Chapter 2, Problem 43Q

To determine

The time when the second star will pass through zenith, if one star has $\text{R}\text{.A}\text{.}={\text{8}}^{\text{h}}{\text{0}}^{\text{m}}{\text{0}}^{\text{s}}$, $\text{Decl}\text{.}=\text{0}{°}^{}\text{0}{\prime }^{}\text{0}{″}^{}$, and the other star has $\text{R}\text{.A}\text{.}={11}^{\text{h}}{\text{20}}^{\text{m}}{\text{0}}^{\text{s}}$, $\text{Decl}\text{.}=\text{0}{°}^{}\text{0}{\prime }^{}\text{0}{″}^{}$. Given that 24 hours of right ascension is equal to $360°$ of the celestial equator. Given that the first star crosses the zenith at 12:30 A.M. local time.