Chapter 2, Problem 42A

Two vertical chains are used to hold up a 1000-N log. One chain has a tension of 400 N. Find the tension in the other chain.

To determine

Tension in the other chain.

Answer to Problem 42A

Tension in the other chain is $T=600\text{N}$

Explanation of Solution

Given:

Weight of log, $W=1000\text{N}$

Tension in one chain is 400 N.

Formula Used:

For mechanical equilibrium, summation of all forces is zero, that is

  $\sum F=0$

Calculation:

The figure is,

  

Since, the log is in mechanical equilibrium so, $\sum F=0$ or

Upward force = Downward force

  $\begin{array}{l}\Rightarrow 400+T=W\\ \Rightarrow 400+T=1000\\ \Rightarrow T=1000-400=600\text{N}\end{array}$

Conclusion:

Therefore, the tension in the other chain is $T=600\text{N}$