Chapter 2, Problem 71E

Name the compounds in parts a–d and write the formulas for the compounds in parts e–h.

1. a. NaBr
2. b. Rb₂O
3. c. CaS
4. d. AlI₃
5. e. strontium fluoride
6. f. aluminum selenide
7. g. potassium nitride
8. h. magnesium phosphide

Interpretation Introduction

Interpretation:

The compounds given in parts “a-d” are to be named and the formulas for the compounds in parts “e-h” are to be stated.

Concept introduction:

The chemical bonds are the forces which hold the atoms together in compounds.

• The simplest representation of the molecule is known as a chemical formula.
• The chemical formula of an ionic compound comprises cations and the anions.
• Every element always gets stabilization by getting electronic configuration of the nearest noble gas. Therefore in getting stabilization elements are ionized.
• In the representation of the chemical formula of ionic compound the cation always comes first in the naming while the anion comes last with the ending the term “-ide”.
• In an ionic compound generally cations are metals while anions are non metals.
• The charges present on the cations and on the anions always follow the concept of valency.
• According to the concept of valency the net charge present on an ionic compound must be zero.

Answer to Problem 71E

Answer

The Name of the compound is Sodium bromide.

Explanation of Solution

To determine: The name of the compound $\text{NaBr}$.

Name of the compound is Sodium bromide.

The given formula consists of one Sodium ion and one Bromine ion. In an ionic compound representation cations are always written first and the anions make the root of the element by adding the term “-ide” at the end of the compound.

The charges present on cation and anion must be neutralized with the charges present on each other.

The given $\text{NaBr}$ compound has one ${\text{Na}}^{+}$ cation and one ${\text{Br}}^{-}$ anion so the name of the compound is Sodium bromide

Interpretation Introduction

Interpretation:

The compounds given in parts “a-d” are to be named and the formulas for the compounds in parts “e-h” are to be stated.

Concept introduction:

The chemical bonds are the forces which hold the atoms together in compounds.

• The simplest representation of the molecule is known as a chemical formula.
• The chemical formula of an ionic compound comprises cations and the anions.
• Every element always gets stabilization by getting electronic configuration of the nearest noble gas. Therefore in getting stabilization elements are ionized.
• In the representation of the chemical formula of ionic compound the cation always comes first in the naming while the anion comes last with the ending the term “-ide”.
• In an ionic compound generally cations are metals while anions are non metals.
• The charges present on the cations and on the anions always follow the concept of valency.
• According to the concept of valency the net charge present on an ionic compound must be zero.

Answer to Problem 71E

Answer

Name of the compound is Rubidium oxide.

Explanation of Solution

Explanation

To determine: The name of the compound ${\text{Rb}}_{\text{2}}\text{O}$.

Name of the compound is Rubidium oxide.

The given compound consists of two Rubidium cation $\left({\text{2Rb}}^{\text{+}}\right)$ and one Oxide anion $\left({\text{O}}^{\text{2-}}\right)$. The positive charge present on two Rubidium ion is neutralized with two negative charges present on Oxygen anion.

Hence, the name of the compound is Rubidium oxide

Interpretation Introduction

Interpretation:

The compounds given in parts “a-d” are to be named and the formulas for the compounds in parts “e-h” are to be stated.

Concept introduction:

The chemical bonds are the forces which hold the atoms together in compounds.

• The simplest representation of the molecule is known as a chemical formula.
• The chemical formula of an ionic compound comprises cations and the anions.
• Every element always gets stabilization by getting electronic configuration of the nearest noble gas. Therefore in getting stabilization elements are ionized.
• In the representation of the chemical formula of ionic compound the cation always comes first in the naming while the anion comes last with the ending the term “-ide”.
• In an ionic compound generally cations are metals while anions are non metals.
• The charges present on the cations and on the anions always follow the concept of valency.
• According to the concept of valency the net charge present on an ionic compound must be zero.

Answer to Problem 71E

Answer

Name of the compound is Calcium sulfide.

Explanation of Solution

Explanation

To determine: The name of the compound $\text{CaS}$.

Name of the compound is Calcium sulfide.

