Java Programming
9th Edition
ISBN: 9780357238530
Author: Joyce Farrell
Publisher: Cengage Limited
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Expert Solution & Answer
Chapter 2, Problem 6RQ
Program Description Answer
The data type that can store the value 0 using least amount of memory is “Byte”.
Hence, the correct answer is option “D”.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
Consider a file currently consisting of 10 blocks. Assume that the file control block and the new block
information to be added are already in memory. Calculate how many disk I/O operations are required for the
linked allocation strategy, if, for one block, the following conditions hold:
HINTS: 1) ignore disk I/O associated with the file control block. 2) each read and each write is an explicit disk
I/O. 3) assume a pointer to the end of the list for linked allocation
a. The block is added at the beginning.
b. The block is added in the middle.
c. The block is added at the end.
d. The block is removed from the beginning.
e. The block is removed from the middle.
f. The block is removed from the end.
Segment Base (original)
Length
Base (after compaction)
0
100
300
1
1400
600
2
450
100
3
3200
80
4
2200
500
5
3300
33
1. Given the original base addresses, what are the physical addresses for the following logical addresses? If
it's an invalid address, just write "invalid". Note that (X, Y) => segment X, offset Y
a) (0,350)
b) (1,599)
c) (2,50)
d) (3,81)
e) (4,300)
f) (5.0)
g) (5,34)
Process
Allocation
A
Max
BCDABC
D
A
Available
B C
PO
3
0
2
1
4
2
4
2
1
0 0
P1
0
1
0
1
0
2
2
2
P2
1
2
0
0
3
2
1
0
P3
0
1
1
2
1
1
1
2
P4
0
0 1
1
1
-
0
2
1
a) What is the content of the matrix Need?
Process
PO
P1
P2
P3
P4
A
Need
BC
D
D
°
b) Is the system in a safe state? If yes, give a safe sequence of processes. If not, explain why the system is
not in a safe state.
c) If a request from process P4 arrives for (1,0,0,0), can the request be granted immediately? Please state the
reason.
Chapter 2 Solutions
Java Programming
Ch. 2 - Prob. 1RQCh. 2 - Prob. 2RQCh. 2 - Prob. 3RQCh. 2 - Prob. 4RQCh. 2 - Prob. 5RQCh. 2 - Prob. 6RQCh. 2 - Prob. 7RQCh. 2 - Prob. 8RQCh. 2 - Prob. 9RQCh. 2 - Prob. 10RQ
Ch. 2 - Prob. 11RQCh. 2 - Prob. 12RQCh. 2 - Prob. 13RQCh. 2 - Prob. 14RQCh. 2 - Prob. 15RQCh. 2 - Prob. 16RQCh. 2 - Prob. 17RQCh. 2 - Prob. 18RQCh. 2 - Prob. 19RQCh. 2 - Prob. 20RQCh. 2 - Prob. 1PECh. 2 - Prob. 2PECh. 2 - Prob. 4PECh. 2 - Prob. 5PECh. 2 - Prob. 6PECh. 2 - Prob. 7PECh. 2 - Prob. 8PECh. 2 - Prob. 9PECh. 2 - Prob. 10PECh. 2 - Prob. 11PECh. 2 - Prob. 12PECh. 2 - Prob. 13PECh. 2 - Prob. 14PECh. 2 - Prob. 15PECh. 2 - Prob. 16PECh. 2 - Prob. 1GZCh. 2 - Prob. 3GZCh. 2 - Prob. 1CPCh. 2 - Prob. 2CP
Knowledge Booster
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