Java Programming
9th Edition
ISBN: 9780357238530
Author: Joyce Farrell
Publisher: Cengage Limited
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Chapter 2, Problem 1PE
a. Evaluate the expression, 4 + 6 * 2
Program Plan Intro
Operator Precedence:
An expression is a statement, which will hold a value when it is evaluated. A mathematical expression will hold multiple operators and grouping symbols; an expression will be evaluated based on the precedence of the operator. The rules of the operator precedence are given below.
- Unary negation (-) and brackets () will have the highest priority.
- Multiplication (*), division (/) and modulus (%) will have the next highest priority.
- Addition (+), subtraction (-) will have the lowest priority.
b. Evaluate the expression, 10 / 5 + 8
Explanation of Solution
In the above expression, the division “/” operation will be evaluated first and next “+” addition operation will be executed as shown below:
St...
c. Evaluate the expression, 12 / 4 + 16 / 2
Explanation of Solution
In the above expression, the division “/” operation will be evaluated first and next “+” addition operation will be executed as shown below:
Step 1:
�...
d. Evaluate the expression, 17 / 2
Explanation of Solution
In the above expression, the division “/” operation will be evaluated first and the quotient is returned as the result as shown b...
e. Evaluate the expression, 22 / 5
Explanation of Solution
In the above expression, the division “/” operation will be evaluated first and the quotient is returned as the result as shown b...
f. Evaluate the expression, 39 / 10
Explanation of Solution
In the above expression, the division “/” operation will be evaluated first and the quotient is returned as the result as shown be...
g. Evaluate the expression, 19 % (2 + 3)
Explanation of Solution
In the above expression, the values inside the brackets are evaluated first and then modulus (%) operator is evaluated and the remainder is returned as a result as shown below:
...h. Evaluate the expression, 3 + 4 * 20 / 3
Explanation of Solution
In the above expression, the multiplication “*” operation will be evaluated first, next division “/” operation is evaluated and at last, addition “+”operation will be evaluated as shown below:
...i. Evaluate the expression, 36 % (6 + 2)
Explanation of Solution
In the above expression, the values inside the brackets are evaluated first and then modulus (%) operator is evaluated and the remainder is returned as a result as shown below:
...j. Evaluate the expression, 8 % 2 * 0
Explanation of Solution
In the above expression, the values inside the brackets are evaluated first and then modulus (%) operator is evaluated and the remainder is returned as a result as shown below:
...
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Chapter 2 Solutions
Java Programming
Ch. 2 - Prob. 1RQCh. 2 - Prob. 2RQCh. 2 - Prob. 3RQCh. 2 - Prob. 4RQCh. 2 - Prob. 5RQCh. 2 - Prob. 6RQCh. 2 - Prob. 7RQCh. 2 - Prob. 8RQCh. 2 - Prob. 9RQCh. 2 - Prob. 10RQ
Ch. 2 - Prob. 11RQCh. 2 - Prob. 12RQCh. 2 - Prob. 13RQCh. 2 - Prob. 14RQCh. 2 - Prob. 15RQCh. 2 - Prob. 16RQCh. 2 - Prob. 17RQCh. 2 - Prob. 18RQCh. 2 - Prob. 19RQCh. 2 - Prob. 20RQCh. 2 - Prob. 1PECh. 2 - Prob. 2PECh. 2 - Prob. 4PECh. 2 - Prob. 5PECh. 2 - Prob. 6PECh. 2 - Prob. 7PECh. 2 - Prob. 8PECh. 2 - Prob. 9PECh. 2 - Prob. 10PECh. 2 - Prob. 11PECh. 2 - Prob. 12PECh. 2 - Prob. 13PECh. 2 - Prob. 14PECh. 2 - Prob. 15PECh. 2 - Prob. 16PECh. 2 - Prob. 1GZCh. 2 - Prob. 3GZCh. 2 - Prob. 1CPCh. 2 - Prob. 2CP
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