Concept explainers
Write the formula for each of the following compounds:
- a. ammonium hydrogen phosphate
- b. mercury (I) sulfide
- c. silicon dioxide
- d. sodium sulfite
- e. aluminum hydrogen sulfate
- f. nitrogen trichloride
- g. hydiobromic acid
- h. bromous acid
- i. perbromic acid
- j. potassium hydrogen sulfide
- k. calcium iodide
- l. cesium perchlorate
(a)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of ammonium hydrogen phosphate is
Explanation of Solution
To determine: The formula of ammonium hydrogen phosphate.
The oxidation state of ammonium
Hydrogen phosphate
So, the formula of the given compound is
The formula of ammonium hydrogen phosphate is
(b)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of mercury (I) sulfide is
Explanation of Solution
To determine: The formula of mercury (I) sulfide.
The oxidation state of mercury is
Sulfide is an anion having oxidation state
So, the formula of the given compound is
The formula of mercury(I) sulfide is
(c)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of silicon dioxide is
Explanation of Solution
To determine: The formula of silicon dioxide
The oxidation state of silicon is
Dioxide is an anion having oxidation state
So, the formula of the given compound is
The formula of silicon dioxide is
(d)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of sodium sulfite is
Explanation of Solution
To determine: The formula of sodium sulfite
The oxidation state of sodium is
Sulfite
So, the formula of the given compound is
The formula of sodium sulfite is
(e)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of alumunium hydrogen sulfate is
Explanation of Solution
To determine: The formula of alumunium hydrogen sulfate.
The oxidation state of alumunium is
Hydrogen sulfate
So, the formula of the given compound is
The formula of alumunium hydrogen sulfate is
(f)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of nitrogen trichloride is
Explanation of Solution
To determine: The formula of nitrogen trichloride.
The oxidation state of nitrogen is
The oxidation state of chlorine is
So, the formula of the given compound is
The formula of nitrogen trichloride is
(g)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of hydrobromic acid is
Explanation of Solution
To determine: The formula of of hydrobromic acid
The oxidation state of hydrogen
Bromine is an anion having oxidation state
So, the formula of the given compound is
The formula of hydrobromic acid is
(h)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of bromous acid is
Explanation of Solution
To determine: The formula of bromous acid
The oxidation state of hydrogen
Bromite
So, the formula of the given compound is
The formula of bromous acid is
(i)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of perbromic acid is
Explanation of Solution
To determine: The formula of perbromic acid
The oxidation state of hydrogen
Perbromate
So, the formula of the given compound is
The formula of perbromic acid is
(j)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of potassium hydrogen sulfide is
Explanation of Solution
To determine: The formula of potassium hydrogen sulfide
The oxidation state of potassium
Hydrogen sulfide is an anion having oxidation state
So, the formula of the given compound is
The formula of potassium hydrogen sulfide is
(k)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of calcium iodide is
Explanation of Solution
To determine: The formula of of calcium iodide
The oxidation state of calcium
Iodine is an anion having oxidation state
So, the formula of the given compound is
The formula of calcium iodide is
(l)

Interpretation: The formula of the binary compound formed from the given pairs of elements in each case is to be stated.
Concept introduction: The oxidation state of an element corresponds to the group number of that element. In case of non-metals, the oxidation state can be calculated as,
Answer to Problem 86E
The formula of cesium perchlorate is
Explanation of Solution
To determine: The formula of of cesium perchlorate.
The oxidation state of cesium
Perchlorate
So, the formula of the given compound is
The formula of cesium perchlorate is
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Chapter 2 Solutions
Chemistry: AP Edition - Package
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- Identifying electron-donating and electron-withdrawing effects on benzene For each of the substituted benzene molecules below, determine the inductive and resonance effects the substituent will have on the benzene ring, as well as the overall electron-density of the ring compared to unsubstituted benzene. Inductive Effects Resonance Effects Overall Electron-Density Molecule CF3 O donating O donating O withdrawing O withdrawing O no inductive effects O no resonance effects electron-rich electron-deficient O similar to benzene CH3 O donating O withdrawing O no inductive effects O donating O withdrawing Ono resonance effects O electron-rich O electron-deficient O similar to benzene Explanation Check Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forward* Hint: Think back to Chem 1 solubility rules. Follow Up Questions for Part B 12. What impact do the following disturbances to a system at equilibrium have on k, the rate constant for the forward reaction? Explain. (4 pts) a) Changing the concentration of a reactant or product. (2 pts) b) Changing the temperature of an exothermic reaction. (2 pts) ofarrow_forwardDraw TWO general chemical equation to prepare Symmetrical and non-Symmetrical ethers Draw 1 chemical reaction of an etherarrow_forward
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