Program plan: The variable Fof type float is declared and initialized with value 4 to store force in N. The variable k of type float is declared and initialized with value 1000 given. The variable l of type float is declared and initialized after converting 3 meters to mm to store the length of rectangular slab. The variable w of type float is declared and initialized after converting 4 cm to mm to store the width of rectangular slab. The variable d of type float is declared and initialized to value 2 to store the width of rectangular slab. The variable e of type float is declared to accept metal's modulus of elasticity. The variable I of type float is declared to calculate and store the increase in length using the given formula. Program description: The main purpose of the program is to calculate the increase in length when a slab of aluminum that’s 3 meters long, 4 cm wide, and 2 mm deep is subjected to a force of 4 Newton. Aluminum’s modulus of elasticity is 68,950 N/mm 2 . .Manually verifies the result produced by the program when Aluminum’s modulus of elasticity is 68,950 N/mm 2 .

Question

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Answer 1

Question

Chapter 2, Problem 6PP

a.

Program Plan Intro

Program plan:

The variable Fof type float is declared and initialized with value 4 to store force in N.

The variable k of type float is declared and initialized with value 1000 given.

The variable l of type float is declared and initialized after converting 3 meters to mm to store the length of rectangular slab.

The variable w of type float is declared and initialized after converting 4 cm to mm to store the width of rectangular slab.

The variable d of type float is declared and initialized to value 2 to store the width of rectangular slab.

The variable e of type float is declared to accept metal's modulus of elasticity.

The variable I of type float is declared to calculate and store the increase in length using the given formula.

Program description:

The main purpose of the program is to calculate the increase in length when a slab of aluminum that’s 3 meters long, 4 cm wide, and 2 mm deep is subjected to a force of 4 Newton. Aluminum’s modulus of elasticity is 68,950 N/mm².

.Manually verifies the result produced by the program when Aluminum’s modulus of elasticity is 68,950 N/mm².

b.

Program Plan Intro

To check the given program for the test value of copper modulus of elasticity of 110000N/mm².

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Answer 2

Question

Chapter 2, Problem 6PP

a.

Program Plan Intro

Program plan:

The variable Fof type float is declared and initialized with value 4 to store force in N.

The variable k of type float is declared and initialized with value 1000 given.

The variable l of type float is declared and initialized after converting 3 meters to mm to store the length of rectangular slab.

The variable w of type float is declared and initialized after converting 4 cm to mm to store the width of rectangular slab.

The variable d of type float is declared and initialized to value 2 to store the width of rectangular slab.

The variable e of type float is declared to accept metal's modulus of elasticity.

The variable I of type float is declared to calculate and store the increase in length using the given formula.

Program description:

The main purpose of the program is to calculate the increase in length when a slab of aluminum that’s 3 meters long, 4 cm wide, and 2 mm deep is subjected to a force of 4 Newton. Aluminum’s modulus of elasticity is 68,950 N/mm².

.Manually verifies the result produced by the program when Aluminum’s modulus of elasticity is 68,950 N/mm².

b.

Program Plan Intro

To check the given program for the test value of copper modulus of elasticity of 110000N/mm².

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 2, Problem 6PP

a.

Program Plan Intro

Program plan:

The variable Fof type float is declared and initialized with value 4 to store force in N.

The variable k of type float is declared and initialized with value 1000 given.

The variable l of type float is declared and initialized after converting 3 meters to mm to store the length of rectangular slab.

The variable w of type float is declared and initialized after converting 4 cm to mm to store the width of rectangular slab.

The variable d of type float is declared and initialized to value 2 to store the width of rectangular slab.

The variable e of type float is declared to accept metal's modulus of elasticity.

The variable I of type float is declared to calculate and store the increase in length using the given formula.

Program description:

The main purpose of the program is to calculate the increase in length when a slab of aluminum that’s 3 meters long, 4 cm wide, and 2 mm deep is subjected to a force of 4 Newton. Aluminum’s modulus of elasticity is 68,950 N/mm².

.Manually verifies the result produced by the program when Aluminum’s modulus of elasticity is 68,950 N/mm².

b.

Program Plan Intro

To check the given program for the test value of copper modulus of elasticity of 110000N/mm².

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 2, Problem 6PP

a.

Program Plan Intro

Program plan:

The variable Fof type float is declared and initialized with value 4 to store force in N.

The variable k of type float is declared and initialized with value 1000 given.

The variable l of type float is declared and initialized after converting 3 meters to mm to store the length of rectangular slab.

