Chapter 2, Problem 4STP

To determine

To Choose: The correct option.

Answer to Problem 4STP

B. $24\text{m/s east}$

Explanation of Solution

Given:

The displacement of the train is 192m east in a time periodof $8.0\text{ s}$ .

Formula used:

The average velocity of a particle is given by

  $\overline{v}=\frac{\Delta d}{\Delta t}=\frac{d_{final}-d_{initial}}{t_{final}-t_{initial}}$

Calculation:

Using the above formula of average velocity, the average velocity of the train will be

  $\begin{array}{c}\overline{v}=\frac{\Delta d}{\Delta t}\\ =\frac{192\text{m}}{8.0\text{s}}\\ =24\text{m/s}\end{array}$

Towards East.

Conclusion:

Thus, the average velocity of the train is $24\text{m/s}$ east.