Concept explainers
The higher regard by professional astronomers between hypothesis and theory as an approximation of truth.
Answer to Problem 1CC
Solution:
A theory has a higher regard than hypothesis by professional astronomers.
Explanation of Solution
Introduction:
Science makes use of creativity and is in alignment with what is observed in nature. Scientific methods have an approach towards creating hypotheses, observations, theories and experiments to prove their validity. Scientists further work out the implications, thus, evolving the way nature is studied.
Explanation:
A hypothesis is a collection of ideas that seems to explain what is observed. Scientists tend to be most imaginative, creative or intuitive at this level. The implications of a hypothesis is to work out with logic and to make predictions that can be tested. A hypothesis becomes valid and more recognized only after testing the authenticity of results and observations with reality.
A good theory in science is one which explains reality in accordance with new observations and results. So, when related hypothesis are merged together to form a self-consistent description of nature, it is known as a theory. Scientific theories is capable of making predication that can be further used by the other scientists to test. Predictions are verified through observations and if it is found that they do not match with the observations, the theory demands to be replaced or modified. Hence, an idea which cannot be tested by observations or experiments does not qualify as a theory.
Conclusion:
Therefore, it can be concluded that theory has a higher regard for approximation of truth by professional astronomers as it is a collection of related hypothesis which has already been tested.
Want to see more full solutions like this?
Chapter 1 Solutions
EBK LOOSE-LEAF VERSION OF UNIVERSE
- 3.37(a) Five free electrons exist in a three-dimensional infinite potential well with all three widths equal to \( a = 12 \, \text{Å} \). Determine the Fermi energy level at \( T = 0 \, \text{K} \). (b) Repeat part (a) for 13 electrons. Book: Semiconductor Physics and Devices 4th ed, NeamanChapter-3Please expert answer only. don't give gpt-generated answers, & please clear the concept of quantum states for determining nx, ny, nz to determine E, as I don't have much idea about that topic.arrow_forwardNo chatgpt pls will upvotearrow_forwardUse the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: Incident ray at A Note: This diagram is not to scale. a Air (n = 1.00) Water (n = 1.34) 1) Determine the angle of refraction of the ray of light in the water. Barrow_forward
- Hi can u please solvearrow_forward6. Bending a lens in OpticStudio or OSLO. In either package, create a BK7 singlet lens of 10 mm semi-diameter and with 10 mm thickness. Set the wavelength to the (default) 0.55 microns and a single on-axis field point at infinite object distance. Set the image distance to 200 mm. Make the first surface the stop insure that the lens is fully filled (that is, that the entrance beam has a radius of 10 mm). Use the lens-maker's equation to calculate initial glass curvatures assuming you want a symmetric, bi-convex lens with an effective focal length of 200 mm. Get this working and examine the RMS spot size using the "Text" tab of the Spot Diagram analysis tab (OpticStudio) or the Spd command of the text widnow (OSLO). You should find the lens is far from diffraction limited, with a spot size of more than 100 microns. Now let's optimize this lens. In OpticStudio, create a default merit function optimizing on spot size.Then insert one extra line at the top of the merit function. Assign the…arrow_forwardNo chatgpt pls will upvote Already got wrong chatgpt answer .arrow_forward
- Use the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: A Incident ray at A Note: This diagram is not to scale. Air (n = 1.00) Water (n = 1.34) Barrow_forwardUse the following information to answer the next question. Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of 42°. The ray of light reflects off mirror B and then enters water, as shown below: A Incident ray at A Note: This diagram is not to scale. Air (n = 1.00) Water (n = 1.34) Barrow_forwardGood explanation it sure experts solve it.arrow_forward
- No chatgpt pls will upvote Asaparrow_forwardA satellite has a mass of 100kg and is located at 2.00 x 10^6 m above the surface of the earth. a) What is the potential energy associated with the satellite at this loction? b) What is the magnitude of the gravitational force on the satellite?arrow_forwardNo chatgpt pls will upvotearrow_forward
- Foundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningStars and Galaxies (MindTap Course List)PhysicsISBN:9781337399944Author:Michael A. SeedsPublisher:Cengage Learning
- Stars and GalaxiesPhysicsISBN:9781305120785Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning