
(a)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(a)

Answer to Problem 87E
The formula of sulfur difluoride is
Explanation of Solution
To determine: The formula of of sulfur difluoride
The formula of sulfur difluoride is
Sulfur belongs to the Group
Fluorine is a non-metal of the
Oxidation state
In
(b)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(b)

Answer to Problem 87E
The formula of sulfur hexafluoride is
Explanation of Solution
To determine: The formula of sulfur hexafluoride
The formula of sulfur hexafluoride is
Sulfur belongs to the Group
Fluorine is a non-metal of the
Oxidation state
In
(c)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(c)

Answer to Problem 87E
The formula of
Explanation of Solution
To determine: The formula of
The formula of
Sodium belongs to the Group
Dihydrogen phosphate is an anion having oxidation state
So, the formula of the given compound is
(d)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(d)

Answer to Problem 87E
The formula of lithium nitride is
Explanation of Solution
To determine: The formula of lithium nitride
The formula of lithium nitride is
Lithium belongs to the Group
Nitrogen is a non-metal of the
Oxidation state
So, the formula of the given compound is
(e)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(e)

Answer to Problem 87E
The formula of chromium (III) carbonate is
Explanation of Solution
To determine: The formula of chromium (III) carbonate.
The formula of chromium (III) carbonate is
Chromium belongs to the Group
Carbonate is an anion having oxidation state
So, the formula of the given compound is
(f)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(f)

Answer to Problem 87E
The formula of tin (II) fluoride is
Explanation of Solution
To determine: The formula of tin (II) fluoride.
The formula of tin (II) fluoride is
Tin belongs to the Group
Fluorine is a non-metal of the
Oxidation state
So, the formula of the given compound is
(g)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(g)

Answer to Problem 87E
The formula of ammonium acetate is
Explanation of Solution
To determine: The formula of ammonium acetate.
The formula of ammonium acetate is
The oxidation state of ammonium
Acetate
So, the formula of the given compound is
(h)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(h)

Answer to Problem 87E
The formula of ammonium hydrogen sulfate is
Explanation of Solution
To determine: The formula of ammonium hydrogen sulfate.
The formula of ammonium hydrogen sulfate is
The oxidation state of ammonium
Hydrogen sulfate
So, the formula of the given compound is
(i)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(i)

Answer to Problem 87E
The formula of cobalt (III) nitrate.is
Explanation of Solution
To determine: The formula of cobalt (III) nitrate.
The formula of cobalt (III) nitrate.is
The oxidation state of cobalt
Nitrate
So, the formula of the given compound is
(j)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(j)

Answer to Problem 87E
The formula of mercury (I) chloride is
Explanation of Solution
To determine: The formula of mercury (I) chloride.
The formula of mercury (I) chloride is
The oxidation state of mercury
Chloride
Two mercury and chlorine ions is joined to form mercury (I) chloride.
So, the formula of the given compound is
(k)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(k)

Answer to Problem 87E
The formula of potassium chlorate is
Explanation of Solution
To determine: The formula of potassium chlorate.
The formula of potassium chlorate is
The oxidation state of potassium
Chlorate
So, the formula of the given compound is
(l)
Interpretation:
The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction:
The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
(l)

Answer to Problem 87E
The formula of sodium hydride is
Explanation of Solution
To determine: The formula of sodium hydride.
The formula of sodium hydride is
The oxidation state of sodium
Hydride
So, the formula of the given compound is
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Chapter 2 Solutions
Lab Manual for Zumdahl/Zumdahl/DeCoste¿s Chemistry, 10th Edition
- For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Molecule Inductive Effects O donating O withdrawing O no inductive effects Resonance Effects Overall Electron-Density ○ donating ○ withdrawing O no resonance effects O electron-rich O electron-deficient O similar to benzene Cl O donating O withdrawing ○ donating ○ withdrawing O no inductive effects O no resonance effects O Explanation Check O electron-rich O electron-deficient similar to benzene X © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessarrow_forwardIdentifying electron-donating and For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Molecule Inductive Effects NH2 ○ donating NO2 Explanation Check withdrawing no inductive effects Resonance Effects Overall Electron-Density ○ donating O withdrawing O no resonance effects O donating O withdrawing O donating withdrawing O no inductive effects Ono resonance effects O electron-rich electron-deficient O similar to benzene O electron-rich O electron-deficient O similar to benzene olo 18 Ar 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibilityarrow_forwardRank each of the following substituted benzene molecules in order of which will react fastest (1) to slowest (4) by electrophilic aromatic substitution. Explanation Check Х (Choose one) OH (Choose one) OCH3 (Choose one) OH (Choose one) © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forward
- Assign R or S to all the chiral centers in each compound drawn below porat bg 9 Br Brarrow_forwarddescrive the energy levels of an atom and howan electron moces between themarrow_forwardRank each set of substituents using the Cahn-Ingold-Perlog sequence rules (priority) by numbering the highest priority substituent 1.arrow_forward
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