(a)
The distance at which a person will have to hold a European 2-euro coin to subtend an angle of
(a)

Answer to Problem 16Q
Solution:
1.49 m
Explanation of Solution
Given data:
A European 2-euro coin has a diameter of 2.6 cm. The angle subtended by the coin is
Formula used:
The small-angle formula is written as,
Here, α is the angle subtended by the object (in arcseconds), d is the distance between the observer and the object and D is the linear size of the object.
Explanation:
The distance at which a person will hold a 2-euro coin to subtend an angle of
Rearrange for d,
Since
Conclusion:
Hence, the coin should be held at 1.49 m if the angle to be subtended is
(b)
The distance at which a person will have to hold a European 2-euro coin to subtend an angle of
(b)

Answer to Problem 16Q
Solution:
89.3815 m
Explanation of Solution
Given data:
A European 2-euro coin has a diameter of 2.6 cm. The angle subtended by the coin is
Formula used:
The small-angle formula is written as,
Here, α is the angle subtended by the object (in arcseconds), d is the distance between the observer and the object and D is the linear size of the object.
Explanation:
The distance at which a person will hold a 2-euro coin to subtend an angle of
Rearrange for d,
Since
Conclusion:
Hence, the coin should be held at 89.4 m in order to subtend an angle of
(c)
The distance at which a person will have to hold a European 2-euro coin to subtend an angle of
(c)

Answer to Problem 16Q
Solution:
5362.9 m
Explanation of Solution
Given data:
A European 2-euro coin that has a diameter of 2.6 cm. The angle subtended by the coin is
Formula used:
The small-angle formula is written as,
Here, α is the angle subtended by the object (in arcseconds), d is the distance between the observer and the object and D is the linear size of the object.
Explanation:
The distance at which a person will hold a 2-euro coin to subtend an angle of
Rearrange for d,
Substitute 2.6 cm for D and
Conclusion:
Hence, the coin should be held at 5362.9 m in order to subtend an angle of
Want to see more full solutions like this?
Chapter 1 Solutions
EBK LOOSE-LEAF VERSION OF UNIVERSE
- Sketch the harmonic.arrow_forwardFor number 11 please sketch the harmonic on graphing paper.arrow_forward# E 94 20 13. Time a) What is the frequency of the above wave? b) What is the period? c) Highlight the second cycle d) Sketch the sine wave of the second harmonic of this wave % 7 & 5 6 7 8 * ∞ Y U 9 0 0 P 150arrow_forward
- Show work using graphing paperarrow_forwardCan someone help me answer this physics 2 questions. Thank you.arrow_forwardFour capacitors are connected as shown in the figure below. (Let C = 12.0 μF.) a C 3.00 με Hh. 6.00 με 20.0 με HE (a) Find the equivalent capacitance between points a and b. 5.92 HF (b) Calculate the charge on each capacitor, taking AV ab = 16.0 V. 20.0 uF capacitor 94.7 6.00 uF capacitor 67.6 32.14 3.00 µF capacitor capacitor C ☑ με με The 3 µF and 12.0 uF capacitors are in series and that combination is in parallel with the 6 μF capacitor. What quantity is the same for capacitors in parallel? μC 32.14 ☑ You are correct that the charge on this capacitor will be the same as the charge on the 3 μF capacitor. μCarrow_forward
- In the pivot assignment, we observed waves moving on a string stretched by hanging weights. We noticed that certain frequencies produced standing waves. One such situation is shown below: 0 ст Direct Measurement ©2015 Peter Bohacek I. 20 0 cm 10 20 30 40 50 60 70 80 90 100 Which Harmonic is this? Do NOT include units! What is the wavelength of this wave in cm with only no decimal places? If the speed of this wave is 2500 cm/s, what is the frequency of this harmonic (in Hz, with NO decimal places)?arrow_forwardFour capacitors are connected as shown in the figure below. (Let C = 12.0 µF.) A circuit consists of four capacitors. It begins at point a before the wire splits in two directions. On the upper split, there is a capacitor C followed by a 3.00 µF capacitor. On the lower split, there is a 6.00 µF capacitor. The two splits reconnect and are followed by a 20.0 µF capacitor, which is then followed by point b. (a) Find the equivalent capacitance between points a and b. µF(b) Calculate the charge on each capacitor, taking ΔVab = 16.0 V. 20.0 µF capacitor µC 6.00 µF capacitor µC 3.00 µF capacitor µC capacitor C µCarrow_forwardTwo conductors having net charges of +14.0 µC and -14.0 µC have a potential difference of 14.0 V between them. (a) Determine the capacitance of the system. F (b) What is the potential difference between the two conductors if the charges on each are increased to +196.0 µC and -196.0 µC? Varrow_forward
- Please see the attached image and answer the set of questions with proof.arrow_forwardHow, Please type the whole transcript correctly using comma and periods as needed. I have uploaded the picture of a video on YouTube. Thanks,arrow_forwardA spectra is a graph that has amplitude on the Y-axis and frequency on the X-axis. A harmonic spectra simply draws a vertical line at each frequency that a harmonic would be produced. The height of the line indicates the amplitude at which that harmonic would be produced. If the Fo of a sound is 125 Hz, please sketch a spectra (amplitude on the Y axis, frequency on the X axis) of the harmonic series up to the 4th harmonic. Include actual values on Y and X axis.arrow_forward
- Horizons: Exploring the Universe (MindTap Course ...PhysicsISBN:9781305960961Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningAn Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage LearningFoundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning
- Stars and Galaxies (MindTap Course List)PhysicsISBN:9781337399944Author:Michael A. SeedsPublisher:Cengage Learning