The given compound consists of one Calcium cation $\left({\text{Ca}}^{2+}\right)$ and one Sulfide anion $\left({\text{S}}^{2-}\right)$. The two positive charges present on one Calcium cation is neutralized with two negative charges present on one Sulfide anion.

Hence, the name of the compound is Calcium Sulfide.

Interpretation Introduction

Interpretation:

The compounds given in parts “a-d” are to be named and the formulas for the compounds in parts “e-h” are to be stated.

Concept introduction:

The chemical bonds are the forces which hold the atoms together in compounds.

• The simplest representation of the molecule is known as a chemical formula.
• The chemical formula of an ionic compound comprises cations and the anions.
• Every element always gets stabilization by getting electronic configuration of the nearest noble gas. Therefore in getting stabilization elements are ionized.
• In the representation of the chemical formula of ionic compound the cation always comes first in the naming while the anion comes last with the ending the term “-ide”.
• In an ionic compound generally cations are metals while anions are non metals.
• The charges present on the cations and on the anions always follow the concept of valency.
• According to the concept of valency the net charge present on an ionic compound must be zero.

Answer to Problem 71E

Answer

Name of the compound is Aluminum iodide.

Explanation of Solution

Explanation

To determine: The name of the compound ${\text{AlI}}_{\text{3}}$.

Name of the compound is Aluminum iodide.

The given compound consists of one Aluminum cation $\left({\text{Al}}^{3+}\right)$ and three Iodide anion $\left({\text{3I}}^{-}\right)$. The three positive charges present on one Aluminum cation is neutralized with one negative charge present on three iodide anion.

Hence, the name of the compound is Aluminum iodide.

Interpretation Introduction

Interpretation:

The compounds given in parts “a-d” are to be named and the formulas for the compounds in parts “e-h” are to be stated.

Concept introduction:

The chemical bonds are the forces which hold the atoms together in compounds.

• The simplest representation of the molecule is known as a chemical formula.
• The chemical formula of an ionic compound comprises cations and the anions.
• Every element always gets stabilization by getting electronic configuration of the nearest noble gas. Therefore in getting stabilization elements are ionized.
• In the representation of the chemical formula of ionic compound the cation always comes first in the naming while the anion comes last with the ending the term “-ide”.
• In an ionic compound generally cations are metals while anions are non metals.
• The charges present on the cations and on the anions always follow the concept of valency.
• According to the concept of valency the net charge present on an ionic compound must be zero.

Answer to Problem 71E

Answer

Formula of the compound is ${\text{SrF}}_{\text{2}}$.

Explanation of Solution

Explanation

To determine: The formula of the compound Strontium fluoride.

Formula of the compound is “ ${\text{SrF}}_{\text{2}}$”.

The given compound consists of Strontium cation and fluoride anion. As the name of the compound is starting with Strontium so the cation is $\text{Sr}$ and the name is ending with the term “-ide” which shows that fluorine is anion here.

Strontium is present in the second group in the periodic table so by losing two electrons it gets stabilized. Therefore, it becomes ${\text{Sr}}^{2+}$ while Fluorine is present in the ${17}^{\text{th}}$ group in the periodic table; so by gaining one electron it acquires stabilization.

Therefore,  it becomes ${\text{F}}^{-}$. Strontium consist of two positive charge while fluorine consist of single negative charge. Therefore two Fluorine is balanced with the dispositive Strontium ion. On combining the both anion and cation the observed formula of the compound is ${\text{SrF}}_{\text{2}}$.

Interpretation Introduction

Interpretation:

The compounds given in parts “a-d” are to be named and the formulas for the compounds in parts “e-h” are to be stated.

Concept introduction:

The chemical bonds are the forces which hold the atoms together in compounds.

• The simplest representation of the molecule is known as a chemical formula.
• The chemical formula of an ionic compound comprises cations and the anions.
• Every element always gets stabilization by getting electronic configuration of the nearest noble gas. Therefore in getting stabilization elements are ionized.
• In the representation of the chemical formula of ionic compound the cation always comes first in the naming while the anion comes last with the ending the term “-ide”.
• In an ionic compound generally cations are metals while anions are non metals.
• The charges present on the cations and on the anions always follow the concept of valency.
• According to the concept of valency the net charge present on an ionic compound must be zero.

