Explanation Write the expression for the equation of motion having constant acceleration. v 2 = v 0 2 − 2 a ( x − x 0 ) (I) Here, v is the final speed, v 0 is the initial speed, a is the acceleration, x − x 0 is the change in distance. Since the airplane comes to stop, the final velocity will be zero. So that equation (I) for a , a = − v 0 2 2 ( x − x 0 ) (II) Conclusion: Substitute 275 km / h for v 0 , 1.2 km for ( x − x 0 ) , in equation (II) to find a

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ISBN: 9780134988559

Author: Wolfson, Richard

Publisher: Pearson Education,

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Chapter 2, Problem 42E

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The magnitude of the acceleration of the Jetliner as it slows to a stop.

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Chapter 2, Problem 41E

Chapter 2, Problem 43E

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