111PCh. 2 - Prob. 112PCh. 2 - Prob. 113PCh. 2 - Prob. 114PCh. 2 - Prob. 115PCh. 2 - Prob. 116PCh. 2 - Prob. 117PCh. 2 - Prob. 118PCh. 2 - Prob. 119PCh. 2 - Prob. 120PCh. 2 - Prob. 121PCh. 2 - Prob. 122P
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
Text book image
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Text book image
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Relative Velocity - Basic Introduction; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=_39hCnqbNXM;License: Standard YouTube License, CC-BY