Answer to Problem 71E

Answer

Formula of the compound is ${\text{Al}}_{\text{2}}{\text{Se}}_{\text{3}}$.

Explanation of Solution

Explanation

To determine: The formula of the compound Aluminum selenide.

Formula of the compound is ${\text{Al}}_{\text{2}}{\text{Se}}_{\text{3}}$.

The given compound consists of Aluminum cation and Selenium anion. As the name of the compound is starting with Aluminum so the cation is $\text{Al}$ and the name is ending with the term “-ide” which shows that Selenium is anion here. Aluminum present in the ${13}^{\text{th}}$  group in the periodic table so by losing three electrons it gets stabilization. Therefore it becomes ${\text{Al}}^{3+}$ while Selenium is present in the ${16}^{\text{th}}$ group in the periodic table so by gaining two electrons it get stabilization. Therefore it becomes ${\text{Se}}^{2+}$. Aluminum consist of two positive charge while fluorine consist of single negative charge. Therefore two Fluorine is balanced with the dispositive Strontium ion. On combining the both anion and cation the observed formula of the compound is ${\text{SrF}}_{\text{2}}$

Interpretation Introduction

Interpretation:

The compounds given in parts “a-d” are to be named and the formulas for the compounds in parts “e-h” are to be stated.

Concept introduction:

The chemical bonds are the forces which hold the atoms together in compounds.

• The simplest representation of the molecule is known as a chemical formula.
• The chemical formula of an ionic compound comprises cations and the anions.
• Every element always gets stabilization by getting electronic configuration of the nearest noble gas. Therefore in getting stabilization elements are ionized.
• In the representation of the chemical formula of ionic compound the cation always comes first in the naming while the anion comes last with the ending the term “-ide”.
• In an ionic compound generally cations are metals while anions are non metals.
• The charges present on the cations and on the anions always follow the concept of valency.
• According to the concept of valency the net charge present on an ionic compound must be zero.

Answer to Problem 71E

Answer

Formula of the compound is ${\text{K}}_{\text{3}}\text{N}$.

Explanation of Solution

Explanation

To determine: The formula of the compound Potassium nitride.

Formula of the compound is “ ${\text{K}}_{\text{3}}\text{N}$”.

The given compound consists of Potassium cation and Nitride anion. As the name of the compound is starting with Potassium so the cation is $\text{K}$ and the name is ending with the term “-ide” which shows that Nitrogen is anion here. On balancing the both anion and cation the observed formula of the compound is ${\text{K}}_{\text{3}}\text{N}$.

Interpretation Introduction

Interpretation:

The compounds given in parts “a-d” are to be named and the formulas for the compounds in parts “e-h” are to be stated.

Concept introduction:

The chemical bonds are the forces which hold the atoms together in compounds.

• The simplest representation of the molecule is known as a chemical formula.
• The chemical formula of an ionic compound comprises cations and the anions.
• Every element always gets stabilization by getting electronic configuration of the nearest noble gas. Therefore in getting stabilization elements are ionized.
• In the representation of the chemical formula of ionic compound the cation always comes first in the naming while the anion comes last with the ending the term “-ide”.
• In an ionic compound generally cations are metals while anions are non metals.
• The charges present on the cations and on the anions always follow the concept of valency.
• According to the concept of valency the net charge present on an ionic compound must be zero.

Answer to Problem 71E

Answer

Formula of the compound is ${\text{Mg}}_{\text{3}}{\text{P}}_{\text{2}}$.

Explanation of Solution

Explanation

To determine: The formula of the compound Magnesium phosphide.

Formula of the compound is “ ${\text{Mg}}_{\text{3}}{\text{P}}_{\text{2}}$”.

The given compound consists of Magnesium cation and phosphide anion. As the name of the compound is starting with Magnesium so the cation is ${\text{Mg}}^{2+}$ and the name is ending with the term “-ide” which shows that phosphorous is anion $\left({\text{P}}^{3-}\right)$ here. On balancing the both anion and cation the observed formula of the compound is ${\text{Mg}}_{\text{3}}{\text{P}}_{\text{2}}$.