The variable w of type float is declared and initialized after converting 4 cm to mm to store the width of rectangular slab.

The variable d of type float is declared and initialized to value 2 to store the width of rectangular slab.

The variable e of type float is declared to accept metal's modulus of elasticity.

The variable I of type float is declared to calculate and store the increase in length using the given formula.

Program description:

The main purpose of the program is to calculate the increase in length when a slab of aluminum that’s 3 meters long, 4 cm wide, and 2 mm deep is subjected to a force of 4 Newton. Aluminum’s modulus of elasticity is 68,950 N/mm².

.Manually verifies the result produced by the program when Aluminum’s modulus of elasticity is 68,950 N/mm².

b.

Program Plan Intro

To check the given program for the test value of copper modulus of elasticity of 110000N/mm².

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 2, Problem 6PP

a.

Program Plan Intro

Program plan:

The variable Fof type float is declared and initialized with value 4 to store force in N.

The variable k of type float is declared and initialized with value 1000 given.

The variable l of type float is declared and initialized after converting 3 meters to mm to store the length of rectangular slab.

The variable w of type float is declared and initialized after converting 4 cm to mm to store the width of rectangular slab.

The variable d of type float is declared and initialized to value 2 to store the width of rectangular slab.

The variable e of type float is declared to accept metal's modulus of elasticity.

The variable I of type float is declared to calculate and store the increase in length using the given formula.

Program description:

The main purpose of the program is to calculate the increase in length when a slab of aluminum that’s 3 meters long, 4 cm wide, and 2 mm deep is subjected to a force of 4 Newton. Aluminum’s modulus of elasticity is 68,950 N/mm².

.Manually verifies the result produced by the program when Aluminum’s modulus of elasticity is 68,950 N/mm².

b.

Program Plan Intro

To check the given program for the test value of copper modulus of elasticity of 110000N/mm².

Answer 6

Chapter 2, Problem 6PP

a.

Program Plan Intro

Program plan:

The variable Fof type float is declared and initialized with value 4 to store force in N.

The variable k of type float is declared and initialized with value 1000 given.

The variable l of type float is declared and initialized after converting 3 meters to mm to store the length of rectangular slab.

The variable w of type float is declared and initialized after converting 4 cm to mm to store the width of rectangular slab.

The variable d of type float is declared and initialized to value 2 to store the width of rectangular slab.

The variable e of type float is declared to accept metal's modulus of elasticity.

The variable I of type float is declared to calculate and store the increase in length using the given formula.

Program description:

The main purpose of the program is to calculate the increase in length when a slab of aluminum that’s 3 meters long, 4 cm wide, and 2 mm deep is subjected to a force of 4 Newton. Aluminum’s modulus of elasticity is 68,950 N/mm².

.Manually verifies the result produced by the program when Aluminum’s modulus of elasticity is 68,950 N/mm².

Answer 7

Chapter 2, Problem 6PP

a.

Program Plan Intro

Program plan:

The variable Fof type float is declared and initialized with value 4 to store force in N.

The variable k of type float is declared and initialized with value 1000 given.

The variable l of type float is declared and initialized after converting 3 meters to mm to store the length of rectangular slab.

The variable w of type float is declared and initialized after converting 4 cm to mm to store the width of rectangular slab.

The variable d of type float is declared and initialized to value 2 to store the width of rectangular slab.

The variable e of type float is declared to accept metal's modulus of elasticity.

The variable I of type float is declared to calculate and store the increase in length using the given formula.

Program description:

The main purpose of the program is to calculate the increase in length when a slab of aluminum that’s 3 meters long, 4 cm wide, and 2 mm deep is subjected to a force of 4 Newton. Aluminum’s modulus of elasticity is 68,950 N/mm².

.Manually verifies the result produced by the program when Aluminum’s modulus of elasticity is 68,950 N/mm².

Answer 8

b.

Program Plan Intro

To check the given program for the test value of copper modulus of elasticity of 110000N/mm².

Answer 9

b.

Program Plan Intro

To check the given program for the test value of copper modulus of elasticity of 110000N/mm².

Answer 10

Expert Solution & Answer

Answer 11

Expert Solution & Answer

Answer 12

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Answer 13

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Concept explainers

To check the given program for the test value of copper modulus of elasticity of 110000N/mm².

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Chapter 2 Solutions

Concept explainers

To check the given program for the test value of copper modulus of elasticity of 110000N/mm2.

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Chapter 2 Solutions

To check the given program for the test value of copper modulus of elasticity of 110000N/mm².